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If \(p(x)=ax+b\), where \(a\ne 0\), what is the zero of this linear polynomial?यदि \(p(x)=ax+b\), जहाँ \(a\ne 0\), तो इस रैखिक बहुपद का शून्यक क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-\frac{b}{a}\)\(-\frac{b}{a}\)
The zero is the value of \(x\) for which \(p(x)=0\). Solving \(ax+b=0\) gives \(ax=-b\), and since \(a\ne 0\), \(x=-\frac{b}{a}\).शून्यक वह मान है जिसके लिए \(p(x)=0\) होता है। \(ax+b=0\) हल करने पर \(ax=-b\) मिलता है और, क्योंकि \(a\ne 0\), \(x=-\frac{b}{a}\) होता है।
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