If (x=\sqrt{5}-\sqrt{2}), what is the value of (x^{2}+2\sqrt{10})?यदि (x=\sqrt{5}-\sqrt{2}), तो (x^{2}+2\sqrt{10}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (7)(7)
Since (x^{2}=5+2-2\sqrt{10}=7-2\sqrt{10}), (x^{2}+2\sqrt{10}=7). In exams, write the middle term of ((a-b)^{2}) carefully.(x^{2}=5+2-2\sqrt{10}=7-2\sqrt{10}), इसलिए (x^{2}+2\sqrt{10}=7)। परीक्षा में ((a-b)^{2}) का मध्य पद ध्यान से लिखें।
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