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What is the simplified form of (\sqrt{98}-\sqrt{72}+\sqrt{32}-\sqrt{18})?(\sqrt{98}-\sqrt{72}+\sqrt{32}-\sqrt{18}) का सरल रूप क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (2\sqrt{2})(2\sqrt{2})
We have (\sqrt{98}=7\sqrt{2}), (\sqrt{72}=6\sqrt{2}), (\sqrt{32}=4\sqrt{2}), and (\sqrt{18}=3\sqrt{2}), so the value is (2\sqrt{2}). In exams, combine only like radicals.(\sqrt{98}=7\sqrt{2}), (\sqrt{72}=6\sqrt{2}), (\sqrt{32}=4\sqrt{2}), और (\sqrt{18}=3\sqrt{2}), इसलिए मान (2\sqrt{2}) है। परीक्षा में समान करणी पदों को ही जोड़ें।
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