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If (u=\sqrt{17}+\sqrt{8}) and (v=\sqrt{17}-\sqrt{8}), what is the value of (\frac{u^{2}-v^{2}}{uv})?यदि (u=\sqrt{17}+\sqrt{8}) और (v=\sqrt{17}-\sqrt{8}), तो (\frac{u^{2}-v^{2}}{uv}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{8\sqrt{34}}{9})(\frac{8\sqrt{34}}{9})
Here (u^{2}-v^{2}=(u-v)(u+v)=2\sqrt{8}\cdot2\sqrt{17}=8\sqrt{34}), and (uv=9). Hence the value is (\frac{8\sqrt{34}}{9}).(u^{2}-v^{2}=(u-v)(u+v)=2\sqrt{8}\cdot2\sqrt{17}=8\sqrt{34}) और (uv=9) है। इसलिए मान (\frac{8\sqrt{34}}{9}) है।
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