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If (\frac{1}{\sqrt{a}+\sqrt{b}}=\sqrt{a}-\sqrt{b}) and (a>b>0), what is the value of (a-b)?यदि (\frac{1}{\sqrt{a}+\sqrt{b}}=\sqrt{a}-\sqrt{b}) और (a>b>0), तो (a-b) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (1)(1)
Multiplying both sides by (\sqrt{a}+\sqrt{b}), we get (1=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b})=a-b). In exams, apply the conjugate product directly.दोनों पक्षों को (\sqrt{a}+\sqrt{b}) से गुणा करने पर (1=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b})=a-b)। परीक्षा में संयुग्म गुणनफल सीधे लगाएं।
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