0 reads0 ratings0 helpful
What is (\sqrt{75}+\sqrt{12}) equal to and what is its type?(\sqrt{75}+\sqrt{12}) किसके बराबर है और उसका प्रकार क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (7\sqrt{3}) and irrational(7\sqrt{3}) और अपरिमेय
Step 1: (\sqrt{75}=5\sqrt{3}) and (\sqrt{12}=2\sqrt{3}). Step 2: The sum is (7\sqrt{3}) which is irrational. Step 3: Simplify radicals before adding them.चरण 1: (\sqrt{75}=5\sqrt{3}) और (\sqrt{12}=2\sqrt{3})। चरण 2: योग (7\sqrt{3}) है जो अपरिमेय है। चरण 3: अलग-अलग वर्गमूलों को जोड़ने से पहले सरल रूप में बदलें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
