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2 results found for "addition of surds" in Class 10.

Question Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 15

कौन-सा विकल्प \(\sqrt{75}\) और \(\sqrt{27}\) के योग को सही बताता है?

Which option correctly gives the sum of \(\sqrt{75}\) and \(\sqrt{27}\)?

Explanation opens after your attempt
Correct Answer

A. \(8\sqrt{3}\)

Step 1

Concept

\(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\).

Step 2

Why this answer is correct

The sum is \(5\sqrt{3}+3\sqrt{3}=8\sqrt{3}\).

Step 3

Exam Tip

Do not combine separate square roots directly into one root. चरण 1: \(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\)। चरण 2: योग \(5\sqrt{3}+3\sqrt{3}=8\sqrt{3}\) है। चरण 3: अलग-अलग मूलों को सीधे जोड़कर एक मूल न बनाएं।

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Question Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

कौन-सी संख्या \(\sqrt{27}+\sqrt{12}\) का सरल रूप है?

Which number is the simplified form of \(\sqrt{27}+\sqrt{12}\)?

Explanation opens after your attempt
Correct Answer

A. \(5\sqrt{3}\)

Step 1

Concept

\(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\).

Step 2

Why this answer is correct

The sum is \(3\sqrt{3}+2\sqrt{3}=5\sqrt{3}\), which is irrational.

Step 3

Exam Tip

Do not combine separate square roots as \(\sqrt{39}\). चरण 1: \(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\)। चरण 2: योग \(3\sqrt{3}+2\sqrt{3}=5\sqrt{3}\), जो अपरिमेय है। चरण 3: अलग-अलग मूलों को सीधे जोड़कर \(\sqrt{39}\) न लिखें।

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