\(\sqrt{75}+\sqrt{12}\) किसके बराबर है और उसका प्रकार क्या है?
What is \(\sqrt{75}+\sqrt{12}\) equal to and what is its type?
Explanation opens after your attempt
Correct Answer
A. \(7\sqrt{3}\) और अपरिमेय\(7\sqrt{3}\) and irrational
Concept
\(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\).
Why this answer is correct
The sum is \(7\sqrt{3}\) which is irrational.
Exam Tip
Simplify radicals before adding them. चरण 1: \(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\)। चरण 2: योग \(7\sqrt{3}\) है जो अपरिमेय है। चरण 3: अलग-अलग वर्गमूलों को जोड़ने से पहले सरल रूप में बदलें।
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