With rational coefficients, the conjugate of the irrational part is also a zero. Hence \(\frac{3-\sqrt{5}}{2}\) is the other zero.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{3-\sqrt{5}}{2}\). With rational coefficients, the conjugate of the irrational part is also a zero. Hence \(\frac{3-\sqrt{5}}{2}\) is the other zero.
Step 3
Exam Tip
परिमेय गुणांकों में अपरिमेय भाग का संयुग्मी भी शून्यक होता है। इसलिए \(\frac{3-\sqrt{5}}{2}\) दूसरा शून्यक है।
The product is (\frac{\(1+\sqrt{3}\)\(1-\sqrt{3}\)}{4}=\frac{1-3}{4}=-\frac{1}{2}). Use \(a^2-b\) for conjugate products.
Step 2
Why this answer is correct
The correct answer is A. \(-\frac{1}{2}\). The product is (\frac{\(1+\sqrt{3}\)\(1-\sqrt{3}\)}{4}=\frac{1-3}{4}=-\frac{1}{2}). Use \(a^2-b\) for conjugate products.
Step 3
Exam Tip
गुणनफल (\frac{\(1+\sqrt{3}\)\(1-\sqrt{3}\)}{4}=\frac{1-3}{4}=-\frac{1}{2}) है। संयुग्मी गुणनफल में \(a^2-b\) प्रयोग करें।
A. \(\frac{1}{2}\) शून्यक है/\(\frac{1}{2}\) is a zero
Step 1
Concept
A zero can be a fraction and touching is enough. The key point is (p\left\(\frac{1}{2}\right\)=0).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\) शून्यक है / \(\frac{1}{2}\) is a zero. A zero can be a fraction and touching is enough. The key point is (p\left\(\frac{1}{2}\right\)=0).
Step 3
Exam Tip
शून्यक भिन्न भी हो सकता है और छूना पर्याप्त है। जरूरी बात (p\left\(\frac{1}{2}\right\)=0) है।
