If the roots of (x^2-18x+77=0) are (\alpha,\beta), what is (\frac{\alpha}{\beta}+\frac{\beta}{\alpha})?
Answer and explanation
Correct answer: ( \frac{170}{77}) / (\frac{170}{77})
(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}), where (\alpha+\beta=18) and (\alpha\beta=77), so the value is (\frac{324-154}{77}=\frac{170}{77}). In exams, convert expressions into sum and product.
Frequently asked questions
What is the correct answer to this question?
( \frac{170}{77}) / (\frac{170}{77})
Why is this the correct answer?
(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}), where (\alpha+\beta=18) and (\alpha\beta=77), so the value is (\frac{324-154}{77}=\frac{170}{77}). In exams, convert expressions into sum and product.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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