\(\cos^{-1}0-\sin^{-1}0\) का मान क्या है?
What is the value of \(\cos^{-1}0-\sin^{-1}0\)?
Explanation opens after your attempt
B. \(\frac{\pi}{2}\)
Concept
Since \(\cos^{-1}0=\frac{\pi}{2}\) and \(\sin^{-1}0=0\), the difference is \(\frac{\pi}{2}\). Inverse trigonometric values at zero are very useful.
Why this answer is correct
The correct answer is B. \(\frac{\pi}{2}\). Since \(\cos^{-1}0=\frac{\pi}{2}\) and \(\sin^{-1}0=0\), the difference is \(\frac{\pi}{2}\). Inverse trigonometric values at zero are very useful.
Exam Tip
\(\cos^{-1}0=\frac{\pi}{2}\) और \(\sin^{-1}0=0\), इसलिए अंतर \(\frac{\pi}{2}\) है। शून्य के उल्टे त्रिकोणमितीय मान बहुत उपयोगी हैं।
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