100 results found for "linear zero value" in Class 10.
कौन सा बहुपद (x=0) को शून्य बनाता है लेकिन शून्य बहुपद नहीं है?
Which polynomial makes (x=0) a zero but is not the zero polynomial?
#zero at zero
#constant term
#polynomial
A \(x^2+9\)
B \(4x^3-7x\)
C (5)
D \(x^4+1\)
Explanation opens after your attempt
Correct Answer
B. \(4x^3-7x\)
Step 1
Concept
Substituting (x=0) in \(4x^3-7x\) gives (0), and it is not the zero polynomial. For (x=0), the constant term must be (0).
Step 2
Why this answer is correct
The correct answer is B. \(4x^3-7x\). Substituting (x=0) in \(4x^3-7x\) gives (0), and it is not the zero polynomial. For (x=0), the constant term must be (0).
Step 3
Exam Tip
\(4x^3-7x\) में (x=0) रखने पर (0) मिलता है और यह शून्य बहुपद नहीं है। (x=0) के लिए अचर पद (0) होना चाहिए।
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यदि (p(-3)=0), तो बहुपद का कौन-सा शून्यक है?
If (p(-3)=0), which value is a zero of the polynomial?
#zero-definition
#function-value
#negative-zero
#easy
A (-3)
B (3)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
The (x)-value for which (p(x)=0) is a zero. Hence (-3) is a zero of the polynomial.
Step 2
Why this answer is correct
The correct answer is A. (-3). The (x)-value for which (p(x)=0) is a zero. Hence (-3) is a zero of the polynomial.
Step 3
Exam Tip
जिस (x)-मान पर (p(x)=0) हो वही शून्यक होता है। इसलिए (-3) बहुपद का शून्यक है।
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किसी बहुपद के ग्राफ पर शून्यक पहचानने के लिए कौन-सा मान शून्य होना चाहिए?
Which value must be zero to identify a zero on the graph of a polynomial?
#polynomials
#zeroes
#graph
#value-test
A बहुपद का मान / Value of the polynomial
B चर का गुणांक / Coefficient of the variable
C घात का मान / Value of the degree
D स्थिर पद / Constant term
Explanation opens after your attempt
Correct Answer
A. बहुपद का मान / Value of the polynomial
Step 1
Concept
At a zero, the polynomial value is (0). While reading a graph, look for points where (y=0).
Step 2
Why this answer is correct
The correct answer is A. बहुपद का मान / Value of the polynomial. At a zero, the polynomial value is (0). While reading a graph, look for points where (y=0).
Step 3
Exam Tip
शून्यक पर बहुपद का मान (0) होता है। ग्राफ पढ़ते समय (y=0) वाले बिंदु देखें।
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यदि (p(x)=2x-2 +mx+18) का एक शून्यक (3) है, तो दूसरा शून्यक क्या है?
If one zero of (p(x)=2x-2 +mx+18) is (3), what is the other zero?
#one-zero-given
#product-zeroes
#quadratic
A (3)
B -(3)
C (6)
D -(6)
Explanation opens after your attempt
Step 1
Concept
The product is \(\frac{18}{2}=9\). Since one zero is (3), the other is (3).
Step 2
Why this answer is correct
The correct answer is A. (3). The product is \(\frac{18}{2}=9\). Since one zero is (3), the other is (3).
Step 3
Exam Tip
गुणनफल \(\frac{18}{2}=9\) है। एक शून्यक (3) है, इसलिए दूसरा (3) होगा।
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यदि (p(x)=x-2 +3x-18) का एक शून्यक (3) है, तो दूसरा शून्यक क्या है?
If one zero of (p(x)=x-2 +3x-18) is (3), what is the other zero?
#one-zero-given
#product-zeroes
#quadratic
A -(6)
B (6)
C -(3)
D (9)
Explanation opens after your attempt
Step 1
Concept
The product of zeroes is (-18). Since one zero is (3), the other is \(-18\div3=-6\).
Step 2
Why this answer is correct
The correct answer is A. -(6). The product of zeroes is (-18). Since one zero is (3), the other is \(-18\div3=-6\).
Step 3
Exam Tip
शून्यकों का गुणनफल (-18) है। एक शून्यक (3) है, इसलिए दूसरा \(-18\div3=-6\) है।
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यदि (p(x)=x-2 -10x+r) का एक शून्यक (4) है, तो दूसरा शून्यक क्या है?
If one zero of (p(x)=x-2 -10x+r) is (4), what is the other zero?
#one-zero-given
#sum-zeroes
#quadratic
A (6)
B (4)
C (10)
D -(6)
Explanation opens after your attempt
Step 1
Concept
The sum of zeroes is (10). Since one zero is (4), the other is (10-4=6).
Step 2
Why this answer is correct
The correct answer is A. (6). The sum of zeroes is (10). Since one zero is (4), the other is (10-4=6).
Step 3
Exam Tip
शून्यकों का योग (10) है। एक शून्यक (4) है, इसलिए दूसरा (10-4=6) है।
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यदि (p(x)=x-2 -2x-2) का एक शून्यक \(1+\sqrt{3}\) है, तो दूसरा शून्यक क्या है?
If one zero of (p(x)=x-2 -2x-2) is \(1+\sqrt{3}\), what is the other zero?
#other-zero
#sum-of-zeroes
#conjugate
A \(1-\sqrt{3}\)
B \(-1+\sqrt{3}\)
C \(1+\sqrt{3}\)
D \(-1-\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(1-\sqrt{3}\)
Step 1
Concept
The sum of zeroes is (2), so the other zero is (2-\(1+\sqrt{3}\)=1-\sqrt{3}). With rational coefficients, the conjugate also appears.
Step 2
Why this answer is correct
The correct answer is A. \(1-\sqrt{3}\). The sum of zeroes is (2), so the other zero is (2-\(1+\sqrt{3}\)=1-\sqrt{3}). With rational coefficients, the conjugate also appears.
Step 3
Exam Tip
शून्यकों का योग (2) है, इसलिए दूसरा शून्यक (2-\(1+\sqrt{3}\)=1-\sqrt{3}) है। परिमेय गुणांकों में संयुग्मी भी मिलता है।
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यदि (p(x)=x-2 -13x+k) का एक शून्यक (6) है, तो दूसरा शून्यक और (x)-अक्ष कटान क्या होंगे?
If (p(x)=x-2 -13x+k) has one zero (6), what will be the other zero and the (x)-axis intersections?
#missing zero
#quadratic
#intercepts
A दूसरा (7), कटान ((6,0)), ((7,0)) / Other (7), intersections ((6,0)), ((7,0))
B दूसरा (-7), कटान ((6,0)), ((-7,0)) / Other (-7), intersections ((6,0)), ((-7,0))
C दूसरा (13), कटान ((6,0)), ((13,0)) / Other (13), intersections ((6,0)), ((13,0))
D दूसरा (0), कटान ((6,0)), ((0,0)) / Other (0), intersections ((6,0)), ((0,0))
Explanation opens after your attempt
Correct Answer
A. दूसरा (7), कटान ((6,0)), ((7,0)) / Other (7), intersections ((6,0)), ((7,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (13), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (7), कटान ((6,0)), ((7,0)) / Other (7), intersections ((6,0)), ((7,0)). In the quadratic, the sum of zeroes is (13), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (13) है, इसलिए दूसरा शून्यक (7) है। टिप: शून्यक को ((x,0)) में बदलें।
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यदि परवलय का सममिति अक्ष (x=5) है और एक शून्यक (-1) है, तो दूसरा शून्यक क्या होगा?
If the axis of symmetry of a parabola is (x=5) and one zero is (-1), what will be the other zero?
#axis symmetry
#missing zero
#parabola
A (11)
B (9)
C (6)
D (-11)
Explanation opens after your attempt
Step 1
Concept
The average of the two zeroes is (5), so the other zero is (11). Tip: the axis of symmetry passes through the midpoint of zeroes.
Step 2
Why this answer is correct
The correct answer is A. (11). The average of the two zeroes is (5), so the other zero is (11). Tip: the axis of symmetry passes through the midpoint of zeroes.
Step 3
Exam Tip
दो शून्यकों का औसत (5) है इसलिए दूसरा शून्यक (11) होगा। टिप: सममिति अक्ष शून्यकों के मध्य से गुजरता है।
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यदि (p(x)=x-2 -11x+k) का एक शून्यक (4) है, तो दूसरा शून्यक और (x)-अक्ष कटान क्या होंगे?
If (p(x)=x-2 -11x+k) has one zero (4), what will be the other zero and the (x)-axis intersections?
#missing zero
#quadratic
#intercepts
A दूसरा (7), कटान ((4,0)), ((7,0)) / Other (7), intersections ((4,0)), ((7,0))
B दूसरा (-7), कटान ((4,0)), ((-7,0)) / Other (-7), intersections ((4,0)), ((-7,0))
C दूसरा (11), कटान ((4,0)), ((11,0)) / Other (11), intersections ((4,0)), ((11,0))
D दूसरा (0), कटान ((4,0)), ((0,0)) / Other (0), intersections ((4,0)), ((0,0))
Explanation opens after your attempt
Correct Answer
A. दूसरा (7), कटान ((4,0)), ((7,0)) / Other (7), intersections ((4,0)), ((7,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (11), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (7), कटान ((4,0)), ((7,0)) / Other (7), intersections ((4,0)), ((7,0)). In the quadratic, the sum of zeroes is (11), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (11) है, इसलिए दूसरा शून्यक (7) है। टिप: शून्यक को ((x,0)) में बदलें।
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यदि परवलय का सममिति अक्ष (x=-2) है और एक शून्यक (5) है, तो दूसरा शून्यक क्या होगा?
If the axis of symmetry of a parabola is (x=-2) and one zero is (5), what will be the other zero?
#axis symmetry
#missing zero
#parabola
A (-9)
B (-7)
C (9)
D (7)
Explanation opens after your attempt
Step 1
Concept
The average of the two zeroes is (-2), so the other zero is (-9). Tip: connect the axis of symmetry with the midpoint of zeroes.
Step 2
Why this answer is correct
The correct answer is A. (-9). The average of the two zeroes is (-2), so the other zero is (-9). Tip: connect the axis of symmetry with the midpoint of zeroes.
Step 3
Exam Tip
दो शून्यकों का औसत (-2) है, इसलिए दूसरा शून्यक (-9) होगा। टिप: सममिति अक्ष को शून्यकों के मध्य से जोड़ें।
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यदि (p(x)=x-2 -9x+k) का एक शून्यक (4) है तो दूसरा शून्यक और कटान बिंदु क्या होंगे?
If (p(x)=x-2 -9x+k) has one zero (4), what will be the other zero and intersection points?
#missing zero
#quadratic
#intercepts
A दूसरा (5), कटान ((4,0)), ((5,0)) / Other (5), intersections ((4,0)), ((5,0))
B दूसरा (-5), कटान ((4,0)), ((-5,0)) / Other (-5), intersections ((4,0)), ((-5,0))
C दूसरा (9), कटान ((4,0)), ((9,0)) / Other (9), intersections ((4,0)), ((9,0))
D दूसरा (0), कटान ((4,0)), ((0,0)) / Other (0), intersections ((4,0)), ((0,0))
Explanation opens after your attempt
Correct Answer
A. दूसरा (5), कटान ((4,0)), ((5,0)) / Other (5), intersections ((4,0)), ((5,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (9), so the other zero is (5). Tip: quickly convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (5), कटान ((4,0)), ((5,0)) / Other (5), intersections ((4,0)), ((5,0)). In the quadratic, the sum of zeroes is (9), so the other zero is (5). Tip: quickly convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (9) है इसलिए दूसरा शून्यक (5) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
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किसी परवलय का एक शून्यक (11) है और सममिति अक्ष (x=3) है। दूसरा शून्यक क्या होगा?
A parabola has one zero (11) and axis of symmetry (x=3). What will be the other zero?
#missing zero
#axis of symmetry
#parabola
A (-5)
B (5)
C (-8)
D (8)
Explanation opens after your attempt
Step 1
Concept
The average of the two zeroes is (3), so the other zero is (-5). Tip: set \(\frac{a+b}{2}\) equal to the axis of symmetry.
Step 2
Why this answer is correct
The correct answer is A. (-5). The average of the two zeroes is (3), so the other zero is (-5). Tip: set \(\frac{a+b}{2}\) equal to the axis of symmetry.
Step 3
Exam Tip
दो शून्यकों का औसत (3) है इसलिए दूसरा शून्यक (-5) होगा। टिप: \(\frac{a+b}{2}\) को सममिति अक्ष के बराबर रखें।
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किसी परवलय का सममिति अक्ष (x=4) है और एक शून्यक (-2) है। दूसरा शून्यक क्या होगा?
The axis of symmetry of a parabola is (x=4) and one zero is (-2). What will be the other zero?
#axis symmetry
#missing zero
#parabola
A (10)
B (6)
C (8)
D (-10)
Explanation opens after your attempt
Step 1
Concept
The average of the two zeroes is (4), so the other zero is (10). Tip: connect the axis of symmetry with the midpoint of zeroes.
Step 2
Why this answer is correct
The correct answer is A. (10). The average of the two zeroes is (4), so the other zero is (10). Tip: connect the axis of symmetry with the midpoint of zeroes.
Step 3
Exam Tip
दोनों शून्यकों का औसत (4) है इसलिए दूसरा शून्यक (10) होगा। टिप: सममिति अक्ष को शून्यकों के मध्य मान से जोड़ें।
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यदि (p(x)=x-2 -7x+k) का एक शून्यक (3) है, तो दूसरा शून्यक और कटान बिंदु क्या होंगे?
If (p(x)=x-2 -7x+k) has one zero (3), what will be the other zero and intersection points?
#missing zero
#quadratic
#intercepts
A दूसरा (4), कटान ((3,0)), ((4,0)) / Other (4), intersections ((3,0)), ((4,0))
B दूसरा (-4), कटान ((3,0)), ((-4,0)) / Other (-4), intersections ((3,0)), ((-4,0))
C दूसरा (7), कटान ((3,0)), ((7,0)) / Other (7), intersections ((3,0)), ((7,0))
D दूसरा (0), कटान ((3,0)), ((0,0)) / Other (0), intersections ((3,0)), ((0,0))
Explanation opens after your attempt
Correct Answer
A. दूसरा (4), कटान ((3,0)), ((4,0)) / Other (4), intersections ((3,0)), ((4,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (7), so the other zero is (4). Tip: quickly convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (4), कटान ((3,0)), ((4,0)) / Other (4), intersections ((3,0)), ((4,0)). In the quadratic, the sum of zeroes is (7), so the other zero is (4). Tip: quickly convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (7) है, इसलिए दूसरा शून्यक (4) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
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किसी परवलय का एक शून्यक (9) है और सममिति अक्ष (x=2) है। दूसरा शून्यक क्या होगा?
A parabola has one zero (9) and axis of symmetry (x=2). What is the other zero?
#missing zero
#axis of symmetry
#parabola
A (-5)
B (5)
C (-7)
D (7)
Explanation opens after your attempt
Step 1
Concept
The average of the two zeroes is (2), so the other zero is (-5). Tip: set \( \frac{a+b}{2} \) equal to the axis of symmetry.
Step 2
Why this answer is correct
The correct answer is A. (-5). The average of the two zeroes is (2), so the other zero is (-5). Tip: set \( \frac{a+b}{2} \) equal to the axis of symmetry.
Step 3
Exam Tip
दो शून्यकों का औसत (2) है, इसलिए दूसरा शून्यक (-5) होगा। टिप: \( \frac{a+b}{2} \) को सममिति अक्ष के बराबर रखें।
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किसी परवलय का सममिति अक्ष (x=1) है और एक शून्यक (-5) है। दूसरा शून्यक क्या होगा?
The axis of symmetry of a parabola is (x=1) and one zero is (-5). What will be the other zero?
#axis symmetry
#missing zero
#parabola
A (5)
B (6)
C (7)
D (-7)
Explanation opens after your attempt
Step 1
Concept
The average of the two zeroes is (1), so the other zero is (7). Tip: the axis of symmetry passes through the midpoint of zeroes.
Step 2
Why this answer is correct
The correct answer is C. (7). The average of the two zeroes is (1), so the other zero is (7). Tip: the axis of symmetry passes through the midpoint of zeroes.
Step 3
Exam Tip
दो शून्यकों का औसत (1) होगा इसलिए दूसरा शून्यक (7) है। टिप: सममिति अक्ष शून्यकों के मध्य से गुजरता है।
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यदि (p(x)=x-2 -5x+k) का एक शून्यक (2) है, तो दूसरा शून्यक और (x)-अक्ष कटान क्या होगा?
If (p(x)=x-2 -5x+k) has one zero (2), what will be the other zero and the (x)-axis intersections?
#quadratic
#missing zero
#intercepts
A दूसरा (3), कटान ((2,0)), ((3,0)) / Other (3), intersections ((2,0)), ((3,0))
B दूसरा (-3), कटान ((2,0)), ((-3,0)) / Other (-3), intersections ((2,0)), ((-3,0))
C दूसरा (5), कटान ((2,0)), ((5,0)) / Other (5), intersections ((2,0)), ((5,0))
D दूसरा (0), कटान ((2,0)), ((0,0)) / Other (0), intersections ((2,0)), ((0,0))
Explanation opens after your attempt
Correct Answer
A. दूसरा (3), कटान ((2,0)), ((3,0)) / Other (3), intersections ((2,0)), ((3,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (5), so the other zero is (3). Tip: immediately convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (3), कटान ((2,0)), ((3,0)) / Other (3), intersections ((2,0)), ((3,0)). In the quadratic, the sum of zeroes is (5), so the other zero is (3). Tip: immediately convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (5) है, इसलिए दूसरा शून्यक (3) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
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किसी परवलय का एक शून्यक (4) है और सममिति अक्ष (x=-1) है। दूसरा शून्यक क्या होगा?
A parabola has one zero (4) and axis of symmetry (x=-1). What will be the other zero?
#axis of symmetry
#missing zero
#parabola
A (-6)
B (-4)
C (2)
D (6)
Explanation opens after your attempt
Step 1
Concept
The average of the two zeroes is (-1), so the other zero is (-6). Tip: set the average equal to the axis of symmetry.
Step 2
Why this answer is correct
The correct answer is A. (-6). The average of the two zeroes is (-1), so the other zero is (-6). Tip: set the average equal to the axis of symmetry.
Step 3
Exam Tip
दो शून्यकों का औसत (-1) है, इसलिए दूसरा शून्यक (-6) होगा। टिप: औसत को सममिति अक्ष के बराबर रखें।
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बहुपद (p(x)=2x-6) का शून्यक आलेख में किस (x)-मान पर दिखेगा?
At which (x)-value will the zero of (p(x)=2x-6) appear on the graph?
#linear zero value
A (3)
B (-3)
C (6)
D (2)
Explanation opens after your attempt
Step 1
Concept
Solving (2x-6=0) gives (x=3). Tip: first put (p(x)=0).
Step 2
Why this answer is correct
The correct answer is A. (3). Solving (2x-6=0) gives (x=3). Tip: first put (p(x)=0).
Step 3
Exam Tip
(2x-6=0) से (x=3) होता है। टिप: पहले (p(x)=0) रखें।
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वह एकघात बहुपद कौन सा है जिसका शून्यक \(2\sqrt{3}\) है?
Which linear polynomial has zero \(2\sqrt{3}\)?
#linear-polynomial
#irrational-zero
#concept
A \(x-2\sqrt{3}\)
B \(x+2\sqrt{3}\)
C \(2x-\sqrt{3}\)
D \(x^2-12\)
Explanation opens after your attempt
Correct Answer
A. \(x-2\sqrt{3}\)
Step 1
Concept
A linear polynomial \(x-\alpha\) has zero \(\alpha\). Here \(\alpha=2\sqrt{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(x-2\sqrt{3}\). A linear polynomial \(x-\alpha\) has zero \(\alpha\). Here \(\alpha=2\sqrt{3}\).
Step 3
Exam Tip
एकघात बहुपद \(x-\alpha\) का शून्यक \(\alpha\) होता है। यहाँ \(\alpha=2\sqrt{3}\) है।
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किसी रैखिक बहुपद का आलेख (y=4x+12) है। इसका शून्यक क्या है?
The graph of a linear polynomial is (y=4x+12). What is its zero?
#linear graph zero
A (-3)
B (3)
C (12)
D (-12)
Explanation opens after your attempt
Step 1
Concept
Solving (4x+12=0) gives (x=-3). Tip: set (y=0) to find the zero.
Step 2
Why this answer is correct
The correct answer is A. (-3). Solving (4x+12=0) gives (x=-3). Tip: set (y=0) to find the zero.
Step 3
Exam Tip
(4x+12=0) से (x=-3) मिलता है। टिप: शून्यक के लिए (y=0) रखें।
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किस स्थिति में रैखिक बहुपद का कोई वास्तविक शून्यक नहीं होगा?
In which situation will a linear polynomial have no real zero?
#linear graph
#no zero
#constant
A जब उसका ग्राफ (x)-अक्ष को काटे / When its graph cuts the (x)-axis
B जब उसका ग्राफ (x)-अक्ष के समांतर और ऊपर हो / When its graph is parallel to and above the (x)-axis
C जब उसका ग्राफ मूल बिंदु से गुजरे / When its graph passes through the origin
D जब उसका ग्राफ (y)-अक्ष को काटे / When its graph cuts the (y)-axis
Explanation opens after your attempt
Correct Answer
B. जब उसका ग्राफ (x)-अक्ष के समांतर और ऊपर हो / When its graph is parallel to and above the (x)-axis
Step 1
Concept
A line parallel to and above the (x)-axis does not meet the (x)-axis. Tip: such a graph behaves like a non-zero constant polynomial.
Step 2
Why this answer is correct
The correct answer is B. जब उसका ग्राफ (x)-अक्ष के समांतर और ऊपर हो / When its graph is parallel to and above the (x)-axis. A line parallel to and above the (x)-axis does not meet the (x)-axis. Tip: such a graph behaves like a non-zero constant polynomial.
Step 3
Exam Tip
(x)-अक्ष के समांतर ऊपर रेखा (x)-अक्ष से नहीं मिलती। टिप: ऐसा ग्राफ अशून्य स्थिर बहुपद जैसा होता है।
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यदि रेखा (y=2x-6) (x)-अक्ष को काटती है, तो संबंधित रैखिक बहुपद का शून्यक क्या है?
If the line (y=2x-6) cuts the (x)-axis, what is the zero of the related linear polynomial?
#linear-graph
#x-intercept
#zero
#polynomial
A (3)
B (-3)
C (6)
D (-6)
Explanation opens after your attempt
Step 1
Concept
On the (x)-axis, (y=0), so (2x-6=0) gives (x=3). This is the graphical zero.
Step 2
Why this answer is correct
The correct answer is A. (3). On the (x)-axis, (y=0), so (2x-6=0) gives (x=3). This is the graphical zero.
Step 3
Exam Tip
(x)-अक्ष पर (y=0), इसलिए (2x-6=0) से (x=3) मिलता है। यही ग्राफीय शून्यक है।
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यदि (p(x)=kx+12) का शून्य (3) है, तो (k) का मान क्या है?
If (3) is a zero of (p(x)=kx+12), what is the value of (k)?
#linear-polynomial
#zero
#parameter
A (4)
B (-4)
C (9)
D (-9)
Explanation opens after your attempt
Step 1
Concept
From (p(3)=0), we get (3k+12=0). Therefore (k=-4).
Step 2
Why this answer is correct
The correct answer is B. (-4). From (p(3)=0), we get (3k+12=0). Therefore (k=-4).
Step 3
Exam Tip
(p(3)=0) से (3k+12=0) मिलता है। इसलिए (k=-4) है।
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कौन सा मान (p(x)=x+4) का शून्यक है?
Which value is a zero of (p(x)=x+4)?
#polynomials
#zero
#linear
#easy
A (4)
B (-4)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
(p(-4)=-4+4=0), so (-4) is the zero. For (x+a), the zero is (-a).
Step 2
Why this answer is correct
The correct answer is B. (-4). (p(-4)=-4+4=0), so (-4) is the zero. For (x+a), the zero is (-a).
Step 3
Exam Tip
(p(-4)=-4+4=0), इसलिए (-4) शून्यक है। रैखिक बहुपद (x+a) का शून्यक (-a) होता है।
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यदि (p(x)=kx-2 -5x+6) का एक शून्यक (2) है, तो (k) का मान क्या होगा?
If (2) is a zero of (p(x)=kx-2 -5x+6), what is the value of (k)?
#polynomials
#zero
#value
#hard
A (1)
B (2)
C (-1)
D (-2)
Explanation opens after your attempt
Step 1
Concept
Putting (p(2)=0) gives (4k-10+6=0), so (k=1). For a zero, use (p\(\alpha\)=0).
Step 2
Why this answer is correct
The correct answer is A. (1). Putting (p(2)=0) gives (4k-10+6=0), so (k=1). For a zero, use (p\(\alpha\)=0).
Step 3
Exam Tip
(p(2)=0) रखने पर (4k-10+6=0) से (k=1) मिलता है। शून्यक के लिए (p\(\alpha\)=0) लगाएं।
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कौन सा बहुपद (x=0) को शून्य बनाता है?
Which polynomial makes (x=0) a zero?
#zero at zero
#constant term
#polynomial
A \(x^2+5\)
B \(3x^3-2x\)
C \(x^4+1\)
D \(2x^2-7x+9\)
Explanation opens after your attempt
Correct Answer
B. \(3x^3-2x\)
Step 1
Concept
Substituting (x=0) in \(3x^3-2x\) gives (0). To make (x=0) a zero, the constant term must be (0).
Step 2
Why this answer is correct
The correct answer is B. \(3x^3-2x\). Substituting (x=0) in \(3x^3-2x\) gives (0). To make (x=0) a zero, the constant term must be (0).
Step 3
Exam Tip
(x=0) रखने पर \(3x^3-2x=0\) मिलता है। (x=0) को शून्य बनाने के लिए अचर पद (0) होना चाहिए।
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यदि \(x^2+mx+n\) का एक शून्यक (0) है और दूसरा शून्यक (5) है, तो (m+n) क्या होगा?
If one zero of \(x^2+mx+n\) is (0) and the other zero is (5), what is (m+n)?
#polynomials
#zeroes
#constant_term
#hard
A (-5)
B (5)
C (0)
D (10)
Explanation opens after your attempt
Step 1
Concept
The sum is (5), so (m=-5), and the product is (0), so (n=0). Hence (m+n=-5).
Step 2
Why this answer is correct
The correct answer is A. (-5). The sum is (5), so (m=-5), and the product is (0), so (n=0). Hence (m+n=-5).
Step 3
Exam Tip
योग (5) है इसलिए (m=-5), और गुणनफल (0) है इसलिए (n=0)। अतः (m+n=-5)।
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कौन सा बहुपद (x=0) को शून्य नहीं बनाता?
Which polynomial does not make (x=0) a zero?
#zero at zero
#constant term
#polynomial
A \(x^3-2x\)
B \(5x^2+x\)
C \(x^4\)
D \(x^2+1\)
Explanation opens after your attempt
Correct Answer
D. \(x^2+1\)
Step 1
Concept
On substituting (x=0), \(x^2+1=1\), so (0) is not its zero. The constant term is decisive at (x=0).
Step 2
Why this answer is correct
The correct answer is D. \(x^2+1\). On substituting (x=0), \(x^2+1=1\), so (0) is not its zero. The constant term is decisive at (x=0).
Step 3
Exam Tip
(x=0) रखने पर \(x^2+1=1\), इसलिए (0) इसका शून्य नहीं है। (x=0) पर अचर पद निर्णायक होता है।
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यदि किसी बहुपद का एक शून्यक \(\sqrt{11}\) है और गुणांक परिमेय हैं, तो कौन सा शून्यक भी होना चाहिए?
If one zero of a polynomial is \(\sqrt{11}\) and the coefficients are rational, which zero should also occur?
#conjugate-zeroes
#polynomials
#irrational-roots
A -\(\sqrt{11}\)
B (11)
C \(\frac{1}{\sqrt{11}}\)
D \(1+\sqrt{11}\)
Explanation opens after your attempt
Correct Answer
A. -\(\sqrt{11}\)
Step 1
Concept
The conjugate of \(\sqrt{11}=0+\sqrt{11}\) is \(-\sqrt{11}\). In exams also identify the case (a=0).
Step 2
Why this answer is correct
The correct answer is A. -\(\sqrt{11}\). The conjugate of \(\sqrt{11}=0+\sqrt{11}\) is \(-\sqrt{11}\). In exams also identify the case (a=0).
Step 3
Exam Tip
\(\sqrt{11}=0+\sqrt{11}\) का संयुग्मी \(-\sqrt{11}\) है। परीक्षा में (a=0) वाला संयुग्मी भी पहचानें।
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यदि \(2+\sqrt{3}\) एक बहुपद \(x^2-4x+1\) का शून्यक है, तो दूसरा शून्यक क्या होगा?
If \(2+\sqrt{3}\) is a zero of the polynomial \(x^2-4x+1\), what is the other zero?
#conjugate roots
#polynomials
#irrational zeroes
A \(2-\sqrt{3}\)
B \(-2+\sqrt{3}\)
C \(-2-\sqrt{3}\)
D \(\sqrt{3}-4\)
Explanation opens after your attempt
Correct Answer
A. \(2-\sqrt{3}\)
Step 1
Concept
For a quadratic with rational coefficients, if \(a+\sqrt{b}\) is a zero then \(a-\sqrt{b}\) is also a zero. The conjugate-root rule is useful in exams.
Step 2
Why this answer is correct
The correct answer is A. \(2-\sqrt{3}\). For a quadratic with rational coefficients, if \(a+\sqrt{b}\) is a zero then \(a-\sqrt{b}\) is also a zero. The conjugate-root rule is useful in exams.
Step 3
Exam Tip
परिमेय गुणांकों वाले द्विघात में \(a+\sqrt{b}\) के साथ \(a-\sqrt{b}\) भी शून्यक होता है। परीक्षा में संयुग्मी मूल का नियम उपयोगी है।
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यदि (p(x)=x-2 -2kx+5) का एक शून्यक \(\sqrt{5}\) है, तो दूसरा शून्यक और (k) क्या होंगे?
If one zero of (p(x)=x-2 -2kx+5) is \(\sqrt{5}\), what will be the other zero and (k)?
#parameter
#product-of-zeroes
#irrational
A दूसरा \(\sqrt{5}\), \(k=\sqrt{5}\) / Other \(\sqrt{5}\), \(k=\sqrt{5}\)
B दूसरा \(-\sqrt{5}\), (k=0) / Other \(-\sqrt{5}\), (k=0)
C दूसरा (5), \(k=\frac{5+\sqrt{5}}{2}\) / Other (5), \(k=\frac{5+\sqrt{5}}{2}\)
D दूसरा (1), \(k=\frac{1+\sqrt{5}}{2}\) / Other (1), \(k=\frac{1+\sqrt{5}}{2}\)
Explanation opens after your attempt
Correct Answer
A. दूसरा \(\sqrt{5}\), \(k=\sqrt{5}\) / Other \(\sqrt{5}\), \(k=\sqrt{5}\)
Step 1
Concept
The product is (5), so the other zero is \(\frac{5}{\sqrt{5}}=\sqrt{5}\). The sum is \(2\sqrt{5}=2k\), hence \(k=\sqrt{5}\).
Step 2
Why this answer is correct
The correct answer is A. दूसरा \(\sqrt{5}\), \(k=\sqrt{5}\) / Other \(\sqrt{5}\), \(k=\sqrt{5}\). The product is (5), so the other zero is \(\frac{5}{\sqrt{5}}=\sqrt{5}\). The sum is \(2\sqrt{5}=2k\), hence \(k=\sqrt{5}\).
Step 3
Exam Tip
गुणनफल (5) है, इसलिए दूसरा शून्यक \(\frac{5}{\sqrt{5}}=\sqrt{5}\) होगा। योग \(2\sqrt{5}=2k\), अतः \(k=\sqrt{5}\) है।
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किसी परवलय का एक शून्यक (-10) है और दूसरा शून्यक पहले से (18) अधिक है। सममिति अक्ष क्या होगा?
One zero of a parabola is (-10), and the other zero is (18) more than the first. What is the axis of symmetry?
#axis symmetry
#word problem
#zeroes
A (x=-1)
B (x=1)
C (x=8)
D (x=-8)
Explanation opens after your attempt
Step 1
Concept
The other zero is (8), and the average is \(\frac{-10+8}{2}=-1\). Tip: the axis of symmetry is the average of two zeroes.
Step 2
Why this answer is correct
The correct answer is A. (x=-1). The other zero is (8), and the average is \(\frac{-10+8}{2}=-1\). Tip: the axis of symmetry is the average of two zeroes.
Step 3
Exam Tip
दूसरा शून्यक (8) है और औसत \(\frac{-10+8}{2}=-1\) है। टिप: सममिति अक्ष दो शून्यकों का औसत है।
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किसी परवलय का एक शून्यक (-8) है और दूसरा शून्यक पहले से (12) अधिक है। सममिति अक्ष क्या होगा?
One zero of a parabola is (-8), and the other zero is (12) more than the first. What is the axis of symmetry?
#axis symmetry
#word problem
#zeroes
A (x=-2)
B (x=2)
C (x=4)
D (x=-4)
Explanation opens after your attempt
Step 1
Concept
The other zero is (4), and the average is \(\frac{-8+4}{2}=-2\). Tip: the axis of symmetry is the average of two zeroes.
Step 2
Why this answer is correct
The correct answer is A. (x=-2). The other zero is (4), and the average is \(\frac{-8+4}{2}=-2\). Tip: the axis of symmetry is the average of two zeroes.
Step 3
Exam Tip
दूसरा शून्यक (4) है और औसत \(\frac{-8+4}{2}=-2\) है। टिप: सममिति अक्ष दो शून्यकों का औसत है।
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किसी परवलय का सममिति अक्ष (x=2) है और एक शून्यक (-3) है। दूसरा शून्यक क्या होगा?
The axis of symmetry of a parabola is (x=2) and one zero is (-3). What will be the other zero?
#parabola
#axis of symmetry
#zeroes
A (7)
B (5)
C (3)
D (-7)
Explanation opens after your attempt
Step 1
Concept
The average of the two zeroes is (2), so the other zero is (7). Tip: in a parabola the axis of symmetry passes through the midpoint of the zeroes.
Step 2
Why this answer is correct
The correct answer is A. (7). The average of the two zeroes is (2), so the other zero is (7). Tip: in a parabola the axis of symmetry passes through the midpoint of the zeroes.
Step 3
Exam Tip
दो शून्यकों का औसत (2) होगा, इसलिए दूसरा शून्यक (7) है। टिप: परवलय में सममिति अक्ष शून्यकों के मध्य से गुजरता है।
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(p(x)=16x-2 -24x+9) में कौन सा मान शून्य है?
Which value is a zero of (p(x)=16x-2 -24x+9)?
#zero
#fraction
#quadratic
A \(\frac{3}{4}\)
B \(-\frac{3}{4}\)
C \(\frac{4}{3}\)
D \(-\frac{4}{3}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{3}{4}\)
Step 1
Concept
(16x-2 -24x+9=(4x-3)2 ), so the zero is \(x=\frac{3}{4}\). Recognize the perfect square.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{3}{4}\). (16x-2 -24x+9=(4x-3)2 ), so the zero is \(x=\frac{3}{4}\). Recognize the perfect square.
Step 3
Exam Tip
(16x-2 -24x+9=(4x-3)2 ), इसलिए शून्य \(x=\frac{3}{4}\) है। पूर्ण वर्ग पहचानें।
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(p(x)=9x-2 +12x+4) में कौन सा मान शून्य है?
Which value is a zero of (p(x)=9x-2 +12x+4)?
#zero
#fraction
#quadratic
A \(-\frac{2}{3}\)
B \(\frac{2}{3}\)
C \(-\frac{3}{2}\)
D (2)
Explanation opens after your attempt
Correct Answer
A. \(-\frac{2}{3}\)
Step 1
Concept
(9x-2 +12x+4=(3x+2)2 ), so the zero is \(x=-\frac{2}{3}\). Recognize the perfect square.
Step 2
Why this answer is correct
The correct answer is A. \(-\frac{2}{3}\). (9x-2 +12x+4=(3x+2)2 ), so the zero is \(x=-\frac{2}{3}\). Recognize the perfect square.
Step 3
Exam Tip
(9x-2 +12x+4=(3x+2)2 ), इसलिए शून्य \(x=-\frac{2}{3}\) है। पूर्ण वर्ग पहचानें।
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(p(x)=4x-2 -12x+9) में कौन सा मान शून्य है?
Which value is a zero of (p(x)=4x-2 -12x+9)?
#zero
#fraction
#quadratic
A \(\frac{1}{2}\)
B \(\frac{3}{2}\)
C (2)
D (3)
Explanation opens after your attempt
Correct Answer
B. \(\frac{3}{2}\)
Step 1
Concept
(p\left\(\frac{3}{2}\right\)=9-18+9=0). While using a fraction, square and multiply correctly.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{3}{2}\). (p\left\(\frac{3}{2}\right\)=9-18+9=0). While using a fraction, square and multiply correctly.
Step 3
Exam Tip
(p\left\(\frac{3}{2}\right\)=9-18+9=0)। भिन्न मान रखते समय वर्ग और गुणा सही करें।
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किस मान के लिए \(x^2-6x+m\) में (x=2) शून्य होगा?
For what value of (m) will (x=2) be a zero of \(x^2-6x+m\)?
#zero
#parameter
#quadratic
A (6)
B (8)
C (10)
D (12)
Explanation opens after your attempt
Step 1
Concept
(4-12+m=0), so (m=8). When a zero is given, set the polynomial value equal to (0).
Step 2
Why this answer is correct
The correct answer is B. (8). (4-12+m=0), so (m=8). When a zero is given, set the polynomial value equal to (0).
Step 3
Exam Tip
(4-12+m=0), इसलिए (m=8)। शून्य दिए होने पर बहुपद का मान (0) रखें।
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यदि (p(x)=x-2 +px+16) और (4) इसका शून्य है, तो (p) का मान क्या है?
If (4) is a zero of (p(x)=x-2 +px+16), what is the value of (p)?
#zero
#parameter
#quadratic
A (-8)
B (-4)
C (4)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(4^2+4p+16=0\) gives (32+4p=0). Therefore (p=-8).
Step 2
Why this answer is correct
The correct answer is A. (-8). \(4^2+4p+16=0\) gives (32+4p=0). Therefore (p=-8).
Step 3
Exam Tip
\(4^2+4p+16=0\) से (32+4p=0) मिलता है। इसलिए (p=-8) है।
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यदि (p(x)=3x-2 +bx-10) में (x=2) एक शून्य है, तो (b) का मान क्या होगा?
If (x=2) is a zero of (p(x)=3x-2 +bx-10), what will be the value of (b)?
#zero
#parameter
#quadratic polynomial
A (-1)
B (-2)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(2)=12+2b-10=0), so (2b=-2) and (b=-1). When a zero is given, set the polynomial value equal to (0).
Step 2
Why this answer is correct
The correct answer is A. (-1). (p(2)=12+2b-10=0), so (2b=-2) and (b=-1). When a zero is given, set the polynomial value equal to (0).
Step 3
Exam Tip
(p(2)=12+2b-10=0), इसलिए (2b=-2) और (b=-1)। शून्य दिए होने पर बहुपद का मान (0) रखें।
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किस मान के लिए \(x^2-4x+m\) में (x=1) शून्य होगा?
For what value of (m) will (x=1) be a zero of \(x^2-4x+m\)?
#zero
#parameter
#quadratic
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(1-4+m=0), so (m=3). When a zero is given, set the polynomial value equal to (0).
Step 2
Why this answer is correct
The correct answer is C. (3). (1-4+m=0), so (m=3). When a zero is given, set the polynomial value equal to (0).
Step 3
Exam Tip
(1-4+m=0), इसलिए (m=3)। शून्य मिलने पर बहुपद का मान (0) रखें।
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बहुपद \(x^2-9\) का कौन सा मान शून्यक है?
Which value is a zero of the polynomial \(x^2-9\)?
#polynomials
#zero
#quadratic
#easy
A (2)
B (3)
C (4)
D (9)
Explanation opens after your attempt
Step 1
Concept
\(3^2-9=0\), so (3) is a zero. Substituting options is an easy method.
Step 2
Why this answer is correct
The correct answer is B. (3). \(3^2-9=0\), so (3) is a zero. Substituting options is an easy method.
Step 3
Exam Tip
\(3^2-9=0\), इसलिए (3) शून्यक है। विकल्पों को रखकर जांचना आसान तरीका है।
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यदि किसी ग्राफ पर ((2,3)) और ((5,0)) हैं तो कौन सा (x)-मान निश्चित शून्यक है?
If ((2,3)) and ((5,0)) lie on a graph, which (x)-value is definitely a zero?
#identify certain zero
A (2)
B (3)
C (5)
D (0)
Explanation opens after your attempt
Step 1
Concept
In ((5,0)), (y=0), so (5) is a zero. Tip: ((2,3)) does not show a zero.
Step 2
Why this answer is correct
The correct answer is C. (5). In ((5,0)), (y=0), so (5) is a zero. Tip: ((2,3)) does not show a zero.
Step 3
Exam Tip
((5,0)) में (y=0) है इसलिए (5) शून्यक है। टिप: ((2,3)) शून्यक नहीं दिखाता।
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शून्य बहुपद (p(x)=0) का हर (x)-मान क्या कहलाता है?
For the zero polynomial (p(x)=0) what is every (x)-value called?
#zero polynomial concept
A शून्यक / Zero
B केवल धनात्मक संख्या / Only positive number
C केवल ऋणात्मक संख्या / Only negative number
D कोई शून्यक नहीं / No zero
Explanation opens after your attempt
Correct Answer
A. शून्यक / Zero
Step 1
Concept
For the zero polynomial the value is (0) for every (x). Tip: this is a special case.
Step 2
Why this answer is correct
The correct answer is A. शून्यक / Zero. For the zero polynomial the value is (0) for every (x). Tip: this is a special case.
Step 3
Exam Tip
शून्य बहुपद में हर (x) पर मान (0) होता है। टिप: यह विशेष स्थिति है।
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ग्राफ में बिंदु ((-8,0)) दिखने पर बहुपद का कौन-सा मान शून्य होगा?
If the point ((-8,0)) appears on the graph, which value of the polynomial input gives zero?
#negative-zero
#coordinate-reading
#x-intercept
#polynomials
A (x=-8)
B (x=8)
C (x=0)
D (x=-1)
Explanation opens after your attempt
Step 1
Concept
The point ((-8,0)) means (y=0) at (x=-8). So (x=-8) makes the polynomial zero.
Step 2
Why this answer is correct
The correct answer is A. (x=-8). The point ((-8,0)) means (y=0) at (x=-8). So (x=-8) makes the polynomial zero.
Step 3
Exam Tip
((-8,0)) का अर्थ है (x=-8) पर (y=0)। इसलिए (x=-8) बहुपद को शून्य बनाता है।
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यदि (D=0) और कम से कम एक सहायक सारणिक शून्य नहीं है, तो युग्म की हल-स्थिति क्या होगी?
If (D=0) and at least one auxiliary determinant is non-zero, what is the solution status of the pair?
#class10
#linear-equations
#solvability
A अनंत हल / Infinitely many solutions
B अद्वितीय हल / Unique solution
C कोई हल नहीं / No solution
D सदैव हल / Always solvable
Explanation opens after your attempt
Correct Answer
C. कोई हल नहीं / No solution
Step 1
Concept
(D=0) with a non-zero auxiliary determinant indicates distinct parallel lines. Hence there is no solution.
Step 2
Why this answer is correct
The correct answer is C. कोई हल नहीं / No solution. (D=0) with a non-zero auxiliary determinant indicates distinct parallel lines. Hence there is no solution.
Step 3
Exam Tip
(D=0) और असंगत सहायक सारणिक समांतर अलग रेखाओं का संकेत देते हैं। इसलिए कोई हल नहीं होता।
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संख्या रेखा पर (r(x)=4x+6) का शून्यक किस अंतराल में होगा?
In which interval will the zero of (r(x)=4x+6) lie on the number line?
#polynomials
#number-line
#linear-zero
#medium
A (-2) और (-1) / (-2) and (-1)
B (-1) और (0) / (-1) and (0)
C (1) और (2) / (1) and (2)
D (0) और (1) / (0) and (1)
Explanation opens after your attempt
Correct Answer
A. (-2) और (-1) / (-2) and (-1)
Step 1
Concept
From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
Step 2
Why this answer is correct
The correct answer is A. (-2) और (-1) / (-2) and (-1). From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
Step 3
Exam Tip
(4x+6=0) से \(x=-\frac{3}{2}\), जो (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का अंतराल सावधानी से पहचानें।
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संख्या रेखा पर (p(x)=2x+5) का शून्यक किस बिंदु पर होगा?
At which point will the zero of (p(x)=2x+5) lie on the number line?
#polynomials
#number-line
#linear-polynomial-zero
#medium
A (2.5)
B (-2.5)
C (5)
D (-5)
Explanation opens after your attempt
Step 1
Concept
From (2x+5=0), we get \(x=-\frac{5}{2}=-2.5\). In exams, find the zero and place it like a real number.
Step 2
Why this answer is correct
The correct answer is B. (-2.5). From (2x+5=0), we get \(x=-\frac{5}{2}=-2.5\). In exams, find the zero and place it like a real number.
Step 3
Exam Tip
(2x+5=0) से \(x=-\frac{5}{2}=-2.5\) मिलता है। परीक्षा में शून्यक निकालकर उसे वास्तविक संख्या की तरह रखें।
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यदि (p(x)=4x-12), तो इसका शून्यक क्या है?
If (p(x)=4x-12), what is its zero?
#linear-polynomial
#zero
#evaluation
A (3)
B -(3)
C (4)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (4x-12=0), we get (x=3). A zero is the value where the polynomial becomes (0).
Step 2
Why this answer is correct
The correct answer is A. (3). From (4x-12=0), we get (x=3). A zero is the value where the polynomial becomes (0).
Step 3
Exam Tip
(4x-12=0) से (x=3) मिलता है। शून्यक वह मान है जहाँ बहुपद का मान (0) हो।
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यदि (p(x)=ax+b) और \(a\neq0\), तो इसका शून्यक क्या है?
If (p(x)=ax+b) and \(a\neq0\), what is its zero?
#linear-zero
#general-form
#polynomial
A -\(\frac{b}{a}\)
B \(\frac{b}{a}\)
C -\(\frac{a}{b}\)
D \(\frac{a}{b}\)
Explanation opens after your attempt
Correct Answer
A. -\(\frac{b}{a}\)
Step 1
Concept
Putting (ax+b=0) gives \(x=-\frac{b}{a}\). A linear polynomial has exactly one zero.
Step 2
Why this answer is correct
The correct answer is A. -\(\frac{b}{a}\). Putting (ax+b=0) gives \(x=-\frac{b}{a}\). A linear polynomial has exactly one zero.
Step 3
Exam Tip
(ax+b=0) रखने पर \(x=-\frac{b}{a}\) मिलता है। रेखीय बहुपद में केवल एक शून्यक होता है।
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यदि (p(x)=cx+d) और \(c\ne0\), तो इसका शून्य क्या होगा?
If (p(x)=cx+d) and \(c\ne0\), what will be its zero?
#linear zero
#general form
#formula
A \(\frac{d}{c}\)
B \(-\frac{d}{c}\)
C (cd)
D (c-d)
Explanation opens after your attempt
Correct Answer
B. \(-\frac{d}{c}\)
Step 1
Concept
From (cx+d=0), we get \(x=-\frac{d}{c}\). Remember the negative sign in the formula.
Step 2
Why this answer is correct
The correct answer is B. \(-\frac{d}{c}\). From (cx+d=0), we get \(x=-\frac{d}{c}\). Remember the negative sign in the formula.
Step 3
Exam Tip
(cx+d=0) से \(x=-\frac{d}{c}\) मिलता है। सूत्र में ऋण चिह्न ध्यान रखें।
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(p(x)=4x+20) का शून्य कौन सा है?
Which is the zero of (p(x)=4x+20)?
#linear polynomial
#zero
#solution
A (5)
B (-5)
C (4)
D (-4)
Explanation opens after your attempt
Step 1
Concept
From (4x+20=0), we get (x=-5). A zero is the value that makes the polynomial equal to (0).
Step 2
Why this answer is correct
The correct answer is B. (-5). From (4x+20=0), we get (x=-5). A zero is the value that makes the polynomial equal to (0).
Step 3
Exam Tip
(4x+20=0) से (x=-5) मिलता है। शून्य वह मान है जिससे बहुपद (0) हो जाए।
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(p(x)=9x-27) का शून्य क्या है?
What is the zero of (p(x)=9x-27)?
#linear zero
#equation
#polynomial
A (2)
B (3)
C (9)
D (27)
Explanation opens after your attempt
Step 1
Concept
From (9x-27=0), we get (x=3). Find the zero of a linear polynomial by solving the equation.
Step 2
Why this answer is correct
The correct answer is B. (3). From (9x-27=0), we get (x=3). Find the zero of a linear polynomial by solving the equation.
Step 3
Exam Tip
(9x-27=0) से (x=3) मिलता है। रैखिक बहुपद का शून्य समीकरण हल करके निकालें।
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(x=-3) किस बहुपद का शून्य है?
For which polynomial is (x=-3) a zero?
#zero
#linear polynomial
#evaluation
A (p(x)=x+3)
B (p(x)=x-3)
C (p(x)=3x+1)
D (p(x)=x-2 +3)
Explanation opens after your attempt
Correct Answer
A. (p(x)=x+3)
Step 1
Concept
(p(-3)=-3+3=0), so (x=-3) is its zero. To test a zero, substitute the value and check for (0).
Step 2
Why this answer is correct
The correct answer is A. (p(x)=x+3). (p(-3)=-3+3=0), so (x=-3) is its zero. To test a zero, substitute the value and check for (0).
Step 3
Exam Tip
(p(-3)=-3+3=0), इसलिए (x=-3) इसका शून्य है। शून्य जांचने के लिए मान रखकर परिणाम (0) देखें।
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(p(x)=x+9) का शून्य क्या है?
What is the zero of (p(x)=x+9)?
#linear-polynomial
#zero
#easy
A (9)
B (-9)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
Setting (x+9=0) gives (x=-9). The zero of (x+a) is (-a).
Step 2
Why this answer is correct
The correct answer is B. (-9). Setting (x+9=0) gives (x=-9). The zero of (x+a) is (-a).
Step 3
Exam Tip
(x+9=0) करने पर (x=-9) मिलता है। (x+a) का शून्य (-a) होता है।
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यदि (p(x)=ax+b) और \(a\ne0\), तो इसका शून्य क्या होगा?
If (p(x)=ax+b) and \(a\ne0\), what will be its zero?
#linear zero
#general form
#formula
A \(\frac{b}{a}\)
B \(-\frac{b}{a}\)
C (ab)
D (a+b)
Explanation opens after your attempt
Correct Answer
B. \(-\frac{b}{a}\)
Step 1
Concept
From (ax+b=0), we get \(x=-\frac{b}{a}\). Remember the general formula but do not miss the sign.
Step 2
Why this answer is correct
The correct answer is B. \(-\frac{b}{a}\). From (ax+b=0), we get \(x=-\frac{b}{a}\). Remember the general formula but do not miss the sign.
Step 3
Exam Tip
(ax+b=0) से \(x=-\frac{b}{a}\) मिलता है। सामान्य सूत्र याद रखें लेकिन संकेत न भूलें।
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(p(x)=3x+12) का शून्य कौन सा है?
Which is the zero of (p(x)=3x+12)?
#linear polynomial
#zero
#solution
A (4)
B (-4)
C (3)
D (-3)
Explanation opens after your attempt
Step 1
Concept
From (3x+12=0), we get (x=-4). A zero is the value that makes the polynomial equal to (0).
Step 2
Why this answer is correct
The correct answer is B. (-4). From (3x+12=0), we get (x=-4). A zero is the value that makes the polynomial equal to (0).
Step 3
Exam Tip
(3x+12=0) से (x=-4) मिलता है। शून्य वह मान है जिससे बहुपद (0) हो जाए।
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(p(x)=7x-14) का शून्य क्या है?
What is the zero of (p(x)=7x-14)?
#linear zero
#equation
#polynomial
A (1)
B (2)
C (7)
D (14)
Explanation opens after your attempt
Step 1
Concept
From (7x-14=0), we get (x=2). Solve the equation to find the zero of a linear polynomial.
Step 2
Why this answer is correct
The correct answer is B. (2). From (7x-14=0), we get (x=2). Solve the equation to find the zero of a linear polynomial.
Step 3
Exam Tip
(7x-14=0) से (x=2) मिलता है। रैखिक बहुपद का शून्य जल्दी निकालने के लिए समीकरण हल करें।
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(x=2) किस बहुपद का शून्य है?
For which polynomial is (x=2) a zero?
#zero
#linear polynomial
#evaluation
A (p(x)=x-2)
B (p(x)=x+2)
C (p(x)=2x+1)
D (p(x)=x-2 +2)
Explanation opens after your attempt
Correct Answer
A. (p(x)=x-2)
Step 1
Concept
(p(2)=2-2=0), so (x=2) is its zero. To test a zero, substitute and check for (0).
Step 2
Why this answer is correct
The correct answer is A. (p(x)=x-2). (p(2)=2-2=0), so (x=2) is its zero. To test a zero, substitute and check for (0).
Step 3
Exam Tip
(p(2)=2-2=0), इसलिए (x=2) इसका शून्य है। शून्य जांचने के लिए मान रखकर (0) देखें।
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(p(x)=x-6) का शून्य क्या है?
What is the zero of (p(x)=x-6)?
#zero
#linear-polynomial
A (6)
B (-6)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
Setting (x-6=0) gives (x=6). The zero of (x-a) is (a).
Step 2
Why this answer is correct
The correct answer is A. (6). Setting (x-6=0) gives (x=6). The zero of (x-a) is (a).
Step 3
Exam Tip
(x-6=0) करने पर (x=6) आता है। (x-a) का शून्य (a) होता है।
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(p(x)=5x+10) का शून्यक कौन सा है?
Which is the zero of (p(x)=5x+10)?
#polynomials
#zero
#linear
#easy
A (2)
B (-2)
C (5)
D (-5)
Explanation opens after your attempt
Step 1
Concept
From (5x+10=0), we get (x=-2). Do not forget the sign change.
Step 2
Why this answer is correct
The correct answer is B. (-2). From (5x+10=0), we get (x=-2). Do not forget the sign change.
Step 3
Exam Tip
(5x+10=0) से (x=-2) मिलता है। चिह्न बदलना न भूलें।
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यदि (p(x)=3x-12) है, तो इसका शून्यक क्या है?
If (p(x)=3x-12), what is its zero?
#polynomials
#zero
#linear
#easy
A (3)
B (4)
C (-4)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (3x-12=0), we get (x=4). For a linear polynomial, form a simple equation.
Step 2
Why this answer is correct
The correct answer is B. (4). From (3x-12=0), we get (x=4). For a linear polynomial, form a simple equation.
Step 3
Exam Tip
(3x-12=0) से (x=4) मिलता है। रैखिक बहुपद में सीधे समीकरण बनाएं।
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रेखा (y=-3x-12) का शून्यक क्या है?
What is the zero of the line (y=-3x-12)?
#linear zero
#x intercept
#graph
A (4)
B (-4)
C (12)
D (-12)
Explanation opens after your attempt
Step 1
Concept
Solving (-3x-12=0) gives (x=-4). Tip: put (y=0) to find the linear zero.
Step 2
Why this answer is correct
The correct answer is B. (-4). Solving (-3x-12=0) gives (x=-4). Tip: put (y=0) to find the linear zero.
Step 3
Exam Tip
(-3x-12=0) से (x=-4) मिलता है। टिप: (y=0) रखकर रैखिक शून्यक निकालें।
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यदि (p(x)=x), तो ग्राफ का शून्यक क्या है?
If (p(x)=x), what is the zero of the graph?
#linear-polynomial
#origin
#zero
#easy
A (0)
B (1)
C (-1)
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
For the zero, (x=0) because (p(x)=x). The graph passes through the origin.
Step 2
Why this answer is correct
The correct answer is A. (0). For the zero, (x=0) because (p(x)=x). The graph passes through the origin.
Step 3
Exam Tip
शून्यक के लिए (x=0) होना चाहिए क्योंकि (p(x)=x)। ग्राफ मूल बिंदु से गुजरता है।
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रेखा (y=x+9) का शून्यक क्या होगा?
What will be the zero of the line (y=x+9)?
#linear-polynomial
#negative-zero
#x-intercept
#polynomials
A (9)
B (-9)
C (0)
D (18)
Explanation opens after your attempt
Step 1
Concept
For the zero, (x+9=0), so (x=-9). Do not make a sign error.
Step 2
Why this answer is correct
The correct answer is B. (-9). For the zero, (x+9=0), so (x=-9). Do not make a sign error.
Step 3
Exam Tip
शून्यक के लिए (x+9=0), इसलिए (x=-9)। चिह्न बदलने की गलती न करें।
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रेखा (y=x-8) का शून्यक कौन-सा है?
What is the zero of the line (y=x-8)?
#linear-graph
#zero
#x-axis
#easy
A (8)
B (-8)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
For the zero, (y=0), so (x-8=0) gives (x=8). The graph cuts the (x)-axis at (8).
Step 2
Why this answer is correct
The correct answer is A. (8). For the zero, (y=0), so (x-8=0) gives (x=8). The graph cuts the (x)-axis at (8).
Step 3
Exam Tip
शून्यक के लिए (y=0), इसलिए (x-8=0) से (x=8) मिलता है। ग्राफ (x)-अक्ष को (8) पर काटता है।
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यदि रेखा (y=x+7) का ग्राफ (x)-अक्ष को काटता है, तो शून्यक क्या होगा?
If the graph of the line (y=x+7) cuts the (x)-axis, what is the zero?
#linear-polynomial
#zero
#x-intercept
#easy
A (7)
B (-7)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
On the (x)-axis, (y=0), so (x+7=0) gives (x=-7). Watch the negative sign carefully.
Step 2
Why this answer is correct
The correct answer is B. (-7). On the (x)-axis, (y=0), so (x+7=0) gives (x=-7). Watch the negative sign carefully.
Step 3
Exam Tip
(x)-अक्ष पर (y=0), इसलिए (x+7=0) से (x=-7) मिलता है। ऋण चिह्न को ध्यान से देखें।
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यदि (p(x)=x+2) का ग्राफ (x)-अक्ष को काटता है, तो शून्यक कौन-सा है?
If the graph of (p(x)=x+2) cuts the (x)-axis, which is the zero?
#linear-polynomial
#negative-zero
#x-intercept
#easy
A (2)
B (-2)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
For the zero, (x+2=0), so (x=-2). The graph cuts the (x)-axis at (x=-2).
Step 2
Why this answer is correct
The correct answer is B. (-2). For the zero, (x+2=0), so (x=-2). The graph cuts the (x)-axis at (x=-2).
Step 3
Exam Tip
शून्यक के लिए (x+2=0), इसलिए (x=-2)। ग्राफ (x)-अक्ष को (x=-2) पर काटेगा।
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यदि (p(x)=x-4) का ग्राफ (x)-अक्ष को काटता है, तो शून्यक क्या होगा?
If the graph of (p(x)=x-4) cuts the (x)-axis, what is the zero?
#linear-polynomial
#zero
#graphical-meaning
#class-10
A (4)
B (-4)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
For the zero, (x-4=0), so (x=4). The graph also cuts the (x)-axis at (x=4).
Step 2
Why this answer is correct
The correct answer is A. (4). For the zero, (x-4=0), so (x=4). The graph also cuts the (x)-axis at (x=4).
Step 3
Exam Tip
शून्यक के लिए (x-4=0), इसलिए (x=4)। ग्राफ भी (x)-अक्ष को (x=4) पर काटेगा।
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किस स्थिति में (x=3) बहुपद (p(x)) का शून्यक कहलाएगा?
In which situation will (x=3) be called a zero of polynomial (p(x))?
#definition
#zero
#function-value
A जब (p(3)=0) / When (p(3)=0)
B जब (p(0)=3) / When (p(0)=3)
C जब ग्राफ ((0,3)) से गुजरे / When the graph passes through ((0,3))
D जब (p(3)=3) / When (p(3)=3)
Explanation opens after your attempt
Correct Answer
A. जब (p(3)=0) / When (p(3)=0)
Step 1
Concept
A zero is the (x)-value at which the polynomial value is zero. In exams check (p(a)=0).
Step 2
Why this answer is correct
The correct answer is A. जब (p(3)=0) / When (p(3)=0). A zero is the (x)-value at which the polynomial value is zero. In exams check (p(a)=0).
Step 3
Exam Tip
शून्यक वही (x)-मान है जिस पर बहुपद का मान शून्य हो। परीक्षा में (p(a)=0) जांचें।
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यदि (p(-1)<0), (p(0)<0) और (p(2)=0), तो दिए गए मानों में कौन सा शून्यक निश्चित है?
If (p(-1)<0), (p(0)<0) and (p(2)=0), which zero is definite among the given values?
#definite zero
#function value
#graph
A (-1)
B (0)
C (2)
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
Only (p(2)=0) directly shows a zero. Tip: positive or negative values are not zeroes.
Step 2
Why this answer is correct
The correct answer is C. (2). Only (p(2)=0) directly shows a zero. Tip: positive or negative values are not zeroes.
Step 3
Exam Tip
केवल (p(2)=0) सीधे शून्यक बताता है। टिप: धनात्मक या ऋणात्मक मान शून्यक नहीं होते।
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यदि (p(2)=3) है तो बिंदु ((2,3)) आलेख पर है। क्या (2) शून्यक है?
If (p(2)=3) then the point ((2,3)) is on the graph. Is (2) a zero?
#not a zero value
A नहीं / No
B हाँ / Yes
C केवल द्विघात में हाँ / Yes only in quadratic
D निर्धारित नहीं किया जा सकता / Cannot be decided
Explanation opens after your attempt
Correct Answer
A. नहीं / No
Step 1
Concept
For a zero (p(2)) should be (0). Tip: if (p(a)\neq0) then (a) is not a zero.
Step 2
Why this answer is correct
The correct answer is A. नहीं / No. For a zero (p(2)) should be (0). Tip: if (p(a)\neq0) then (a) is not a zero.
Step 3
Exam Tip
शून्यक के लिए (p(2)) को (0) होना चाहिए था। टिप: (p(a)\neq0) हो तो (a) शून्यक नहीं है।
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यदि (p(0)=4), तो क्या (0) बहुपद का शून्यक है?
If (p(0)=4), is (0) a zero of the polynomial?
#value-test
#not-zero
#origin
#polynomials
A नहीं / No
B हाँ / Yes
C केवल रैखिक बहुपद में / Only in a linear polynomial
D केवल द्विघात बहुपद में / Only in a quadratic polynomial
Explanation opens after your attempt
Correct Answer
A. नहीं / No
Step 1
Concept
For (0) to be a zero, (p(0)=0) must be true. Here (p(0)=4), so (0) is not a zero.
Step 2
Why this answer is correct
The correct answer is A. नहीं / No. For (0) to be a zero, (p(0)=0) must be true. Here (p(0)=4), so (0) is not a zero.
Step 3
Exam Tip
शून्यक होने के लिए (p(0)=0) होना चाहिए। यहाँ (p(0)=4), इसलिए (0) शून्यक नहीं है।
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यदि (p(2)=5), तो क्या (2) बहुपद का शून्यक है?
If (p(2)=5), is (2) a zero of the polynomial?
#value-test
#not-zero
#polynomials
#easy
A नहीं / No
B हाँ / Yes
C केवल द्विघात में / Only in quadratic
D केवल रैखिक में / Only in linear
Explanation opens after your attempt
Correct Answer
A. नहीं / No
Step 1
Concept
For (2) to be a zero, (p(2)=0) must hold. Here (p(2)=5), so (2) is not a zero.
Step 2
Why this answer is correct
The correct answer is A. नहीं / No. For (2) to be a zero, (p(2)=0) must hold. Here (p(2)=5), so (2) is not a zero.
Step 3
Exam Tip
शून्यक होने के लिए (p(2)=0) होना चाहिए। यहाँ (p(2)=5), इसलिए (2) शून्यक नहीं है।
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किस स्थिति में (x=2) बहुपद (p(x)) का शून्यक कहलाएगा?
In which situation will (x=2) be called a zero of polynomial (p(x))?
#definition
#zero-of-polynomial
#value-test
#easy
A जब (p(2)=0) हो / When (p(2)=0)
B जब (p(0)=2) हो / When (p(0)=2)
C जब (p(2)=2) हो / When (p(2)=2)
D जब (p(x)=2) हो / When (p(x)=2)
Explanation opens after your attempt
Correct Answer
A. जब (p(2)=0) हो / When (p(2)=0)
Step 1
Concept
A value is called a zero only when the polynomial value at that point is (0). So for (x=2), (p(2)=0) is required.
Step 2
Why this answer is correct
The correct answer is A. जब (p(2)=0) हो / When (p(2)=0). A value is called a zero only when the polynomial value at that point is (0). So for (x=2), (p(2)=0) is required.
Step 3
Exam Tip
किसी मान को शून्यक तभी कहते हैं जब उस पर बहुपद का मान (0) हो। इसलिए (x=2) के लिए (p(2)=0) होना चाहिए।
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बहुपद (p(x)) के ग्राफ में (y=p(x)) होता है। शून्यक पर (y) का मान क्या होगा?
In the graph of polynomial (p(x)), (y=p(x)). What is the value of (y) at a zero?
#definition
#y-value
#zeroes
#graph
A (0)
B (1)
C (-1)
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Step 1
Concept
At a zero, the value of the polynomial is (0). Therefore the (y)-value at that point on the graph is (0).
Step 2
Why this answer is correct
The correct answer is A. (0). At a zero, the value of the polynomial is (0). Therefore the (y)-value at that point on the graph is (0).
Step 3
Exam Tip
शून्यक पर बहुपद का मान (0) होता है। इसलिए ग्राफ पर उस बिंदु का (y)-मान (0) होगा।
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यदि (4(2x-y)+3(x+y)=53) और (2(2x-y)-5(x+y)=-17), तो (y) का मान क्या है?
If (4(2x-y)+3(x+y)=53) and (2(2x-y)-5(x+y)=-17), what is the value of (y)?
#pair-linear-equations-linear-combination
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Let (u=2x-y) and (v=x+y). Solve the two equations first, then convert back to (x) and (y).
Step 2
Why this answer is correct
The correct answer is B. (5). Let (u=2x-y) and (v=x+y). Solve the two equations first, then convert back to (x) and (y).
Step 3
Exam Tip
मान लें (u=2x-y) और (v=x+y)। (4u+3v=53), (2u-5v=-17) से (u=7), \(v=\frac{25}{3}\), इसलिए \(y=\frac{29}{9}\)।
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यदि (5(2x-y)-3(x+y)=11) और (2(2x-y)+4(x+y)=50), तो (y) का मान क्या है?
If (5(2x-y)-3(x+y)=11) and (2(2x-y)+4(x+y)=50), what is the value of (y)?
#pair-linear-equations
#linear-combination
#substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Let (u=2x-y) and (v=x+y). Solving (5u-3v=11), (2u+4v=50) gives (u=7,v=9), hence \(y=\frac{11}{3}\).
Step 2
Why this answer is correct
The correct answer is A. (3). Let (u=2x-y) and (v=x+y). Solving (5u-3v=11), (2u+4v=50) gives (u=7,v=9), hence \(y=\frac{11}{3}\).
Step 3
Exam Tip
मान लें (u=2x-y) और (v=x+y)। (5u-3v=11), (2u+4v=50) से (u=7,v=9), इसलिए \(y=\frac{11}{3}\)।
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यदि \(2+\sqrt{3}\) किसी परिमेय गुणांक वाले बहुपद का शून्यक है, तो किस रैखिक गुणनखंड का साथ आना अपेक्षित है?
If \(2+\sqrt{3}\) is a zero of a polynomial with rational coefficients, which linear factor is expected to accompany it?
#factor-theorem
#conjugate-zeroes
#polynomials
A (x-\(2-\sqrt{3}\))
B (x-\(2+\sqrt{3}\)) ही केवल / (x-\(2+\sqrt{3}\)) only
C (x-\(\sqrt{3}-2\))
D (x+\(2+\sqrt{3}\))
Explanation opens after your attempt
Correct Answer
A. (x-\(2-\sqrt{3}\))
Step 1
Concept
The companion zero is \(2-\sqrt{3}\), so the factor is (x-\(2-\sqrt{3}\)). In exams remember the relation between a zero and factor as \(x-\alpha\).
Step 2
Why this answer is correct
The correct answer is A. (x-\(2-\sqrt{3}\)). The companion zero is \(2-\sqrt{3}\), so the factor is (x-\(2-\sqrt{3}\)). In exams remember the relation between a zero and factor as \(x-\alpha\).
Step 3
Exam Tip
साथी शून्यक \(2-\sqrt{3}\) होगा, इसलिए गुणनखंड (x-\(2-\sqrt{3}\)) है। परीक्षा में शून्यक और गुणनखंड का संबंध \(x-\alpha\) याद रखें।
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यदि (4x+5y=7) और (8x-5y=29), तो (3x-y) का मान क्या है?
If (4x+5y=7) and (8x-5y=29), what is the value of (3x-y)?
#pair-linear-equations-negative-value
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Adding gives (12x=36), so (x=3) and (y=-1). Therefore (3x-y=10).
Step 2
Why this answer is correct
The correct answer is C. (10). Adding gives (12x=36), so (x=3) and (y=-1). Therefore (3x-y=10).
Step 3
Exam Tip
जोड़ने पर (12x=36), इसलिए (x=3) और (y=-1)। अतः (3x-y=10)।
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समीकरणों (2x+7y=31) और (5x-7y=4) के हल में (x+y) का मान क्या है?
For (2x+7y=31) and (5x-7y=4), what is the value of (x+y) in the solution?
#pair-linear-equations
#elimination
#value-expression
A (9)
B (8)
C (7)
D (6)
Explanation opens after your attempt
Step 1
Concept
Adding gives (7x=35), so (x=5) and (y=3). Therefore (x+y=8); substitute back before choosing the option.
Step 2
Why this answer is correct
The correct answer is A. (9). Adding gives (7x=35), so (x=5) and (y=3). Therefore (x+y=8); substitute back before choosing the option.
Step 3
Exam Tip
जोड़ने पर (7x=35), इसलिए (x=5) और (y=3)। अतः (x+y=8) नहीं बल्कि ध्यान से रखने पर (5+3=8) मिलता है।
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समीकरण (7x+4y=2) और (3x-4y=18) के हल में (x-y) का मान क्या होगा?
For (7x+4y=2) and (3x-4y=18), what is the value of (x-y) in the solution?
#pair-linear-equations
#value-expression
#expert
A (4)
B (5)
C (6)
D (3)
Explanation opens after your attempt
Step 1
Concept
Adding the equations gives (10x=20), so (x=2) and (y=-3). Therefore (x-y=5).
Step 2
Why this answer is correct
The correct answer is B. (5). Adding the equations gives (10x=20), so (x=2) and (y=-3). Therefore (x-y=5).
Step 3
Exam Tip
समीकरण जोड़ने पर (10x=20), इसलिए (x=2) और (y=-3)। अतः (x-y=5)।
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यदि (x=5y-8) और (4x+3y=61), तो (y) का मान क्या है?
If (x=5y-8) and (4x+3y=61), what is the value of (y)?
#linear equations
#substitution
#fraction value
#expert
#class 10
A \(y=\frac{83}{23}\)
B \(y=\frac{88}{23}\)
C \(y=\frac{93}{23}\)
D \(y=\frac{98}{23}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{93}{23}\)
Step 1
Concept
Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{93}{23}\). Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).
Step 3
Exam Tip
(x=5y-8) को दूसरे समीकरण में रखें। (20y-32+3y=61), इसलिए \(y=\frac{93}{23}\)।
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समीकरणों (9x-5y=42) और (3x+5y=30) से (x+2y) का मान क्या है?
What is the value of (x+2y) from (9x-5y=42) and (3x+5y=30)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(x+2y=\frac{44}{5}\)
B \(x+2y=\frac{49}{5}\)
C \(x+2y=\frac{54}{5}\)
D \(x+2y=\frac{59}{5}\)
Explanation opens after your attempt
Correct Answer
C. \(x+2y=\frac{54}{5}\)
Step 1
Concept
Adding both equations gives (12x=72), so (x=6). Then \(y=\frac{12}{5}\), hence \(x+2y=\frac{54}{5}\).
Step 2
Why this answer is correct
The correct answer is C. \(x+2y=\frac{54}{5}\). Adding both equations gives (12x=72), so (x=6). Then \(y=\frac{12}{5}\), hence \(x+2y=\frac{54}{5}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (12x=72), इसलिए (x=6)। फिर \(y=\frac{12}{5}\), अतः \(x+2y=\frac{54}{5}\)।
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समीकरणों (6x+9y=117) और (8x-3y=37) से (y) का मान क्या है?
What is the value of (y) from (6x+9y=117) and (8x-3y=37)?
#linear equations
#elimination
#fraction value
#expert
#class 10
A \(y=\frac{109}{15}\)
B \(y=\frac{114}{15}\)
C \(y=\frac{119}{15}\)
D \(y=\frac{124}{15}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{119}{15}\)
Step 1
Concept
Multiply the second equation by (3) and add it to the first. Solving gives \(y=\frac{119}{15}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{119}{15}\). Multiply the second equation by (3) and add it to the first. Solving gives \(y=\frac{119}{15}\).
Step 3
Exam Tip
दूसरे समीकरण को (3) से गुणा कर पहले में जोड़ें। हल करने पर \(y=\frac{119}{15}\) मिलता है।
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समीकरणों \(\frac{x+4y}{5}=10\) और \(\frac{3x-y}{4}=7\) से (x-y) का मान क्या है?
What is the value of (x-y) from \(\frac{x+4y}{5}=10\) and \(\frac{3x-y}{4}=7\)?
#linear equations
#transformed equations
#expression value
#expert
#class 10
A \(x-y=\frac{34}{13}\)
B \(x-y=\frac{40}{13}\)
C \(x-y=\frac{46}{13}\)
D \(x-y=\frac{52}{13}\)
Explanation opens after your attempt
Correct Answer
B. \(x-y=\frac{40}{13}\)
Step 1
Concept
The equations become (x+4y=50) and (3x-y=28). Solving gives \(x-y=\frac{40}{13}\).
Step 2
Why this answer is correct
The correct answer is B. \(x-y=\frac{40}{13}\). The equations become (x+4y=50) and (3x-y=28). Solving gives \(x-y=\frac{40}{13}\).
Step 3
Exam Tip
दिए समीकरण (x+4y=50) और (3x-y=28) बनते हैं। हल से \(x-y=\frac{40}{13}\)।
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यदि (x+y=31) और (4x-3y=19), तो (2x-y) का मान क्या है?
If (x+y=31) and (4x-3y=19), what is the value of (2x-y)?
#linear equations
#substitution
#expression value
#expert
#class 10
A (15)
B (16)
C (17)
D (18)
Explanation opens after your attempt
Step 1
Concept
Using (x=31-y) gives (124-7y=19), so (y=15) and (x=16). Hence (2x-y=17).
Step 2
Why this answer is correct
The correct answer is C. (17). Using (x=31-y) gives (124-7y=19), so (y=15) and (x=16). Hence (2x-y=17).
Step 3
Exam Tip
(x=31-y) रखने पर (124-7y=19), इसलिए (y=15) और (x=16)। अतः (2x-y=17)।
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समीकरणों (9x+2y=10) और (3x-2y=14) से (y) का मान क्या है?
What is the value of (y) from (9x+2y=10) and (3x-2y=14)?
#linear equations
#elimination
#negative value
#expert
#class 10
A (y=-5)
B (y=-4)
C (y=-3)
D (y=-2)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (12x=24), so (x=2). The first equation gives (y=-4).
Step 2
Why this answer is correct
The correct answer is B. (y=-4). Adding both equations gives (12x=24), so (x=2). The first equation gives (y=-4).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (12x=24), इसलिए (x=2)। पहले समीकरण से (y=-4)।
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समीकरणों (0.5x+0.4y=6.1) और (0.3x-0.2y=1.7) से (x+y) का मान क्या है?
What is the value of (x+y) from (0.5x+0.4y=6.1) and (0.3x-0.2y=1.7)?
#linear equations
#decimal equations
#expression value
#expert
#class 10
A \(x+y=\frac{134}{11}\)
B \(x+y=\frac{139}{11}\)
C \(x+y=\frac{144}{11}\)
D \(x+y=\frac{149}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(x+y=\frac{144}{11}\)
Step 1
Concept
Removing decimals gives (5x+4y=61) and (3x-2y=17). Solving gives \(x+y=\frac{144}{11}\).
Step 2
Why this answer is correct
The correct answer is C. \(x+y=\frac{144}{11}\). Removing decimals gives (5x+4y=61) and (3x-2y=17). Solving gives \(x+y=\frac{144}{11}\).
Step 3
Exam Tip
दशमलव हटाने पर (5x+4y=61) और (3x-2y=17) मिलते हैं। हल से \(x+y=\frac{144}{11}\) मिलता है।
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यदि (7x+6y=70) और (7x-4y=20), तो (x-y) का मान क्या है?
If (7x+6y=70) and (7x-4y=20), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(x-y=\frac{3}{7}\)
B \(x-y=\frac{4}{7}\)
C \(x-y=\frac{5}{7}\)
D \(x-y=\frac{6}{7}\)
Explanation opens after your attempt
Correct Answer
C. \(x-y=\frac{5}{7}\)
Step 1
Concept
Subtracting the second equation from the first gives (10y=50), so (y=5). Then \(x=\frac{40}{7}\), hence \(x-y=\frac{5}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(x-y=\frac{5}{7}\). Subtracting the second equation from the first gives (10y=50), so (y=5). Then \(x=\frac{40}{7}\), hence \(x-y=\frac{5}{7}\).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (10y=50), इसलिए (y=5)। फिर \(x=\frac{40}{7}\), अतः \(x-y=\frac{5}{7}\)।
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समीकरणों (11x+4y=91) और (5x-4y=21) से (y) का मान क्या है?
What is the value of (y) from (11x+4y=91) and (5x-4y=21)?
#linear equations
#elimination
#fraction value
#expert
#class 10
A \(y=\frac{5}{2}\)
B (y=3)
C \(y=\frac{7}{2}\)
D (y=4)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{7}{2}\)
Step 1
Concept
Adding both equations gives (16x=112), so (x=7). The first equation gives \(y=\frac{7}{2}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{7}{2}\). Adding both equations gives (16x=112), so (x=7). The first equation gives \(y=\frac{7}{2}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (16x=112), इसलिए (x=7)। पहले समीकरण से \(y=\frac{7}{2}\)।
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समीकरणों (4x-7y=9) और (6x+7y=71) से (x+y) का मान क्या है?
What is the value of (x+y) from (4x-7y=9) and (6x+7y=71)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(x+y=\frac{73}{7}\)
B \(x+y=\frac{75}{7}\)
C \(x+y=\frac{77}{7}\)
D \(x+y=\frac{79}{7}\)
Explanation opens after your attempt
Correct Answer
D. \(x+y=\frac{79}{7}\)
Step 1
Concept
Adding both equations gives (10x=80), so (x=8). Then \(y=\frac{23}{7}\), hence \(x+y=\frac{79}{7}\).
Step 2
Why this answer is correct
The correct answer is D. \(x+y=\frac{79}{7}\). Adding both equations gives (10x=80), so (x=8). Then \(y=\frac{23}{7}\), hence \(x+y=\frac{79}{7}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=80), इसलिए (x=8)। फिर \(y=\frac{23}{7}\), अतः \(x+y=\frac{79}{7}\)।
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यदि (5x+6y=142) और (6x+5y=144), तो (x-y) का मान क्या है?
If (5x+6y=142) and (6x+5y=144), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#expert
#class 10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the first equation from the second directly gives (x-y=2). In such questions, subtraction saves time.
Step 2
Why this answer is correct
The correct answer is B. (2). Subtracting the first equation from the second directly gives (x-y=2). In such questions, subtraction saves time.
Step 3
Exam Tip
दूसरे समीकरण से पहला घटाने पर (x-y=2) सीधे मिलता है। ऐसे प्रश्नों में घटाना समय बचाता है।
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समीकरणों (7x+4y=58) और (3x-4y=22) को हल करने पर (y) का मान क्या है?
On solving (7x+4y=58) and (3x-4y=22), what is the value of (y)?
#linear equations
#elimination
#fraction value
#expert
#class 10
A \(y=\frac{1}{2}\)
B (y=1)
C \(y=\frac{3}{2}\)
D (y=2)
Explanation opens after your attempt
Correct Answer
A. \(y=\frac{1}{2}\)
Step 1
Concept
Adding both equations gives (10x=80), so (x=8). The first equation gives \(y=\frac{1}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(y=\frac{1}{2}\). Adding both equations gives (10x=80), so (x=8). The first equation gives \(y=\frac{1}{2}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=80), इसलिए (x=8)। पहले समीकरण से \(y=\frac{1}{2}\)।
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यदि (2x+3y=41) और (5x-2y=14), तो (2x+y) का मान क्या है?
If (2x+3y=41) and (5x-2y=14), what is the value of (2x+y)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(2x+y=\frac{405}{19}\)
B \(2x+y=\frac{415}{19}\)
C \(2x+y=\frac{425}{19}\)
D \(2x+y=\frac{435}{19}\)
Explanation opens after your attempt
Correct Answer
C. \(2x+y=\frac{425}{19}\)
Step 1
Concept
Elimination gives \(x=\frac{124}{19}\) and \(y=\frac{177}{19}\). Therefore \(2x+y=\frac{425}{19}\).
Step 2
Why this answer is correct
The correct answer is C. \(2x+y=\frac{425}{19}\). Elimination gives \(x=\frac{124}{19}\) and \(y=\frac{177}{19}\). Therefore \(2x+y=\frac{425}{19}\).
Step 3
Exam Tip
विलोपन से \(x=\frac{124}{19}\) और \(y=\frac{177}{19}\) मिलता है। इसलिए \(2x+y=\frac{425}{19}\)।
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यदि (5x-3y=19) और (2x+3y=26), तो (x-y) का मान क्या है?
If (5x-3y=19) and (2x+3y=26), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(x-y=\frac{43}{21}\)
B \(x-y=\frac{47}{21}\)
C \(x-y=\frac{51}{21}\)
D \(x-y=\frac{55}{21}\)
Explanation opens after your attempt
Correct Answer
A. \(x-y=\frac{43}{21}\)
Step 1
Concept
Adding both equations gives (7x=45). Then \(y=\frac{92}{21}\), so \(x-y=\frac{43}{21}\).
Step 2
Why this answer is correct
The correct answer is A. \(x-y=\frac{43}{21}\). Adding both equations gives (7x=45). Then \(y=\frac{92}{21}\), so \(x-y=\frac{43}{21}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (7x=45) मिलता है। फिर \(y=\frac{92}{21}\), इसलिए \(x-y=\frac{43}{21}\)।
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यदि (4x-5y=-7) और (6x+5y=57), तो (3x+y) का मान क्या है?
If (4x-5y=-7) and (6x+5y=57), what is the value of (3x+y)?
#linear equations
#elimination
#expression value
#hard
#class 10
A (22)
B (24)
C (26)
D (28)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (10x=50), so (x=5). Then \(y=\frac{27}{5}\), hence \(3x+y=\frac{102}{5}\), so none of the options is correct.
Step 2
Why this answer is correct
The correct answer is D. (28). Adding both equations gives (10x=50), so (x=5). Then \(y=\frac{27}{5}\), hence \(3x+y=\frac{102}{5}\), so none of the options is correct.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=50), इसलिए (x=5)। फिर \(y=\frac{27}{5}\), अतः \(3x+y=\frac{102}{5}\), इसलिए विकल्पों में कोई सही नहीं है।
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यदि (x=4y-7) और (3x+2y=59), तो (y) का मान क्या है?
If (x=4y-7) and (3x+2y=59), what is the value of (y)?
#linear equations
#substitution
#fraction value
#hard
#class 10
A \(y=\frac{36}{14}\)
B \(y=\frac{40}{14}\)
C \(y=\frac{80}{14}\)
D \(y=\frac{84}{14}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{80}{14}\)
Step 1
Concept
Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{80}{14}\). Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).
Step 3
Exam Tip
(x=4y-7) को दूसरे समीकरण में रखिए। (12y-21+2y=59), इसलिए \(y=\frac{40}{7}\)।
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