Which of the following options contains only real numbers?
Answer and explanation
Correct answer: \(-3, 0, \sqrt{2}\)
Real numbers have no imaginary part. In option A, -3 (integer), 0 and \(\sqrt{2}\) (irrational) are all real. Option B contains \(\sqrt{-1}=i\), which is imaginary; option C has \(\sqrt{-9}=3i\), imaginary; option D contains \(\sqrt{3}\) (real) but also \(\sqrt{-16}=4i\), so it is not all real. Thus A is the only choice with only real numbers. Exam tip: if you see \(\sqrt{\text{negative}}\) immediately mark it as non-real (imaginary).
Frequently asked questions
What is the correct answer to this question?
\(-3, 0, \sqrt{2}\)
Why is this the correct answer?
Real numbers have no imaginary part. In option A, -3 (integer), 0 and \(\sqrt{2}\) (irrational) are all real. Option B contains \(\sqrt{-1}=i\), which is imaginary; option C has \(\sqrt{-9}=3i\), imaginary; option D contains \(\sqrt{3}\) (real) but also \(\sqrt{-16}=4i\), so it is not all real. Thus A is the only choice with only real numbers. Exam tip: if you see \(\sqrt{\text{negative}}\) immediately mark it as non-real (imaginary).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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