Concept-wise Practice

addition of surds MCQ Questions for Class 10

addition of surds se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with addition of surds.

कौन-सा विकल्प \(\sqrt{75}\) और \(\sqrt{27}\) के योग को सही बताता है?

Which option correctly gives the sum of \(\sqrt{75}\) and \(\sqrt{27}\)?

Explanation opens after your attempt
Correct Answer

A. \(8\sqrt{3}\)

Step 1

Concept

\(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\).

Step 2

Why this answer is correct

The sum is \(5\sqrt{3}+3\sqrt{3}=8\sqrt{3}\).

Step 3

Exam Tip

Do not combine separate square roots directly into one root. चरण 1: \(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\)। चरण 2: योग \(5\sqrt{3}+3\sqrt{3}=8\sqrt{3}\) है। चरण 3: अलग-अलग मूलों को सीधे जोड़कर एक मूल न बनाएं।

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कौन-सी संख्या \(\sqrt{27}+\sqrt{12}\) का सरल रूप है?

Which number is the simplified form of \(\sqrt{27}+\sqrt{12}\)?

Explanation opens after your attempt
Correct Answer

A. \(5\sqrt{3}\)

Step 1

Concept

\(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\).

Step 2

Why this answer is correct

The sum is \(3\sqrt{3}+2\sqrt{3}=5\sqrt{3}\), which is irrational.

Step 3

Exam Tip

Do not combine separate square roots as \(\sqrt{39}\). चरण 1: \(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\)। चरण 2: योग \(3\sqrt{3}+2\sqrt{3}=5\sqrt{3}\), जो अपरिमेय है। चरण 3: अलग-अलग मूलों को सीधे जोड़कर \(\sqrt{39}\) न लिखें।

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