यदि \(y=\sqrt{8}+\sqrt{32}\), तो \(\frac{y}{\sqrt{2}}\) का मान क्या है?
If \(y=\sqrt{8}+\sqrt{32}\), what is the value of \(\frac{y}{\sqrt{2}}\)?
Explanation opens after your attempt
Correct Answer
A. (6)
Concept
\(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{32}=4\sqrt{2}\).
Why this answer is correct
\(y=6\sqrt{2}\), so \(\frac{y}{\sqrt{2}}=6\).
Exam Tip
First add like surds, then divide. चरण 1: \(\sqrt{8}=2\sqrt{2}\) और \(\sqrt{32}=4\sqrt{2}\)। चरण 2: \(y=6\sqrt{2}\), इसलिए \(\frac{y}{\sqrt{2}}=6\)। चरण 3: पहले समान मूल वाले पदों को जोड़ें, फिर भाग दें।
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