Concept-wise Practice

parallel lines MCQ Questions for Class 10

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Practice Questions

79 questions tagged with parallel lines.

Question 1/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि (9x+2y=18) और (27x+my=55) की रेखाएं समांतर अलग-अलग हों, तो (m) का मान क्या होगा?

If the lines (9x+2y=18) and (27x+my=55) are distinct parallel lines, what will be the value of (m)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For parallel lines, \(\frac{9}{27}=\frac{2}{m}\), so (m=6). Since \(\frac{18}{55}\neq\frac{1}{3}\), the lines are not coincident.

Step 2

Why this answer is correct

The correct answer is C. (6). For parallel lines, \(\frac{9}{27}=\frac{2}{m}\), so (m=6). Since \(\frac{18}{55}\neq\frac{1}{3}\), the lines are not coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{9}{27}=\frac{2}{m}\), इसलिए (m=6)। क्योंकि \(\frac{18}{55}\neq\frac{1}{3}\), रेखाएं संपाती नहीं हैं।

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Question 2/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (3x-8y=11) और (6x-16y=25) का ग्राफीय निष्कर्ष क्या है?

What is the graphical conclusion for (3x-8y=11) and (6x-16y=25)?

Explanation opens after your attempt
Correct Answer

C. कोई समाधान नहींNo solution

Step 1

Concept

\(\frac{3}{6}=\frac{-8}{-16}\neq\frac{11}{25}\), so the lines are distinct and parallel. Such a pair has no solution.

Step 2

Why this answer is correct

The correct answer is C. कोई समाधान नहीं / No solution. \(\frac{3}{6}=\frac{-8}{-16}\neq\frac{11}{25}\), so the lines are distinct and parallel. Such a pair has no solution.

Step 3

Exam Tip

\(\frac{3}{6}=\frac{-8}{-16}\neq\frac{11}{25}\), इसलिए रेखाएं समांतर अलग-अलग हैं। ऐसे युग्म का कोई समाधान नहीं होता।

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Question 3/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि किसी युग्म का ग्राफ दो समांतर अलग-अलग रेखाएं दिखाता है, तो समाधान को कैसे लिखा जा सकता है?

If the graph of a pair shows two distinct parallel lines, how can the solution be described?

Explanation opens after your attempt
Correct Answer

A. कोई समाधान नहींNo solution

Step 1

Concept

Distinct parallel lines have no common point. Therefore such a pair gives no solution.

Step 2

Why this answer is correct

The correct answer is A. कोई समाधान नहीं / No solution. Distinct parallel lines have no common point. Therefore such a pair gives no solution.

Step 3

Exam Tip

समांतर अलग-अलग रेखाओं में कोई साझी बिंदु नहीं होता। इसलिए ऐसा युग्म कोई समाधान नहीं देता।

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Question 4/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (9x+12y=45) और (3x+4y=20) का ग्राफ कैसा होगा?

What will be the graph of (9x+12y=45) and (3x+4y=20)?

Explanation opens after your attempt
Correct Answer

C. समांतर अलग-अलगDistinct parallel

Step 1

Concept

\(\frac{9}{3}=\frac{12}{4}\neq\frac{45}{20}\), so the lines are distinct and parallel. Check the constant term ratio also.

Step 2

Why this answer is correct

The correct answer is C. समांतर अलग-अलग / Distinct parallel. \(\frac{9}{3}=\frac{12}{4}\neq\frac{45}{20}\), so the lines are distinct and parallel. Check the constant term ratio also.

Step 3

Exam Tip

\(\frac{9}{3}=\frac{12}{4}\neq\frac{45}{20}\), इसलिए रेखाएं समांतर अलग-अलग हैं। अनुपातों में स्थिर पद को भी देखें।

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Question 5/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

किस मान पर (8x+3y=27) और (16x+6y=k) का कोई समाधान नहीं होगा?

For which value will (8x+3y=27) and (16x+6y=k) have no solution?

Explanation opens after your attempt
Correct Answer

B. (k=50)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=54). For (k=50), the lines will be distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=50). The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=54). For (k=50), the lines will be distinct and parallel.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{2}\) है; संपाती होने के लिए (k=54) चाहिए। (k=50) पर रेखाएं समांतर अलग-अलग होंगी।

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Question 6/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (7x-3y=18) और (14x-6y=41) के लिए कौन सा निष्कर्ष सही है?

Which conclusion is correct for (7x-3y=18) and (14x-6y=41)?

Explanation opens after your attempt
Correct Answer

B. असंगतInconsistent

Step 1

Concept

\(\frac{7}{14}=\frac{-3}{-6}\neq\frac{18}{41}\), so the lines are distinct and parallel. An inconsistent pair has no solution.

Step 2

Why this answer is correct

The correct answer is B. असंगत / Inconsistent. \(\frac{7}{14}=\frac{-3}{-6}\neq\frac{18}{41}\), so the lines are distinct and parallel. An inconsistent pair has no solution.

Step 3

Exam Tip

\(\frac{7}{14}=\frac{-3}{-6}\neq\frac{18}{41}\), इसलिए रेखाएं समांतर अलग-अलग हैं। असंगत युग्म का कोई समाधान नहीं होता।

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Question 7/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि दो रेखाओं की ढालें \(m_1=-\frac{7}{4}\) और \(m_2=-\frac{7}{4}\) हैं, लेकिन (y)-अवरोध अलग हैं, तो ग्राफीय निष्कर्ष क्या है?

If two lines have slopes \(m_1=-\frac{7}{4}\) and \(m_2=-\frac{7}{4}\), but different (y)-intercepts, what is the graphical conclusion?

Explanation opens after your attempt
Correct Answer

B. कोई समाधान नहींNo solution

Step 1

Concept

Lines with equal slopes and different (y)-intercepts are parallel. Therefore they have no intersection.

Step 2

Why this answer is correct

The correct answer is B. कोई समाधान नहीं / No solution. Lines with equal slopes and different (y)-intercepts are parallel. Therefore they have no intersection.

Step 3

Exam Tip

समान ढाल और अलग (y)-अवरोध वाली रेखाएं समांतर होती हैं। इसलिए उनका कोई प्रतिच्छेद नहीं होता।

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Question 8/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (4x+9y=36) और (8x+18y=75) ग्राफ पर कैसी होंगी?

How will the lines (4x+9y=36) and (8x+18y=75) appear on a graph?

Explanation opens after your attempt
Correct Answer

A. समांतर अलग-अलगDistinct parallel

Step 1

Concept

\(\frac{4}{8}=\frac{9}{18}\neq\frac{36}{75}\), so the lines are distinct and parallel. Distinct parallel lines have no common point.

Step 2

Why this answer is correct

The correct answer is A. समांतर अलग-अलग / Distinct parallel. \(\frac{4}{8}=\frac{9}{18}\neq\frac{36}{75}\), so the lines are distinct and parallel. Distinct parallel lines have no common point.

Step 3

Exam Tip

\(\frac{4}{8}=\frac{9}{18}\neq\frac{36}{75}\), इसलिए रेखाएं समांतर अलग-अलग हैं। समांतर अलग-अलग रेखाओं का कोई साझी बिंदु नहीं होता।

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Question 9/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

यदि (7x+by=21) और (14x+10y=50) की रेखाएं समांतर अलग-अलग हों, तो (b) का मान क्या होगा?

If the lines (7x+by=21) and (14x+10y=50) are distinct parallel lines, what will be the value of (b)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

For parallel lines, \(\frac{7}{14}=\frac{b}{10}\), so (b=5). Since \(\frac{21}{50}\neq\frac{1}{2}\), the lines are not coincident.

Step 2

Why this answer is correct

The correct answer is B. (5). For parallel lines, \(\frac{7}{14}=\frac{b}{10}\), so (b=5). Since \(\frac{21}{50}\neq\frac{1}{2}\), the lines are not coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{7}{14}=\frac{b}{10}\), इसलिए (b=5)। क्योंकि \(\frac{21}{50}\neq\frac{1}{2}\), रेखाएं संपाती नहीं हैं।

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Question 10/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

रेखाएं (2x-5y=7) और (4x-10y=16) का ग्राफीय निष्कर्ष क्या है?

What is the graphical conclusion for (2x-5y=7) and (4x-10y=16)?

Explanation opens after your attempt
Correct Answer

C. कोई समाधान नहींNo solution

Step 1

Concept

\(\frac{2}{4}=\frac{-5}{-10}\neq\frac{7}{16}\), so the lines are distinct and parallel. Such a pair has no solution.

Step 2

Why this answer is correct

The correct answer is C. कोई समाधान नहीं / No solution. \(\frac{2}{4}=\frac{-5}{-10}\neq\frac{7}{16}\), so the lines are distinct and parallel. Such a pair has no solution.

Step 3

Exam Tip

\(\frac{2}{4}=\frac{-5}{-10}\neq\frac{7}{16}\), इसलिए रेखाएं समांतर अलग-अलग हैं। ऐसे युग्म का कोई समाधान नहीं होता।

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Question 11/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

रेखाएं (5x+10y=25) और (x+2y=6) का ग्राफ कैसा होगा?

What will be the graph of (5x+10y=25) and (x+2y=6)?

Explanation opens after your attempt
Correct Answer

C. समांतर अलग-अलगDistinct parallel

Step 1

Concept

\(\frac{5}{1}=\frac{10}{2}\neq\frac{25}{6}\), so the lines are distinct and parallel. Check the constant term ratio also.

Step 2

Why this answer is correct

The correct answer is C. समांतर अलग-अलग / Distinct parallel. \(\frac{5}{1}=\frac{10}{2}\neq\frac{25}{6}\), so the lines are distinct and parallel. Check the constant term ratio also.

Step 3

Exam Tip

\(\frac{5}{1}=\frac{10}{2}\neq\frac{25}{6}\), इसलिए रेखाएं समांतर अलग-अलग हैं। अनुपातों में स्थिर पद को भी देखें।

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Question 12/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

किस मान पर (6x+y=17) और (12x+2y=k) का कोई समाधान नहीं होगा?

For which value will (6x+y=17) and (12x+2y=k) have no solution?

Explanation opens after your attempt
Correct Answer

B. (k=30)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=34). For (k=30), the lines will be distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=30). The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=34). For (k=30), the lines will be distinct and parallel.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{2}\) है; संपाती होने के लिए (k=34) चाहिए। (k=30) पर रेखाएं समांतर अलग-अलग होंगी।

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Question 13/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

रेखाएं (5x-2y=9) और (10x-4y=23) के लिए कौन सा निष्कर्ष सही है?

Which conclusion is correct for (5x-2y=9) and (10x-4y=23)?

Explanation opens after your attempt
Correct Answer

B. असंगतInconsistent

Step 1

Concept

\(\frac{5}{10}=\frac{-2}{-4}\neq\frac{9}{23}\), so the lines are distinct and parallel. An inconsistent pair has no solution.

Step 2

Why this answer is correct

The correct answer is B. असंगत / Inconsistent. \(\frac{5}{10}=\frac{-2}{-4}\neq\frac{9}{23}\), so the lines are distinct and parallel. An inconsistent pair has no solution.

Step 3

Exam Tip

\(\frac{5}{10}=\frac{-2}{-4}\neq\frac{9}{23}\), इसलिए रेखाएं समांतर अलग-अलग हैं। असंगत युग्म का कोई समाधान नहीं होता।

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Question 14/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

यदि दो रेखाओं की ढालें \(m_1=\frac{5}{2}\) और \(m_2=\frac{5}{2}\) हैं, लेकिन (y)-अवरोध अलग हैं, तो ग्राफीय निष्कर्ष क्या है?

If two lines have slopes \(m_1=\frac{5}{2}\) and \(m_2=\frac{5}{2}\), but different (y)-intercepts, what is the graphical conclusion?

Explanation opens after your attempt
Correct Answer

B. कोई समाधान नहींNo solution

Step 1

Concept

Lines with equal slopes and different (y)-intercepts are parallel. Therefore they have no intersection.

Step 2

Why this answer is correct

The correct answer is B. कोई समाधान नहीं / No solution. Lines with equal slopes and different (y)-intercepts are parallel. Therefore they have no intersection.

Step 3

Exam Tip

समान ढाल और अलग (y)-अवरोध वाली रेखाएं समांतर होती हैं। इसलिए उनका कोई प्रतिच्छेद नहीं होता।

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Question 15/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

ग्राफीय विधि में असंगत युग्म की पहचान कैसे होती है?

How is an inconsistent pair identified in the graphical method?

Explanation opens after your attempt
Correct Answer

C. रेखाएं समांतर अलग-अलग होती हैंThe lines are distinct and parallel

Step 1

Concept

An inconsistent pair has no common point, so the lines are distinct and parallel. This is the no-solution case.

Step 2

Why this answer is correct

The correct answer is C. रेखाएं समांतर अलग-अलग होती हैं / The lines are distinct and parallel. An inconsistent pair has no common point, so the lines are distinct and parallel. This is the no-solution case.

Step 3

Exam Tip

असंगत युग्म में कोई साझी बिंदु नहीं होता, इसलिए रेखाएं समांतर अलग-अलग होती हैं। यह कोई समाधान नहीं वाली स्थिति है।

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Question 16/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

ग्राफ में रेखाएं (2x+7y=14) और (4x+14y=31) कैसी होंगी?

How will the lines (2x+7y=14) and (4x+14y=31) appear on a graph?

Explanation opens after your attempt
Correct Answer

A. समांतर अलग-अलगDistinct parallel

Step 1

Concept

\(\frac{2}{4}=\frac{7}{14}\neq\frac{14}{31}\), so the lines are distinct and parallel. Such a graph has no common point.

Step 2

Why this answer is correct

The correct answer is A. समांतर अलग-अलग / Distinct parallel. \(\frac{2}{4}=\frac{7}{14}\neq\frac{14}{31}\), so the lines are distinct and parallel. Such a graph has no common point.

Step 3

Exam Tip

\(\frac{2}{4}=\frac{7}{14}\neq\frac{14}{31}\), इसलिए रेखाएं समांतर अलग-अलग हैं। ऐसे ग्राफ में कोई साझी बिंदु नहीं होता।

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Question 17/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

रेखाएं (x-3y=2) और (2x-6y=9) का ग्राफीय निष्कर्ष क्या है?

What is the graphical conclusion for (x-3y=2) and (2x-6y=9)?

Explanation opens after your attempt
Correct Answer

C. कोई समाधान नहींNo solution

Step 1

Concept

\(\frac{1}{2}=\frac{-3}{-6}\neq\frac{2}{9}\), so the lines are distinct and parallel. Such a pair has no solution.

Step 2

Why this answer is correct

The correct answer is C. कोई समाधान नहीं / No solution. \(\frac{1}{2}=\frac{-3}{-6}\neq\frac{2}{9}\), so the lines are distinct and parallel. Such a pair has no solution.

Step 3

Exam Tip

\(\frac{1}{2}=\frac{-3}{-6}\neq\frac{2}{9}\), इसलिए रेखाएं समांतर अलग-अलग हैं। ऐसे युग्म का कोई समाधान नहीं होता।

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Question 18/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

किस युग्म में दोनों रेखाओं की ढाल समान है लेकिन (y)-अवरोध अलग है?

In which pair do both lines have equal slopes but different (y)-intercepts?

Explanation opens after your attempt
Correct Answer

A. (y=2x+5), (y=2x-3)

Step 1

Concept

Both have slope (2), but intercepts (5) and (-3) are different. Hence they are distinct parallel lines.

Step 2

Why this answer is correct

The correct answer is A. (y=2x+5), (y=2x-3). Both have slope (2), but intercepts (5) and (-3) are different. Hence they are distinct parallel lines.

Step 3

Exam Tip

दोनों में ढाल (2) है लेकिन अवरोध (5) और (-3) अलग हैं। इसलिए ये समांतर अलग-अलग रेखाएं हैं।

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Question 19/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

रेखाएं (4x+6y=18) और (2x+3y=10) का ग्राफ कैसा होगा?

What will be the graph of (4x+6y=18) and (2x+3y=10)?

Explanation opens after your attempt
Correct Answer

C. समांतर अलग-अलगDistinct parallel

Step 1

Concept

\(\frac{4}{2}=\frac{6}{3}\neq\frac{18}{10}\), so the lines are distinct and parallel. Do not ignore the constant ratio.

Step 2

Why this answer is correct

The correct answer is C. समांतर अलग-अलग / Distinct parallel. \(\frac{4}{2}=\frac{6}{3}\neq\frac{18}{10}\), so the lines are distinct and parallel. Do not ignore the constant ratio.

Step 3

Exam Tip

\(\frac{4}{2}=\frac{6}{3}\neq\frac{18}{10}\), इसलिए रेखाएं समांतर अलग-अलग हैं। अनुपातों में स्थिर पद को नजरअंदाज न करें।

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Question 20/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

किस मान पर (5x+2y=13) और (10x+4y=k) का कोई समाधान नहीं होगा?

For which value will (5x+2y=13) and (10x+4y=k) have no solution?

Explanation opens after your attempt
Correct Answer

B. (k=13)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=26). For (k=13), the lines are distinct and parallel, so there is no solution.

Step 2

Why this answer is correct

The correct answer is B. (k=13). The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=26). For (k=13), the lines are distinct and parallel, so there is no solution.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{2}\) है; संपाती के लिए (k=26) चाहिए। (k=13) पर रेखाएं समांतर अलग-अलग हैं, इसलिए कोई समाधान नहीं।

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Question 21/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

रेखाएं (3x-y=2) और (6x-2y=5) के लिए कौन सा निष्कर्ष सही है?

Which conclusion is correct for the lines (3x-y=2) and (6x-2y=5)?

Explanation opens after your attempt
Correct Answer

B. असंगतInconsistent

Step 1

Concept

\(\frac{3}{6}=\frac{-1}{-2}\neq\frac{2}{5}\), so the lines are distinct and parallel. An inconsistent pair has no solution.

Step 2

Why this answer is correct

The correct answer is B. असंगत / Inconsistent. \(\frac{3}{6}=\frac{-1}{-2}\neq\frac{2}{5}\), so the lines are distinct and parallel. An inconsistent pair has no solution.

Step 3

Exam Tip

\(\frac{3}{6}=\frac{-1}{-2}\neq\frac{2}{5}\), इसलिए रेखाएं समांतर अलग-अलग हैं। असंगत युग्म का कोई समाधान नहीं होता।

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Question 22/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

यदि दो रेखाओं की ढालें \(m_1=-\frac{4}{3}\) और \(m_2=-\frac{4}{3}\) हैं, लेकिन (y)-अवरोध अलग हैं, तो ग्राफीय निष्कर्ष क्या है?

If two lines have slopes \(m_1=-\frac{4}{3}\) and \(m_2=-\frac{4}{3}\), but different (y)-intercepts, what is the graphical conclusion?

Explanation opens after your attempt
Correct Answer

B. कोई समाधान नहींNo solution

Step 1

Concept

Lines with equal slopes and different (y)-intercepts are parallel. Therefore they have no intersection.

Step 2

Why this answer is correct

The correct answer is B. कोई समाधान नहीं / No solution. Lines with equal slopes and different (y)-intercepts are parallel. Therefore they have no intersection.

Step 3

Exam Tip

समान ढाल और अलग (y)-अवरोध वाली रेखाएं समांतर होती हैं। इसलिए उनका कोई प्रतिच्छेद नहीं होता।

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Question 23/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

यदि \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\), तो ग्राफ में रेखाओं की स्थिति क्या होगी?

If \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\), what will be the position of the lines on a graph?

Explanation opens after your attempt
Correct Answer

C. समांतर अलग-अलगDistinct parallel

Step 1

Concept

The coefficient ratios of (x) and (y) are equal, but the constant ratio is different. Hence the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is C. समांतर अलग-अलग / Distinct parallel. The coefficient ratios of (x) and (y) are equal, but the constant ratio is different. Hence the lines are distinct and parallel.

Step 3

Exam Tip

(x) और (y) के गुणांक अनुपात बराबर हैं लेकिन स्थिर पद का अनुपात अलग है। इसलिए रेखाएं समांतर अलग-अलग होती हैं।

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Question 24/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

किस स्थिति में ग्राफीय विधि से कोई समाधान नहीं मिलेगा?

In which condition will the graphical method give no solution?

Explanation opens after your attempt
Correct Answer

C. रेखाएं समांतर अलग-अलग होंThe lines are distinct and parallel

Step 1

Concept

Distinct parallel lines have no common point. If there is no common point on the graph, there is no solution.

Step 2

Why this answer is correct

The correct answer is C. रेखाएं समांतर अलग-अलग हों / The lines are distinct and parallel. Distinct parallel lines have no common point. If there is no common point on the graph, there is no solution.

Step 3

Exam Tip

समांतर अलग-अलग रेखाओं में कोई साझी बिंदु नहीं होता। ग्राफ में साझी बिंदु न होने पर कोई समाधान नहीं होता।

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Question 25/79 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

ग्राफ पर रेखाएं (3x+5y=15) और (6x+10y=32) कैसी स्थिति देंगी?

What situation will the lines (3x+5y=15) and (6x+10y=32) give on a graph?

Explanation opens after your attempt
Correct Answer

B. समांतर अलग-अलग रेखाएंDistinct parallel lines

Step 1

Concept

\(\frac{3}{6}=\frac{5}{10}\neq\frac{15}{32}\), so the lines are distinct and parallel. In exams, compare all three ratios first.

Step 2

Why this answer is correct

The correct answer is B. समांतर अलग-अलग रेखाएं / Distinct parallel lines. \(\frac{3}{6}=\frac{5}{10}\neq\frac{15}{32}\), so the lines are distinct and parallel. In exams, compare all three ratios first.

Step 3

Exam Tip

\(\frac{3}{6}=\frac{5}{10}\neq\frac{15}{32}\), इसलिए रेखाएं समांतर अलग-अलग हैं। परीक्षा में तीनों अनुपातों की तुलना पहले करें।

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Question 26/79 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (2x-3y=6) और (4x-6y=13) के लिए सही ग्राफीय निष्कर्ष कौन सा है?

Which graphical conclusion is correct for (2x-3y=6) and (4x-6y=13)?

Explanation opens after your attempt
Correct Answer

B. कोई समाधान नहींNo solution

Step 1

Concept

\(\frac{2}{4}=\frac{-3}{-6}\neq\frac{6}{13}\), so the lines are parallel. Distinct parallel lines have no intersection.

Step 2

Why this answer is correct

The correct answer is B. कोई समाधान नहीं / No solution. \(\frac{2}{4}=\frac{-3}{-6}\neq\frac{6}{13}\), so the lines are parallel. Distinct parallel lines have no intersection.

Step 3

Exam Tip

\(\frac{2}{4}=\frac{-3}{-6}\neq\frac{6}{13}\), इसलिए रेखाएं समांतर हैं। समांतर अलग-अलग रेखाओं का कोई प्रतिच्छेद नहीं होता।

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Question 27/79 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (x+4y=9) और (2x+8y=21) के लिए ग्राफीय निष्कर्ष क्या है?

What is the graphical conclusion for the lines (x+4y=9) and (2x+8y=21)?

Explanation opens after your attempt
Correct Answer

B. कोई समाधान नहींNo solution

Step 1

Concept

\(\frac{1}{2}=\frac{4}{8}\neq\frac{9}{21}\), so the lines are distinct parallel lines. Such lines have no solution.

Step 2

Why this answer is correct

The correct answer is B. कोई समाधान नहीं / No solution. \(\frac{1}{2}=\frac{4}{8}\neq\frac{9}{21}\), so the lines are distinct parallel lines. Such lines have no solution.

Step 3

Exam Tip

\(\frac{1}{2}=\frac{4}{8}\neq\frac{9}{21}\), इसलिए रेखाएं समांतर अलग-अलग हैं। ऐसी रेखाओं का कोई समाधान नहीं होता।

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Question 28/79 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

किस युग्म का ग्राफ निश्चित रूप से समांतर रेखाएं देगा?

Which pair will definitely give parallel lines on a graph?

Explanation opens after your attempt
Correct Answer

B. (x+2y=5), (2x+4y=9)

Step 1

Concept

In the option, \(\frac{1}{2}=\frac{2}{4}\neq\frac{5}{9}\), so the lines are parallel. Equal coefficient ratio and different constant ratio mean no solution.

Step 2

Why this answer is correct

The correct answer is B. (x+2y=5), (2x+4y=9). In the option, \(\frac{1}{2}=\frac{2}{4}\neq\frac{5}{9}\), so the lines are parallel. Equal coefficient ratio and different constant ratio mean no solution.

Step 3

Exam Tip

विकल्प में \(\frac{1}{2}=\frac{2}{4}\neq\frac{5}{9}\), इसलिए रेखाएं समांतर हैं। समान गुणांक अनुपात और अलग स्थिर अनुपात का अर्थ कोई समाधान नहीं है।

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Question 29/79 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (x+3y=6) और (2x+6y=15) के लिए कौन सा कथन सही है?

Which statement is correct for the lines (x+3y=6) and (2x+6y=15)?

Explanation opens after your attempt
Correct Answer

B. वे समांतर हैंThey are parallel

Step 1

Concept

\(\frac{1}{2}=\frac{3}{6}\neq\frac{6}{15}\), so the lines are parallel. Parallel lines never meet.

Step 2

Why this answer is correct

The correct answer is B. वे समांतर हैं / They are parallel. \(\frac{1}{2}=\frac{3}{6}\neq\frac{6}{15}\), so the lines are parallel. Parallel lines never meet.

Step 3

Exam Tip

\(\frac{1}{2}=\frac{3}{6}\neq\frac{6}{15}\), इसलिए रेखाएं समांतर हैं। समांतर रेखाएं कभी नहीं मिलतीं।

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Question 30/79 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाओं (5x+2y=10) और (10x+4y=25) का ग्राफ कैसा होगा?

What will be the graph of the lines (5x+2y=10) and (10x+4y=25)?

Explanation opens after your attempt
Correct Answer

B. समांतर रेखाएंParallel lines

Step 1

Concept

Here \(\frac{5}{10}=\frac{2}{4}\neq\frac{10}{25}\), so the lines are parallel. Parallel lines have no common point.

Step 2

Why this answer is correct

The correct answer is B. समांतर रेखाएं / Parallel lines. Here \(\frac{5}{10}=\frac{2}{4}\neq\frac{10}{25}\), so the lines are parallel. Parallel lines have no common point.

Step 3

Exam Tip

यहां \(\frac{5}{10}=\frac{2}{4}\neq\frac{10}{25}\), इसलिए रेखाएं समांतर होंगी। समांतर रेखाओं का कोई साझी बिंदु नहीं होता।

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