रेखाएँ (2x+5y=20) और (4x+10y=40) के लिए हलों की संख्या कितनी है?

How many solutions are there for (2x+5y=20) and (4x+10y=40)?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first. Therefore the lines are coincident and have infinitely many common points.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore the lines are coincident and have infinitely many common points.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए रेखाएँ संपाती हैं और उनके अनंत सामान्य बिंदु हैं।

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रेखाएँ (2x+5y=20) और (4x+10y=40) के लिए हलों की संख्या कितनी है? / How many solutions are there for (2x+5y=20) and (4x+10y=40)?

Correct Answer: C. अनंत हल / Infinitely many solutions. Explanation: दूसरा समीकरण पहले का (2) गुना है। इसलिए रेखाएँ संपाती हैं और उनके अनंत सामान्य बिंदु हैं। / The second equation is (2) times the first. Therefore the lines are coincident and have infinitely many common points.

Which concept should I revise for this Mathematics MCQ?

The second equation is (2) times the first. Therefore the lines are coincident and have infinitely many common points.

What exam hint can help solve this Mathematics question?

दूसरा समीकरण पहले का (2) गुना है। इसलिए रेखाएँ संपाती हैं और उनके अनंत सामान्य बिंदु हैं।