C. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\)
Step 1
Concept
Infinite solutions occur when both lines are the same line. For this, all three ratios are equal.
Step 2
Why this answer is correct
The correct answer is C. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\). Infinite solutions occur when both lines are the same line. For this, all three ratios are equal.
Step 3
Exam Tip
अनंत समाधान तब होते हैं जब दोनों रेखाएं एक ही रेखा हों। इसके लिए तीनों अनुपात बराबर होते हैं।
The second equation is (2) times the first, so the lines are coincident. In coincident lines, every point is a solution.
Step 2
Why this answer is correct
The correct answer is D. अनंत / Infinite. The second equation is (2) times the first, so the lines are coincident. In coincident lines, every point is a solution.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है, इसलिए रेखाएं संपाती हैं। संपाती रेखाओं में हर बिंदु समाधान होता है।
The second equation is (2) times the first. Therefore the lines are coincident and have infinitely many common points.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore the lines are coincident and have infinitely many common points.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है। इसलिए रेखाएँ संपाती हैं और उनके अनंत सामान्य बिंदु हैं।
The second equation is (2) times the first. Hence the lines are coincident and have infinitely many common points.
Step 2
Why this answer is correct
The correct answer is C. अनंत / Infinitely many. The second equation is (2) times the first. Hence the lines are coincident and have infinitely many common points.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों रेखाएँ संपाती हैं और अनंत सामान्य बिंदु हैं।
B. जब रेखाएँ एक ही रेखा हों/When lines are the same line
Step 1
Concept
All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is B. जब रेखाएँ एक ही रेखा हों / When lines are the same line. All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.
Step 3
Exam Tip
एक ही रेखा के सभी बिंदु दोनों समीकरणों को संतुष्ट करते हैं। इसलिए अनंत हल मिलते हैं।
All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is B. अनंत हल / Infinitely many solutions. All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.
Step 3
Exam Tip
एक ही रेखा के सभी बिंदु दोनों समीकरणों को संतुष्ट करते हैं। इसलिए अनंत हल मिलते हैं।
B. जब रेखाएँ एक ही रेखा हों/When lines are the same line
Step 1
Concept
All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is B. जब रेखाएँ एक ही रेखा हों / When lines are the same line. All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.
Step 3
Exam Tip
एक ही रेखा के सभी बिंदु दोनों समीकरणों को संतुष्ट करते हैं। इसलिए अनंत हल मिलते हैं।
Coincident lines have infinitely many common points. Therefore, such a pair of equations has infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is B. अनंत हल / Infinitely many solutions. Coincident lines have infinitely many common points. Therefore, such a pair of equations has infinitely many solutions.
Step 3
Exam Tip
संपाती रेखाओं के अनंत सामान्य बिंदु होते हैं। इसलिए ऐसे समीकरण युग्म के अनंत हल होते हैं।
Every point on coincident lines satisfies both equations. In exams, call this a consistent and dependent case.
Step 2
Why this answer is correct
The correct answer is A. अनंत हल / Infinitely many solutions. Every point on coincident lines satisfies both equations. In exams, call this a consistent and dependent case.
Step 3
Exam Tip
संपाती रेखाओं के सभी बिंदु दोनों समीकरणों को संतुष्ट करते हैं। परीक्षा में इसे संगत और आश्रित स्थिति कहें।
From \(y^2-25y+144=0\), (y=9,16), so \(x^2=9,16\) and \(x=\pm3,\pm4\). In exams, do not forget to return to (x).
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm3,\pm4\). From \(y^2-25y+144=0\), (y=9,16), so \(x^2=9,16\) and \(x=\pm3,\pm4\). In exams, do not forget to return to (x).
Step 3
Exam Tip
\(y^2-25y+144=0\) से (y=9,16), इसलिए \(x^2=9,16\) और \(x=\pm3,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।
From \(y^2-20y+64=0\), (y=4,16), so \(x^2=4,16\) and \(x=\pm2,\pm4\). In exams, do not forget to return to (x).
Step 2
Why this answer is correct
The correct answer is B. \(x=\pm4,\pm2\). From \(y^2-20y+64=0\), (y=4,16), so \(x^2=4,16\) and \(x=\pm2,\pm4\). In exams, do not forget to return to (x).
Step 3
Exam Tip
\(y^2-20y+64=0\) से (y=4,16), इसलिए \(x^2=4,16\) और \(x=\pm2,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।
From \(y^2-17y+16=0\), (y=1,16), so \(x^2=1,16\) and \(x=\pm1,\pm4\). In exams, do not forget to return to (x).
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm1,\pm4\). From \(y^2-17y+16=0\), (y=1,16), so \(x^2=1,16\) and \(x=\pm1,\pm4\). In exams, do not forget to return to (x).
Step 3
Exam Tip
\(y^2-17y+16=0\) से (y=1,16), इसलिए \(x^2=1,16\) और \(x=\pm1,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।
From \(y^2-13y+36=0\), (y=4,9), so \(x^2=4,9\) and \(x=\pm2,\pm3\). In exams, do not forget to return to (x).
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm2,\pm3\). From \(y^2-13y+36=0\), (y=4,9), so \(x^2=4,9\) and \(x=\pm2,\pm3\). In exams, do not forget to return to (x).
Step 3
Exam Tip
\(y^2-13y+36=0\) से (y=4,9), इसलिए \(x^2=4,9\) और \(x=\pm2,\pm3\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।
A quadratic equation can have at most (2) real solutions. In easy questions, degree indicates the maximum possible solutions.
Step 2
Why this answer is correct
The correct answer is B. (2). A quadratic equation can have at most (2) real solutions. In easy questions, degree indicates the maximum possible solutions.
Step 3
Exam Tip
द्विघात समीकरण के अधिकतम (2) वास्तविक हल हो सकते हैं। आसान प्रश्न में घात से अधिकतम हल का संकेत मिलता है।
Unequal coefficient ratios make the lines intersect at one point. Therefore the pair is consistent and independent.
Step 2
Why this answer is correct
The correct answer is B. ठीक (1) हल / Exactly (1) solution. Unequal coefficient ratios make the lines intersect at one point. Therefore the pair is consistent and independent.
Step 3
Exam Tip
असमान गुणांक अनुपात से रेखाएँ एक बिंदु पर कटती हैं। इसलिए युग्म संगत और स्वतंत्र होता है।
One intersection point means the equations have exactly one solution. Remember, intersecting lines are consistent and independent.
Step 2
Why this answer is correct
The correct answer is A. (1) अद्वितीय हल / (1) unique solution. One intersection point means the equations have exactly one solution. Remember, intersecting lines are consistent and independent.
Step 3
Exam Tip
एक प्रतिच्छेद बिंदु होने पर समीकरणों का एक ही हल होता है। याद रखें, कटती हुई रेखाएँ संगत और स्वतंत्र होती हैं।
The graph does not meet the (x)-axis, so there is no real solution. Tip: (p(x)=0) means an (x)-axis intersection on the graph.
Step 2
Why this answer is correct
The correct answer is A. शून्य / Zero. The graph does not meet the (x)-axis, so there is no real solution. Tip: (p(x)=0) means an (x)-axis intersection on the graph.
Step 3
Exam Tip
आलेख (x)-अक्ष से नहीं मिलता इसलिए कोई वास्तविक हल नहीं है। टिप: (p(x)=0) ग्राफ पर (x)-अक्ष कटान है।
In Class 10 real numbers the square root of a negative number is not real. Note that \(\sqrt{7}\) is real irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{-4}\). In Class 10 real numbers the square root of a negative number is not real. Note that \(\sqrt{7}\) is real irrational.
Step 3
Exam Tip
कक्षा 10 के वास्तविक संख्याओं में ऋणात्मक संख्या की वर्गमूल वास्तविक नहीं मानी जाती। ध्यान दें \(\sqrt{7}\) वास्तविक अपरिमेय है।
C. \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\) जैसे अनेक बिंदु/Many points like \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\)
Step 1
Concept
Between (0) and (1), there are infinitely many rational and irrational numbers. Between any two real numbers, more numbers can be found.
Step 2
Why this answer is correct
The correct answer is C. \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\) जैसे अनेक बिंदु / Many points like \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\). Between (0) and (1), there are infinitely many rational and irrational numbers. Between any two real numbers, more numbers can be found.
Step 3
Exam Tip
(0) और (1) के बीच परिमेय और अपरिमेय दोनों प्रकार की अनंत संख्याएं होती हैं। किसी भी दो वास्तविक संख्याओं के बीच और संख्याएं मिलती हैं।
A. कथन और कारण दोनों सही हैं/Both assertion and reason are correct
Step 1
Concept
Here (D=32-4(1)(7)=-19). Since (D<0), the assertion is correct.
Step 2
Why this answer is correct
The correct answer is A. कथन और कारण दोनों सही हैं / Both assertion and reason are correct. Here (D=32-4(1)(7)=-19). Since (D<0), the assertion is correct.
Step 3
Exam Tip
यहाँ (D=32-4(1)(7)=-19) है। (D<0) होने से कथन सही है।
The principal square root is always non-negative, so \(\sqrt{a^2}=|a|\). In exams do not forget the possibility of negative (a).
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{a^2}=|a|\). The principal square root is always non-negative, so \(\sqrt{a^2}=|a|\). In exams do not forget the possibility of negative (a).
Step 3
Exam Tip
मुख्य वर्गमूल हमेशा अऋणात्मक होता है, इसलिए \(\sqrt{a^2}=|a|\) है। परीक्षा में (a) ऋणात्मक होने की संभावना न भूलें।
\(\sqrt{-9}\) is not a real number, while the others are real. In exams do not take the square root of a negative number in the real number system.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{-9}\). \(\sqrt{-9}\) is not a real number, while the others are real. In exams do not take the square root of a negative number in the real number system.
Step 3
Exam Tip
\(\sqrt{-9}\) वास्तविक संख्या नहीं है, जबकि बाकी सभी वास्तविक हैं। परीक्षा में ऋणात्मक संख्या का वर्गमूल वास्तविक संख्या पद्धति में नहीं लेते।
\(\sqrt{45}=3\sqrt{5}\), which is real and irrational. In exams do not treat the square root of a negative number as real.
Step 2
Why this answer is correct
The correct answer is C. \(\sqrt{45}\). \(\sqrt{45}=3\sqrt{5}\), which is real and irrational. In exams do not treat the square root of a negative number as real.
Step 3
Exam Tip
\(\sqrt{45}=3\sqrt{5}\), जो वास्तविक और अपरिमेय है। परीक्षा में ऋणात्मक वर्गमूल को वास्तविक संख्या न मानें।
C. कोई वास्तविक मूल नहीं है/There are no real roots
Step 1
Concept
The discriminant is (4-20=-16), which is negative, so there are no real roots. In exams do not treat a negative discriminant as real zeroes.
Step 2
Why this answer is correct
The correct answer is C. कोई वास्तविक मूल नहीं है / There are no real roots. The discriminant is (4-20=-16), which is negative, so there are no real roots. In exams do not treat a negative discriminant as real zeroes.
Step 3
Exam Tip
विविक्तकर (4-20=-16) ऋणात्मक है, इसलिए वास्तविक मूल नहीं हैं। परीक्षा में ऋणात्मक विविक्तकर को वास्तविक शून्यक नहीं मानें।
If (x) were rational then \(\sqrt{2}+x\) would be irrational. So (x) must be irrational; remember the sum rule for rational and irrational numbers.
Step 2
Why this answer is correct
The correct answer is B. (x) अपरिमेय है / (x) is irrational. If (x) were rational then \(\sqrt{2}+x\) would be irrational. So (x) must be irrational; remember the sum rule for rational and irrational numbers.
Step 3
Exam Tip
यदि (x) परिमेय होता तो \(\sqrt{2}+x\) अपरिमेय होता। इसलिए (x) अपरिमेय होना चाहिए; परीक्षा में परिमेय और अपरिमेय के योग का नियम याद रखें।
A. \(b^2-4c\) धनात्मक अपूर्ण वर्ग हो/\(b^2-4c\) is positive and not a perfect square
Step 1
Concept
For real zeroes, the discriminant must be positive, and for irrational zeroes it must not be a perfect square. This is the key check for quadratics with rational coefficients.
Step 2
Why this answer is correct
The correct answer is A. \(b^2-4c\) धनात्मक अपूर्ण वर्ग हो / \(b^2-4c\) is positive and not a perfect square. For real zeroes, the discriminant must be positive, and for irrational zeroes it must not be a perfect square. This is the key check for quadratics with rational coefficients.
Step 3
Exam Tip
वास्तविक शून्यकों के लिए विविक्तकर धनात्मक चाहिए और अपरिमेय शून्यकों के लिए वह पूर्ण वर्ग नहीं होना चाहिए। परिमेय गुणांकों वाले द्विघात में यही मुख्य जाँच है।
For \(x^2-8x+3\), (D=64-12=52), positive and not a perfect square. The other options give equal rational, non-real, or rational zeroes.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x+3\). For \(x^2-8x+3\), (D=64-12=52), positive and not a perfect square. The other options give equal rational, non-real, or rational zeroes.
Step 3
Exam Tip
\(x^2-8x+3\) के लिए (D=64-12=52), जो धनात्मक अपूर्ण वर्ग है। बाकी विकल्पों में शून्यक समान परिमेय, अवास्तविक या परिमेय हैं।
B. (k) धनात्मक हो लेकिन पूर्ण वर्ग न हो/(k) is positive but not a perfect square
Step 1
Concept
The zeroes are \(x=\pm\sqrt{k}\). They are irrational real when (k>0) and (k) is not a perfect square.
Step 2
Why this answer is correct
The correct answer is B. (k) धनात्मक हो लेकिन पूर्ण वर्ग न हो / (k) is positive but not a perfect square. The zeroes are \(x=\pm\sqrt{k}\). They are irrational real when (k>0) and (k) is not a perfect square.
Step 3
Exam Tip
शून्यक \(x=\pm\sqrt{k}\) हैं। ये अपरिमेय वास्तविक तभी होंगे जब (k>0) और (k) पूर्ण वर्ग न हो।
The zeroes are \(x=\pm\sqrt{2}\), and \(\sqrt{2}\) is irrational. In exams, simplify square-root zeroes before deciding the type.
Step 2
Why this answer is correct
The correct answer is B. दोनों अपरिमेय हैं / Both are irrational. The zeroes are \(x=\pm\sqrt{2}\), and \(\sqrt{2}\) is irrational. In exams, simplify square-root zeroes before deciding the type.
Step 3
Exam Tip
शून्यक \(x=\pm\sqrt{2}\) हैं और \(\sqrt{2}\) अपरिमेय है। परीक्षा में वर्गमूल वाले शून्यकों को सरल करके जाँचें।
A real number that is not rational is called irrational. It can also be identified through its decimal form.
Step 2
Why this answer is correct
The correct answer is A. अपरिमेय संख्या / Irrational number. A real number that is not rational is called irrational. It can also be identified through its decimal form.
Step 3
Exam Tip
वास्तविक संख्या जो परिमेय नहीं होती वह अपरिमेय कहलाती है। इसे दशमलव से भी पहचाना जा सकता है।
\(\sqrt{18}\) is irrational and its negative is also real irrational. A negative sign does not change rationality.
Step 2
Why this answer is correct
The correct answer is A. \(-\sqrt{18}\). \(\sqrt{18}\) is irrational and its negative is also real irrational. A negative sign does not change rationality.
Step 3
Exam Tip
\(\sqrt{18}\) अपरिमेय है और उसका ऋण भी वास्तविक अपरिमेय है। ऋण चिह्न परिमेयता नहीं बदलता।
A. इनमें परिमेय और अपरिमेय दोनों शामिल हैं/They include both rational and irrational numbers
Step 1
Concept
Real numbers form the large set of rational and irrational numbers. They can be represented on the number line.
Step 2
Why this answer is correct
The correct answer is A. इनमें परिमेय और अपरिमेय दोनों शामिल हैं / They include both rational and irrational numbers. Real numbers form the large set of rational and irrational numbers. They can be represented on the number line.
Step 3
Exam Tip
वास्तविक संख्याएँ परिमेय और अपरिमेय संख्याओं का बड़ा समुच्चय हैं। संख्या रेखा पर इन्हें दर्शाया जा सकता है।
The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।
The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।
The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।
Same slope and same intercept mean both lines are identical. Therefore, the pair has infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. Same slope and same intercept mean both lines are identical. Therefore, the pair has infinitely many solutions.
Step 3
Exam Tip
समान ढाल और समान अवरोध का अर्थ है कि दोनों रेखाएं एक ही हैं। इसलिए युग्म के अनंत हल होते हैं।
The second equation is (3) times the first. Therefore both conditions give the same information and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore both conditions give the same information and have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।
The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।
The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।
Every point on the same line satisfies both equations. Therefore such a pair has infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is D. अनंत हल / Infinitely many solutions. Every point on the same line satisfies both equations. Therefore such a pair has infinitely many solutions.
Step 3
Exam Tip
एक ही रेखा के हर बिंदु से दोनों समीकरण संतुष्ट होते हैं। इसलिए ऐसे युग्म में अनंत हल होते हैं।
The second equation is (2) times the first so the lines are coincident. Coincident lines have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first so the lines are coincident. Coincident lines have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है इसलिए रेखाएं संपाती हैं। संपाती रेखाओं में अनंत हल होते हैं।
In a consistent and dependent pair both equations represent the same line. Therefore every common point is a solution.
Step 2
Why this answer is correct
The correct answer is D. अनंत हल / Infinitely many solutions. In a consistent and dependent pair both equations represent the same line. Therefore every common point is a solution.
Step 3
Exam Tip
संगत और आश्रित युग्म में दोनों समीकरण एक ही रेखा दर्शाते हैं। इसलिए हर सामान्य बिंदु हल होता है।
In the first option the second equation is (2) times the first. Therefore the lines are coincident and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is A. (x+y=5) और (2x+2y=10) / (x+y=5) and (2x+2y=10). In the first option the second equation is (2) times the first. Therefore the lines are coincident and have infinitely many solutions.
Step 3
Exam Tip
पहले विकल्प में दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं।
Infinitely many common solutions occur only when both equations represent the same line. In exams this can be written as coincident lines.
Step 2
Why this answer is correct
The correct answer is B. एक ही रेखा / Same line. Infinitely many common solutions occur only when both equations represent the same line. In exams this can be written as coincident lines.
Step 3
Exam Tip
अनंत सामान्य हल तभी मिलते हैं जब दोनों समीकरण एक ही रेखा दर्शाते हैं। परीक्षा में इसे coincident lines लिख सकते हैं।
The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है इसलिए दोनों रेखाएं संपाती हैं। संपाती रेखाओं में अनंत हल होते हैं।
The first equation is (2) times the second, so both lines are coincident. Coincident lines have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The first equation is (2) times the second, so both lines are coincident. Coincident lines have infinitely many solutions.
Step 3
Exam Tip
पहला समीकरण दूसरे का (2) गुना है, इसलिए दोनों रेखाएं संपाती हैं। संपाती रेखाओं के अनंत हल होते हैं।
For infinitely many solutions, all three ratios must be equal. Then both equations form the same line.
Step 2
Why this answer is correct
The correct answer is C. \(a_1 / a_2=b_1 / b_2=c_1 / c_2\). For infinitely many solutions, all three ratios must be equal. Then both equations form the same line.
Step 3
Exam Tip
अनंत हल के लिए तीनों अनुपात बराबर होने चाहिए। इससे दोनों समीकरण एक ही रेखा बनाते हैं।
