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Class 10 Mathematics Quadratic Equations Methods of Solving Quadratic EquationsExpert

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What are the real solutions of (x^4-25x^2+144=0)?

Answer and explanation

Correct answer: (x=\pm3,\pm4)

From (y^2-25y+144=0), (y=9,16), so (x^2=9,16) and (x=\pm3,\pm4). In exams, do not forget to return to (x).

Related tags

Quadratic Substitution Real-Solutions Methods Of Solving Quadratic Equations Quadratic Equations Mathematics Class 10 Mcq

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