Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

What is the value of a for the pair of equations 3x + ay = 12 and 6x + 8y = 24 to have infinitely many solutions?

Advertisement

Answer and explanation

Correct answer: 4

For a pair of linear equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0, infinitely many solutions occur when a₁/a₂ = b₁/b₂ = c₁/c₂. Here the corresponding ratios are 3/6, a/8, and 12/24. Since 3/6 = 12/24 = 1/2, we must have a/8 = 1/2. Multiplying by 8 gives a = 4. Therefore, option B is correct. Option A, C, and D do not make all three ratios equal, so they would not represent coincident lines and cannot produce infinitely many common solutions.

Related tags

Linear EquationsInfinite SolutionsRatio ConditionConditions For SolvabilityPair Of Linear Equations In Two VariablesMathematicsClass 10 Mcq

Frequently asked questions

What is the correct answer to this question?

4

Why is this the correct answer?

For a pair of linear equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0, infinitely many solutions occur when a₁/a₂ = b₁/b₂ = c₁/c₂. Here the corresponding ratios are 3/6, a/8, and 12/24. Since 3/6 = 12/24 = 1/2, we must have a/8 = 1/2. Multiplying by 8 gives a = 4. Therefore, option B is correct. Option A, C, and D do not make all three ratios equal, so they would not represent coincident lines and cannot produce infinitely many common solutions.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement