How many solutions will (9x-4y=17) and (18x-8y=39) have?
Answer and explanation
Correct answer: No solution
For the two equations, \(\frac{a_1}{a_2}=\frac{9}{18}=\frac{1}{2}\) and \(\frac{b_1}{b_2}=\frac{-4}{-8}=\frac{1}{2}\), but \(\frac{c_1}{c_2}=\frac{17}{39}\neq\frac{1}{2}\). Thus, \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\), so the lines are parallel and distinct and the pair has no solution. Exam tip: this ratio condition identifies inconsistent equations with zero solutions.
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What is the correct answer to this question?
No solution
Why is this the correct answer?
For the two equations, \(\frac{a_1}{a_2}=\frac{9}{18}=\frac{1}{2}\) and \(\frac{b_1}{b_2}=\frac{-4}{-8}=\frac{1}{2}\), but \(\frac{c_1}{c_2}=\frac{17}{39}\neq\frac{1}{2}\). Thus, \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\), so the lines are parallel and distinct and the pair has no solution. Exam tip: this ratio condition identifies inconsistent equations with zero solutions.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.
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