किस विकल्प में (\(3\sqrt{5}-2\sqrt{7}\)^{2}) का सही विस्तार है?

Which option gives the correct expansion of (\(3\sqrt{5}-2\sqrt{7}\)^{2})?

Explanation opens after your attempt
Correct Answer

A. \(73-12\sqrt{35}\)

Step 1

Concept

Here (\(3\sqrt{5}\)^{2}=45), (\(2\sqrt{7}\)^{2}=28), and the middle term is \(12\sqrt{35}\). Therefore, the expansion is \(73-12\sqrt{35}\).

Step 2

Why this answer is correct

The correct answer is A. \(73-12\sqrt{35}\). Here (\(3\sqrt{5}\)^{2}=45), (\(2\sqrt{7}\)^{2}=28), and the middle term is \(12\sqrt{35}\). Therefore, the expansion is \(73-12\sqrt{35}\).

Step 3

Exam Tip

(\(3\sqrt{5}\)^{2}=45), (\(2\sqrt{7}\)^{2}=28), और मध्य पद \(12\sqrt{35}\) है। इसलिए विस्तार \(73-12\sqrt{35}\) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

किस विकल्प में (\(3\sqrt{5}-2\sqrt{7}\)^{2}) का सही विस्तार है? / Which option gives the correct expansion of (\(3\sqrt{5}-2\sqrt{7}\)^{2})?

Correct Answer: A. \(73-12\sqrt{35}\). Explanation: (\(3\sqrt{5}\)^{2}=45), (\(2\sqrt{7}\)^{2}=28), और मध्य पद \(12\sqrt{35}\) है। इसलिए विस्तार \(73-12\sqrt{35}\) है। / Here (\(3\sqrt{5}\)^{2}=45), (\(2\sqrt{7}\)^{2}=28), and the middle term is \(12\sqrt{35}\). Therefore, the expansion is \(73-12\sqrt{35}\).

Which concept should I revise for this Mathematics MCQ?

Here (\(3\sqrt{5}\)^{2}=45), (\(2\sqrt{7}\)^{2}=28), and the middle term is \(12\sqrt{35}\). Therefore, the expansion is \(73-12\sqrt{35}\).

What exam hint can help solve this Mathematics question?

(\(3\sqrt{5}\)^{2}=45), (\(2\sqrt{7}\)^{2}=28), और मध्य पद \(12\sqrt{35}\) है। इसलिए विस्तार \(73-12\sqrt{35}\) है।