समीकरण (px+3y=15) और (12x+6y=30) के अनंत हल होने के लिए (p) क्या होगा?

What will (p) be for (px+3y=15) and (12x+6y=30) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).

Step 2

Why this answer is correct

The correct answer is C. (6). For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).

Step 3

Exam Tip

अनंत हल के लिए (p/12=3/6=15/30) होना चाहिए। इसलिए (p=6) है।

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समीकरण (px+3y=15) और (12x+6y=30) के अनंत हल होने के लिए (p) क्या होगा? / What will (p) be for (px+3y=15) and (12x+6y=30) to have infinitely many solutions?

Correct Answer: C. (6). Explanation: अनंत हल के लिए (p/12=3/6=15/30) होना चाहिए। इसलिए (p=6) है। / For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).

Which concept should I revise for this Mathematics MCQ?

For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).

What exam hint can help solve this Mathematics question?

अनंत हल के लिए (p/12=3/6=15/30) होना चाहिए। इसलिए (p=6) है।