Concept-wise Practice

multiple surds MCQ Questions for Class 10

multiple surds se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with multiple surds.

कौन-सा विकल्प \(\sqrt{50}+\sqrt{72}-\sqrt{98}\) का सही सरल रूप है?

Which option is the correct simplified form of \(\sqrt{50}+\sqrt{72}-\sqrt{98}\)?

Explanation opens after your attempt
Correct Answer

A. \(4\sqrt{2}\)

Step 1

Concept

\(\sqrt{50}=5\sqrt{2}\), \(\sqrt{72}=6\sqrt{2}\), and \(\sqrt{98}=7\sqrt{2}\).

Step 2

Why this answer is correct

\(5\sqrt{2}+6\sqrt{2}-7\sqrt{2}=4\sqrt{2}\).

Step 3

Exam Tip

Once all terms are like surds, add or subtract only the coefficients. चरण 1: \(\sqrt{50}=5\sqrt{2}\), \(\sqrt{72}=6\sqrt{2}\), और \(\sqrt{98}=7\sqrt{2}\)। चरण 2: \(5\sqrt{2}+6\sqrt{2}-7\sqrt{2}=4\sqrt{2}\)। चरण 3: सभी पद समान मूल में बदल जाएँ तो केवल गुणांक जोड़ें या घटाएँ।

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कौन-सा विकल्प \(\sqrt{3}+\sqrt{12}+\sqrt{27}\) का सही सरल रूप है?

Which option is the correct simplified form of \(\sqrt{3}+\sqrt{12}+\sqrt{27}\)?

Explanation opens after your attempt
Correct Answer

A. \(6\sqrt{3}\)

Step 1

Concept

\(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\).

Step 2

Why this answer is correct

The total sum is \(\sqrt{3}+2\sqrt{3}+3\sqrt{3}=6\sqrt{3}\).

Step 3

Exam Tip

Converting all terms into like surds makes addition easy. चरण 1: \(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\)। चरण 2: कुल योग \(\sqrt{3}+2\sqrt{3}+3\sqrt{3}=6\sqrt{3}\) है। चरण 3: सभी पदों को समान मूल में बदलने से जोड़ आसान हो जाता है।

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