A. यह \(6\sqrt{2}\) है और अपरिमेय है/It is \(6\sqrt{2}\) and irrational
Step 1
Concept
\(\sqrt{32}=4\sqrt{2}\), \(\sqrt{50}=5\sqrt{2}\), and \(\sqrt{18}=3\sqrt{2}\).
Step 2
Why this answer is correct
The result is \(6\sqrt{2}\) which is irrational.
Step 3
Exam Tip
Add and subtract coefficients of like radicals. चरण 1: \(\sqrt{32}=4\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\)। चरण 2: परिणाम \(6\sqrt{2}\) है जो अपरिमेय है। चरण 3: समान मूल वाले पदों के गुणांक जोड़ें और घटाएं।
\(\sqrt{80}=4\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), and \(\sqrt{20}=2\sqrt{5}\).
Step 2
Why this answer is correct
\(4\sqrt{5}-3\sqrt{5}+2\sqrt{5}=3\sqrt{5}\), which is irrational.
Step 3
Exam Tip
Handle the signs carefully when three terms are involved. चरण 1: \(\sqrt{80}=4\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), और \(\sqrt{20}=2\sqrt{5}\)। चरण 2: \(4\sqrt{5}-3\sqrt{5}+2\sqrt{5}=3\sqrt{5}\), जो अपरिमेय है। चरण 3: तीन पदों में चिह्नों को ध्यान से संभालें।
\(\sqrt{45}=3\sqrt{5}\) and \(\sqrt{20}=2\sqrt{5}\).
Step 2
Why this answer is correct
\(\sqrt{5}+3\sqrt{5}-2\sqrt{5}=2\sqrt{5}\).
Step 3
Exam Tip
In questions with many radicals, first convert all terms to like surds when possible. चरण 1: \(\sqrt{45}=3\sqrt{5}\) और \(\sqrt{20}=2\sqrt{5}\)। चरण 2: \(\sqrt{5}+3\sqrt{5}-2\sqrt{5}=2\sqrt{5}\)। चरण 3: कई मूलों वाले प्रश्न में पहले सभी पदों को समान मूल में बदलें।
