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If (s=3+\sqrt{10}), what is the value of (s^{2}-\frac{1}{s^{2}})?यदि (s=3+\sqrt{10}), तो (s^{2}-\frac{1}{s^{2}}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (12\sqrt{10})(12\sqrt{10})
Here (\frac{1}{s}=\sqrt{10}-3), so (s-\frac{1}{s}=6) and (s+\frac{1}{s}=2\sqrt{10}). Thus (s^{2}-\frac{1}{s^{2}}=12\sqrt{10}).(\frac{1}{s}=\sqrt{10}-3), इसलिए (s-\frac{1}{s}=6) और (s+\frac{1}{s}=2\sqrt{10})। अतः (s^{2}-\frac{1}{s^{2}}=12\sqrt{10})।
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