0 reads0 ratings0 helpful
If (x=\sqrt{2}+\sqrt{5}), what is the value of (x^{3}-7x)?यदि (x=\sqrt{2}+\sqrt{5}), तो (x^{3}-7x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (10\sqrt{2}+4\sqrt{5})(10\sqrt{2}+4\sqrt{5})
Here (x^{2}=7+2\sqrt{10}), so (x^{3}=17\sqrt{2}+11\sqrt{5}) and (x^{3}-7x=10\sqrt{2}+4\sqrt{5}). In exams, first find (x^{2}) and then multiply by (x).(x^{2}=7+2\sqrt{10}), इसलिए (x^{3}=17\sqrt{2}+11\sqrt{5}) और (x^{3}-7x=10\sqrt{2}+4\sqrt{5})। परीक्षा में पहले (x^{2}) निकालकर फिर (x) से गुणा करें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
