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If (y=3+2\sqrt{2}), what is the value of (y+\frac{1}{y})?यदि (y=3+2\sqrt{2}), तो (y+\frac{1}{y}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (6)(6)
Since (\frac{1}{3+2\sqrt{2}}=3-2\sqrt{2}), the sum is (6). In exams, use the conjugate quickly for such reciprocals.(\frac{1}{3+2\sqrt{2}}=3-2\sqrt{2}), इसलिए योग (6) है। परीक्षा में ऐसी संख्याओं को संयुग्म से तुरंत उलटें।
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