If (s=2+\sqrt{7}), what is the value of (s^{2}-\frac{1}{s^{2}})?यदि (s=2+\sqrt{7}), तो (s^{2}-\frac{1}{s^{2}}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (8\sqrt{7})(8\sqrt{7})
Here (\frac{1}{s}=\sqrt{7}-2), so (s-\frac{1}{s}=4) and (s+\frac{1}{s}=2\sqrt{7}). Thus (s^{2}-\frac{1}{s^{2}}=8\sqrt{7}).(\frac{1}{s}=\sqrt{7}-2), इसलिए (s-\frac{1}{s}=4) और (s+\frac{1}{s}=2\sqrt{7})। अतः (s^{2}-\frac{1}{s^{2}}=8\sqrt{7})।
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