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9 results found for "real-solutions" in Class 10.

Question Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^4-25x^2+144=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-25x^2+144=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm3,\pm4\)

Step 1

Concept

From \(y^2-25y+144=0\), (y=9,16), so \(x^2=9,16\) and \(x=\pm3,\pm4\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm3,\pm4\). From \(y^2-25y+144=0\), (y=9,16), so \(x^2=9,16\) and \(x=\pm3,\pm4\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-25y+144=0\) से (y=9,16), इसलिए \(x^2=9,16\) और \(x=\pm3,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^4-20x^2+64=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-20x^2+64=0\)?

Explanation opens after your attempt
Correct Answer

B. \(x=\pm4,\pm2\)

Step 1

Concept

From \(y^2-20y+64=0\), (y=4,16), so \(x^2=4,16\) and \(x=\pm2,\pm4\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is B. \(x=\pm4,\pm2\). From \(y^2-20y+64=0\), (y=4,16), so \(x^2=4,16\) and \(x=\pm2,\pm4\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-20y+64=0\) से (y=4,16), इसलिए \(x^2=4,16\) और \(x=\pm2,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^4-17x^2+16=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-17x^2+16=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm1,\pm4\)

Step 1

Concept

From \(y^2-17y+16=0\), (y=1,16), so \(x^2=1,16\) and \(x=\pm1,\pm4\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm1,\pm4\). From \(y^2-17y+16=0\), (y=1,16), so \(x^2=1,16\) and \(x=\pm1,\pm4\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-17y+16=0\) से (y=1,16), इसलिए \(x^2=1,16\) और \(x=\pm1,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^4-13x^2+36=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-13x^2+36=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm2,\pm3\)

Step 1

Concept

From \(y^2-13y+36=0\), (y=4,9), so \(x^2=4,9\) and \(x=\pm2,\pm3\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm2,\pm3\). From \(y^2-13y+36=0\), (y=4,9), so \(x^2=4,9\) and \(x=\pm2,\pm3\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-13y+36=0\) से (y=4,9), इसलिए \(x^2=4,9\) और \(x=\pm2,\pm3\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^4-10x^2+9=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-10x^2+9=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm1,\pm3\)

Step 1

Concept

From \(y^2-10y+9=0\), (y=1,9), so \(x^2=1,9\) and \(x=\pm1,\pm3\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm1,\pm3\). From \(y^2-10y+9=0\), (y=1,9), so \(x^2=1,9\) and \(x=\pm1,\pm3\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-10y+9=0\) से (y=1,9), इसलिए \(x^2=1,9\) और \(x=\pm1,\pm3\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^4-5x^2+4=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-5x^2+4=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm1,\pm2\)

Step 1

Concept

From \(y^2-5y+4=0\), (y=1,4), so \(x^2=1,4\) and \(x=\pm1,\pm2\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm1,\pm2\). From \(y^2-5y+4=0\), (y=1,4), so \(x^2=1,4\) and \(x=\pm1,\pm2\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-5y+4=0\) से (y=1,4), इसलिए \(x^2=1,4\) और \(x=\pm1,\pm2\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

\(2x^2+7x+3=0\) के अधिकतम कितने वास्तविक हल हो सकते हैं?

What is the maximum number of real solutions possible for \(2x^2+7x+3=0\)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

A quadratic equation can have at most (2) real solutions. The degree indicates the maximum number of solutions.

Step 2

Why this answer is correct

The correct answer is B. (2). A quadratic equation can have at most (2) real solutions. The degree indicates the maximum number of solutions.

Step 3

Exam Tip

द्विघात समीकरण के अधिकतम (2) वास्तविक हल हो सकते हैं। घात से अधिकतम हलों का संकेत मिलता है।

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Question Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

\(x^2+3x+2=0\) में कितने अधिकतम वास्तविक हल हो सकते हैं?

What is the maximum number of real solutions possible for \(x^2+3x+2=0\)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

A quadratic equation can have at most (2) real solutions. In easy questions, degree indicates the maximum possible solutions.

Step 2

Why this answer is correct

The correct answer is B. (2). A quadratic equation can have at most (2) real solutions. In easy questions, degree indicates the maximum possible solutions.

Step 3

Exam Tip

द्विघात समीकरण के अधिकतम (2) वास्तविक हल हो सकते हैं। आसान प्रश्न में घात से अधिकतम हल का संकेत मिलता है।

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Question Medium Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि परवलय (x)-अक्ष के नीचे रहता है और उसे कहीं नहीं छूता तो (p(x)=0) के वास्तविक हल कितने हैं?

If a parabola stays below the (x)-axis and never touches it, how many real solutions does (p(x)=0) have?

Explanation opens after your attempt
Correct Answer

A. शून्यZero

Step 1

Concept

The graph does not meet the (x)-axis, so there is no real solution. Tip: (p(x)=0) means an (x)-axis intersection on the graph.

Step 2

Why this answer is correct

The correct answer is A. शून्य / Zero. The graph does not meet the (x)-axis, so there is no real solution. Tip: (p(x)=0) means an (x)-axis intersection on the graph.

Step 3

Exam Tip

आलेख (x)-अक्ष से नहीं मिलता इसलिए कोई वास्तविक हल नहीं है। टिप: (p(x)=0) ग्राफ पर (x)-अक्ष कटान है।

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