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Subjects
Class 10MathematicsPolynomialsOperations on real numbers and the laws of exponentsHardLevel 45
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If (m=\sqrt{6}+\sqrt{2}), what is the value of (m^{2})?

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Answer and explanation

Correct answer: (8+4\sqrt{3})

((\sqrt{6}+\sqrt{2})^{2}=6+2+2\sqrt{12}=8+4\sqrt{3}). In exams, do not miss the middle term of ((a+b)^{2}).

Related tags

SurdsIdentityReal Numbers

Frequently asked questions

What is the correct answer to this question?

(8+4\sqrt{3})

Why is this the correct answer?

((\sqrt{6}+\sqrt{2})^{2}=6+2+2\sqrt{12}=8+4\sqrt{3}). In exams, do not miss the middle term of ((a+b)^{2}).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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  1. 1Which option gives the correct value of 1/(√10 − 3)?
  2. 2What is the value of (2^3\cdot2^4)?
  3. 3What is the simplified form of (\frac{5^6}{5^2})?
  4. 4What is the simplified form of ((3^2)^4)?
  5. 5If \(a\ne0\), what is the value of \(a^0\)?
  6. 6What is (10^{-2}) equal to?
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  8. 8What is the value of \(\left(\frac{3}{4}\right)^2\)?
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