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If the roots of (x^2-26x+165=0) are (\alpha,\beta), what is (\frac{\alpha}{\beta}+\frac{\beta}{\alpha})?यदि (x^2-26x+165=0) के मूल (\alpha,\beta) हैं, तो (\frac{\alpha}{\beta}+\frac{\beta}{\alpha}) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \frac{346}{165}) / (\frac{346}{165})( \frac{346}{165}) / (\frac{346}{165})
(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}), where (\alpha+\beta=26) and (\alpha\beta=165), so the value is (\frac{676-330}{165}=\frac{346}{165}). In exams, convert expressions into sum and product.(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}), जहां (\alpha+\beta=26) और (\alpha\beta=165), इसलिए मान (\frac{676-330}{165}=\frac{346}{165}) है। परीक्षा में अभिव्यक्ति को योग और गुणनफल में बदलें।
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