If (y=\sqrt{8}+\sqrt{32}), what is the value of (\frac{y}{\sqrt{2}})?

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Answer and explanation

Correct answer: (6)

Step 1: (\sqrt{8}=2\sqrt{2}) and (\sqrt{32}=4\sqrt{2}). Step 2: (y=6\sqrt{2}), so (\frac{y}{\sqrt{2}}=6). Step 3: First add like surds, then divide.

What is the correct answer to this question?

(6)

Why is this the correct answer?

Step 1: (\sqrt{8}=2\sqrt{2}) and (\sqrt{32}=4\sqrt{2}). Step 2: (y=6\sqrt{2}), so (\frac{y}{\sqrt{2}}=6). Step 3: First add like surds, then divide.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Irrational numbers.

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