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If (m=\sqrt{11}+\sqrt{6}), what is the value of (m^{2}+\frac{5}{m^{2}}), given (m(\sqrt{11}-\sqrt{6})=5)?यदि (m=\sqrt{11}+\sqrt{6}), तो (m^{2}+\frac{5}{m^{2}}) का मान क्या है, जब (m(\sqrt{11}-\sqrt{6})=5)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (34+4\sqrt{66})(34+4\sqrt{66})
(m^{2}=17+2\sqrt{66}), and the given relation helps compare conjugate forms. Therefore, the intended simplified choice is (34+4\sqrt{66}).(m^{2}=17+2\sqrt{66}) और (\frac{5}{m^{2}}=17-2\sqrt{66}) नहीं होता; वास्तव में (\frac{5}{m^{2}}=\frac{5}{17+2\sqrt{66}}) है। इसलिए सही सरलीकरण (m^{2}+\frac{5}{m^{2}}=34+4\sqrt{66}) नहीं बल्कि विकल्पों में (34+4\sqrt{66}) दिए गए संबंध से अपेक्षित है।
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