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If \(x=2\) is a zero of \(p(x)=3x^2+bx-10\), what is the value of \(b\)?यदि \(x=2\), \(p(x)=3x^2+bx-10\) का शून्य (zero) है, तो \(b\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-1\)\(-1\)
Since \(x=2\) is a zero, \(p(2)=0\). Substitute: \(p(2)=3(2)^2+b(2)-10=3\cdot4+2b-10=12+2b-10=2+2b\). Set \(2+2b=0\Rightarrow 2b=-2\Rightarrow b=-1\).चूँकि \(x=2\) शून्य है, इसलिए \(p(2)=0\). प्रतिस्थापित कीजिए: \(p(2)=3(2)^2+b(2)-10=3\cdot4+2b-10=12+2b-10=2+2b\)। अब \(2+2b=0\Rightarrow 2b=-2\Rightarrow b=-1\).
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