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What will (k) be for (8x+ky=72) and (2x+7y=18) to have infinitely many solutions?

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Answer and explanation

Correct answer: 28

For two linear equations to have infinitely many solutions, the ratios of their corresponding coefficients and constant terms must be equal: 8/2 = k/7 = 72/18. Since 8/2 and 72/18 are both 4, k/7 = 4, giving k = 28. Therefore, option C is correct. In an exam, check the ratio of the constant terms as well as the variable coefficients.

Related tags

Linear EquationsInfinite SolutionsSolvability Conditions

Frequently asked questions

What is the correct answer to this question?

28

Why is this the correct answer?

For two linear equations to have infinitely many solutions, the ratios of their corresponding coefficients and constant terms must be equal: 8/2 = k/7 = 72/18. Since 8/2 and 72/18 are both 4, k/7 = 4, giving k = 28. Therefore, option C is correct. In an exam, check the ratio of the constant terms as well as the variable coefficients.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.

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