Concept-wise Practice

surd simplification MCQ Questions for Class 10

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Practice Questions

11 questions tagged with surd simplification.

Question 1/11 Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

कौन-सा विकल्प \(\sqrt{96}-\sqrt{54}+\sqrt{24}\) का सही सरल रूप है?

Which option is the correct simplified form of \(\sqrt{96}-\sqrt{54}+\sqrt{24}\)?

Explanation opens after your attempt
Correct Answer

A. \(5\sqrt{6}\)

Step 1

Concept

\(\sqrt{96}=4\sqrt{6}\), \(\sqrt{54}=3\sqrt{6}\), and \(\sqrt{24}=2\sqrt{6}\).

Step 2

Why this answer is correct

\(4\sqrt{6}-3\sqrt{6}+2\sqrt{6}=3\sqrt{6}\), so the correct value is \(3\sqrt{6}\).

Step 3

Exam Tip

Match the options with your simplified result carefully. चरण 1: \(\sqrt{96}=4\sqrt{6}\), \(\sqrt{54}=3\sqrt{6}\), और \(\sqrt{24}=2\sqrt{6}\)। चरण 2: \(4\sqrt{6}-3\sqrt{6}+2\sqrt{6}=3\sqrt{6}\), इसलिए सही मान \(3\sqrt{6}\) है। चरण 3: विकल्प मिलाते समय अपनी सरल गणना से मिलान करें।

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Question 2/11 Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

यदि \(x=\sqrt{8}+\sqrt{18}\), तो \(\frac{x}{\sqrt{2}}\) का मान क्या है?

If \(x=\sqrt{8}+\sqrt{18}\), what is the value of \(\frac{x}{\sqrt{2}}\)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

\(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\).

Step 2

Why this answer is correct

\(x=5\sqrt{2}\), so \(\frac{x}{\sqrt{2}}=5\).

Step 3

Exam Tip

Division is easier after combining like surds. चरण 1: \(\sqrt{8}=2\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\)। चरण 2: \(x=5\sqrt{2}\), इसलिए \(\frac{x}{\sqrt{2}}=5\)। चरण 3: समान मूल वाले पदों को जोड़ने के बाद भाग देना आसान होता है।

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Question 3/11 Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

कौन-सा विकल्प \(\frac{\sqrt{12}+\sqrt{27}}{\sqrt{3}}\) का सही मान देता है?

Which option gives the correct value of \(\frac{\sqrt{12}+\sqrt{27}}{\sqrt{3}}\)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

Write \(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\).

Step 2

Why this answer is correct

The numerator is \(5\sqrt{3}\), so \(\frac{5\sqrt{3}}{\sqrt{3}}=5\).

Step 3

Exam Tip

Combine like surds before division. चरण 1: \(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\) लिखें। चरण 2: ऊपर का योग \(5\sqrt{3}\) है, इसलिए \(\frac{5\sqrt{3}}{\sqrt{3}}=5\)। चरण 3: भाग से पहले समान मूल वाले पदों को जोड़ें।

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Question 4/11 Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 13

कौन-सा विकल्प \(\sqrt{48}+\sqrt{75}-\sqrt{27}\) को सरल करके देता है?

Which option gives the simplified form of \(\sqrt{48}+\sqrt{75}-\sqrt{27}\)?

Explanation opens after your attempt
Correct Answer

B. \(6\sqrt{3}\)

Step 1

Concept

\(\sqrt{48}=4\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\), and \(\sqrt{27}=3\sqrt{3}\).

Step 2

Why this answer is correct

\(4\sqrt{3}+5\sqrt{3}-3\sqrt{3}=6\sqrt{3}\).

Step 3

Exam Tip

For like surds, work with the coefficients. चरण 1: \(\sqrt{48}=4\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\), और \(\sqrt{27}=3\sqrt{3}\)। चरण 2: \(4\sqrt{3}+5\sqrt{3}-3\sqrt{3}=6\sqrt{3}\)। चरण 3: एक ही मूल वाले पदों में गुणांकों पर काम करें।

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Question 5/11 Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 13

कौन-सा विकल्प \(\sqrt{80}-\sqrt{45}+\sqrt{20}\) का सही सरल रूप देता है?

Which option gives the correct simplified form of \(\sqrt{80}-\sqrt{45}+\sqrt{20}\)?

Explanation opens after your attempt
Correct Answer

B. \(5\sqrt{5}\)

Step 1

Concept

\(\sqrt{80}=4\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), and \(\sqrt{20}=2\sqrt{5}\).

Step 2

Why this answer is correct

\(4\sqrt{5}-3\sqrt{5}+2\sqrt{5}=3\sqrt{5}\), so none of the listed options is correct.

Step 3

Exam Tip

In such questions, trust your simplification before matching options. चरण 1: \(\sqrt{80}=4\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), और \(\sqrt{20}=2\sqrt{5}\)। चरण 2: \(4\sqrt{5}-3\sqrt{5}+2\sqrt{5}=3\sqrt{5}\), इसलिए दिए विकल्पों में कोई सही नहीं दिखता। चरण 3: ऐसे प्रश्न में विकल्प से पहले अपनी गणना पर भरोसा करें।

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Question 6/11 Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 13

यदि \(x=3+\sqrt{8}\), तो (x) की प्रकृति और सरल रूप के बारे में सही कथन कौन-सा है?

If \(x=3+\sqrt{8}\), which statement about the nature and simplified form of (x) is correct?

Explanation opens after your attempt
Correct Answer

A. \(x=3+2\sqrt{2}\), अपरिमेय\(x=3+2\sqrt{2}\), irrational

Step 1

Concept

\(\sqrt{8}=2\sqrt{2}\).

Step 2

Why this answer is correct

So \(x=3+2\sqrt{2}\), which contains an irrational part.

Step 3

Exam Tip

Do not combine rational and irrational terms into a single radical. चरण 1: \(\sqrt{8}=2\sqrt{2}\) है। चरण 2: इसलिए \(x=3+2\sqrt{2}\), जिसमें अपरिमेय भाग है। चरण 3: परिमेय और अपरिमेय पदों को सीधे जोड़कर एक मूल न बनाएं।

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Question 7/11 Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 15

किस विकल्प में दी गई संख्या (0) के बराबर है?

Which option is equal to (0)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{8}-2\sqrt{2}\)

Step 1

Concept

\(\sqrt{8}=2\sqrt{2}\).

Step 2

Why this answer is correct

Therefore \(\sqrt{8}-2\sqrt{2}=0\), which is rational.

Step 3

Exam Tip

Sometimes terms that look irrational cancel completely. चरण 1: \(\sqrt{8}=2\sqrt{2}\) है। चरण 2: इसलिए \(\sqrt{8}-2\sqrt{2}=0\), जो परिमेय है। चरण 3: कभी-कभी अपरिमेय जैसे दिखने वाले पद पूरी तरह कट जाते हैं।

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Question 8/11 Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 15

यदि \(y=\sqrt{8}+\sqrt{32}\), तो \(\frac{y}{\sqrt{2}}\) का मान क्या है?

If \(y=\sqrt{8}+\sqrt{32}\), what is the value of \(\frac{y}{\sqrt{2}}\)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

\(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{32}=4\sqrt{2}\).

Step 2

Why this answer is correct

\(y=6\sqrt{2}\), so \(\frac{y}{\sqrt{2}}=6\).

Step 3

Exam Tip

First add like surds, then divide. चरण 1: \(\sqrt{8}=2\sqrt{2}\) और \(\sqrt{32}=4\sqrt{2}\)। चरण 2: \(y=6\sqrt{2}\), इसलिए \(\frac{y}{\sqrt{2}}=6\)। चरण 3: पहले समान मूल वाले पदों को जोड़ें, फिर भाग दें।

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Question 9/11 Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 15

किस विकल्प में दी गई संख्या निश्चित रूप से अपरिमेय है?

In which option is the given number definitely irrational?

Explanation opens after your attempt
Correct Answer

B. \(\frac{\sqrt{45}}{3}\)

Step 1

Concept

\(\frac{\sqrt{45}}{3}=\frac{3\sqrt{5}}{3}=\sqrt{5}\).

Step 2

Why this answer is correct

Since (5) is not a perfect square, \(\sqrt{5}\) is irrational.

Step 3

Exam Tip

Do not choose an answer in multiplication or division of surds without simplifying. चरण 1: \(\frac{\sqrt{45}}{3}=\frac{3\sqrt{5}}{3}=\sqrt{5}\) है। चरण 2: (5) पूर्ण वर्ग नहीं है, इसलिए \(\sqrt{5}\) अपरिमेय है। चरण 3: भाग और गुणन वाले विकल्पों को सरल किए बिना उत्तर न चुनें।

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Question 10/11 Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

कौन-सी संख्या \(\sqrt{72}\) का सरल रूप है?

Which number is the simplified form of \(\sqrt{72}\)?

Explanation opens after your attempt
Correct Answer

A. \(6\sqrt{2}\)

Step 1

Concept

\(72=36\times2\).

Step 2

Why this answer is correct

\(\sqrt{72}=\sqrt{36}\sqrt{2}=6\sqrt{2}\), which is irrational.

Step 3

Exam Tip

Use the largest perfect square factor for quick simplification. चरण 1: \(72=36\times2\) है। चरण 2: \(\sqrt{72}=\sqrt{36}\sqrt{2}=6\sqrt{2}\), जो अपरिमेय है। चरण 3: सबसे बड़ा पूर्ण वर्ग गुणनखंड लेने से सरल रूप जल्दी मिलता है।

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Question 11/11 Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

कौन-सी संख्या \(\sqrt{45}\) के बराबर है और अपरिमेय भी है?

Which number is equal to \(\sqrt{45}\) and is also irrational?

Explanation opens after your attempt
Correct Answer

A. \(3\sqrt{5}\)

Step 1

Concept

\(45=9\times5\).

Step 2

Why this answer is correct

\(\sqrt{45}=\sqrt{9}\sqrt{5}=3\sqrt{5}\), and \(\sqrt{5}\) is irrational.

Step 3

Exam Tip

Separate the largest perfect square factor while simplifying surds. चरण 1: \(45=9\times5\) है। चरण 2: \(\sqrt{45}=\sqrt{9}\sqrt{5}=3\sqrt{5}\), और \(\sqrt{5}\) अपरिमेय है। चरण 3: मूल को सरल करते समय सबसे बड़े पूर्ण वर्ग गुणनखंड को अलग करें।

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