यदि \(r=\sqrt{15}+\sqrt{6}\), तो \(r^{2}-6\sqrt{10}\) का मान क्या है?
If \(r=\sqrt{15}+\sqrt{6}\), what is the value of \(r^{2}-6\sqrt{10}\)?
Explanation opens after your attempt
Correct Answer
C. (21)
Concept
Since \(r^{2}=15+6+2\sqrt{90}=21+6\sqrt{10}\), \(r^{2}-6\sqrt{10}=21\).
Why this answer is correct
The correct answer is C. (21). Since \(r^{2}=15+6+2\sqrt{90}=21+6\sqrt{10}\), \(r^{2}-6\sqrt{10}=21\).
Exam Tip
\(r^{2}=15+6+2\sqrt{90}=21+6\sqrt{10}\)। इसलिए \(r^{2}-6\sqrt{10}=21\)।
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