यदि \(m=\sqrt{6}+\sqrt{2}\), तो \(m^{2}\) का मान क्या है?
If \(m=\sqrt{6}+\sqrt{2}\), what is the value of \(m^{2}\)?
Explanation opens after your attempt
Correct Answer
A. \(8+4\sqrt{3}\)
Concept
(\(\sqrt{6}+\sqrt{2}\)^{2}=6+2+2\sqrt{12}=8+4\sqrt{3}). In exams, do not miss the middle term of ((a+b)^{2}).
Why this answer is correct
The correct answer is A. \(8+4\sqrt{3}\). (\(\sqrt{6}+\sqrt{2}\)^{2}=6+2+2\sqrt{12}=8+4\sqrt{3}). In exams, do not miss the middle term of ((a+b)^{2}).
Exam Tip
(\(\sqrt{6}+\sqrt{2}\)^{2}=6+2+2\sqrt{12}=8+4\sqrt{3})। परीक्षा में ((a+b)^{2}) का मध्य पद न भूलें।
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