0 reads0 ratings0 helpful
What are the real solutions of (x^4-20x^2+64=0)?
Advertisement
Answer and explanation
Correct answer: (x=\pm4,\pm2)
From (y^2-20y+64=0), (y=4,16), so (x^2=4,16) and (x=\pm2,\pm4). In exams, do not forget to return to (x).
Frequently asked questions
What is the correct answer to this question?
(x=\pm4,\pm2)
Why is this the correct answer?
From (y^2-20y+64=0), (y=4,16), so (x^2=4,16) and (x=\pm2,\pm4). In exams, do not forget to return to (x).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement