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If (s=4+\sqrt{17}), what is the value of (s^{2}-\frac{1}{s^{2}})?यदि (s=4+\sqrt{17}), तो (s^{2}-\frac{1}{s^{2}}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (16\sqrt{17})(16\sqrt{17})
Here (\frac{1}{s}=\sqrt{17}-4), so (s-\frac{1}{s}=8) and (s+\frac{1}{s}=2\sqrt{17}). Thus (s^{2}-\frac{1}{s^{2}}=16\sqrt{17}).(\frac{1}{s}=\sqrt{17}-4), इसलिए (s-\frac{1}{s}=8) और (s+\frac{1}{s}=2\sqrt{17})। अतः (s^{2}-\frac{1}{s^{2}}=16\sqrt{17})।
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