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real-solutions MCQ Questions for Class 10

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6 questions tagged with real-solutions.

Question 1/6 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^4-25x^2+144=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-25x^2+144=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm3,\pm4\)

Step 1

Concept

From \(y^2-25y+144=0\), (y=9,16), so \(x^2=9,16\) and \(x=\pm3,\pm4\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm3,\pm4\). From \(y^2-25y+144=0\), (y=9,16), so \(x^2=9,16\) and \(x=\pm3,\pm4\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-25y+144=0\) से (y=9,16), इसलिए \(x^2=9,16\) और \(x=\pm3,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question 2/6 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^4-20x^2+64=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-20x^2+64=0\)?

Explanation opens after your attempt
Correct Answer

B. \(x=\pm4,\pm2\)

Step 1

Concept

From \(y^2-20y+64=0\), (y=4,16), so \(x^2=4,16\) and \(x=\pm2,\pm4\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is B. \(x=\pm4,\pm2\). From \(y^2-20y+64=0\), (y=4,16), so \(x^2=4,16\) and \(x=\pm2,\pm4\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-20y+64=0\) से (y=4,16), इसलिए \(x^2=4,16\) और \(x=\pm2,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question 3/6 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^4-17x^2+16=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-17x^2+16=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm1,\pm4\)

Step 1

Concept

From \(y^2-17y+16=0\), (y=1,16), so \(x^2=1,16\) and \(x=\pm1,\pm4\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm1,\pm4\). From \(y^2-17y+16=0\), (y=1,16), so \(x^2=1,16\) and \(x=\pm1,\pm4\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-17y+16=0\) से (y=1,16), इसलिए \(x^2=1,16\) और \(x=\pm1,\pm4\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question 4/6 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^4-13x^2+36=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-13x^2+36=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm2,\pm3\)

Step 1

Concept

From \(y^2-13y+36=0\), (y=4,9), so \(x^2=4,9\) and \(x=\pm2,\pm3\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm2,\pm3\). From \(y^2-13y+36=0\), (y=4,9), so \(x^2=4,9\) and \(x=\pm2,\pm3\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-13y+36=0\) से (y=4,9), इसलिए \(x^2=4,9\) और \(x=\pm2,\pm3\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question 5/6 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^4-10x^2+9=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-10x^2+9=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm1,\pm3\)

Step 1

Concept

From \(y^2-10y+9=0\), (y=1,9), so \(x^2=1,9\) and \(x=\pm1,\pm3\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm1,\pm3\). From \(y^2-10y+9=0\), (y=1,9), so \(x^2=1,9\) and \(x=\pm1,\pm3\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-10y+9=0\) से (y=1,9), इसलिए \(x^2=1,9\) और \(x=\pm1,\pm3\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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Question 6/6 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^4-5x^2+4=0\) के वास्तविक हल कौनसे हैं?

What are the real solutions of \(x^4-5x^2+4=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm1,\pm2\)

Step 1

Concept

From \(y^2-5y+4=0\), (y=1,4), so \(x^2=1,4\) and \(x=\pm1,\pm2\). In exams, do not forget to return to (x).

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm1,\pm2\). From \(y^2-5y+4=0\), (y=1,4), so \(x^2=1,4\) and \(x=\pm1,\pm2\). In exams, do not forget to return to (x).

Step 3

Exam Tip

\(y^2-5y+4=0\) से (y=1,4), इसलिए \(x^2=1,4\) और \(x=\pm1,\pm2\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।

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