Concept-wise Practice

table values MCQ Questions for Class 10

table values se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

5 questions tagged with table values.

समीकरण (y=4x-2) के लिए (x=3) होने पर कौन-सा बिंदु मिलेगा?

For (y=4x-2), which point is obtained when (x=3)?

Explanation opens after your attempt
Correct Answer

C. ( (3,10) )

Step 1

Concept

(y=4(3)-2=10), so the point is ( (3,10) ). Do not change the coordinate order after calculation.

Step 2

Why this answer is correct

The correct answer is C. ( (3,10) ). (y=4(3)-2=10), so the point is ( (3,10) ). Do not change the coordinate order after calculation.

Step 3

Exam Tip

(y=4(3)-2=10), इसलिए बिंदु ( (3,10) ) है। गणना के बाद निर्देशांक क्रम न बदलें।

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रेखा (x+y=13) पर (x=5) रखने पर कौन-सा बिंदु मिलेगा?

For the line (x+y=13), which point is obtained when (x=5)?

Explanation opens after your attempt
Correct Answer

A. ( (5,8) )

Step 1

Concept

From (5+y=13), (y=8), so the point is ( (5,8) ). While drawing a graph, write the point as ( (x,y) ).

Step 2

Why this answer is correct

The correct answer is A. ( (5,8) ). From (5+y=13), (y=8), so the point is ( (5,8) ). While drawing a graph, write the point as ( (x,y) ).

Step 3

Exam Tip

(5+y=13) से (y=8), इसलिए बिंदु ( (5,8) ) है। ग्राफ बनाते समय बिंदु को ( (x,y) ) रूप में लिखें।

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रेखा (2x+y=6) पर (x=0) रखने पर (y) का मान क्या होगा?

For the line (2x+y=6), what is the value of (y) when (x=0)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

Putting (x=0) gives (2(0)+y=6), so (y=6). For drawing a graph, first find such easy values.

Step 2

Why this answer is correct

The correct answer is A. (6). Putting (x=0) gives (2(0)+y=6), so (y=6). For drawing a graph, first find such easy values.

Step 3

Exam Tip

(x=0) रखने पर (2(0)+y=6), इसलिए (y=6)। ग्राफ बनाने के लिए ऐसे आसान मान पहले निकालें।

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यदि किसी ग्राफ पर (p(-5)>0), (p(-2)=0), (p(1)<0), (p(6)=0) है, तो दिए गए मानों में शून्यकों का योग क्या है?

If on a graph (p(-5)>0), (p(-2)=0), (p(1)<0), (p(6)=0), what is the sum of the zeroes among the given values?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

The given zeroes are (-2) and (6), so the sum is (4). Tip: take only the (x)-values where (p(x)=0).

Step 2

Why this answer is correct

The correct answer is A. (4). The given zeroes are (-2) and (6), so the sum is (4). Tip: take only the (x)-values where (p(x)=0).

Step 3

Exam Tip

दिए गए शून्यक (-2) और (6) हैं, इसलिए योग (4) है। टिप: केवल (p(x)=0) वाले (x)-मान लें।

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तालिका में (p(-2)=6), (p(1)=0), (p(3)=-4) और (p(5)=0) है। दिए गए मानों से कौन से शून्यक मिलते हैं?

In a table (p(-2)=6), (p(1)=0), (p(3)=-4) and (p(5)=0). Which zeroes are obtained from the given values?

Explanation opens after your attempt
Correct Answer

B. (1) और (5)(1) and (5)

Step 1

Concept

Zeroes are the (x)-values for which (p(x)=0). Tip: find zero (y)-values in the table.

Step 2

Why this answer is correct

The correct answer is B. (1) और (5) / (1) and (5). Zeroes are the (x)-values for which (p(x)=0). Tip: find zero (y)-values in the table.

Step 3

Exam Tip

शून्यक वही (x)-मान हैं जिन पर (p(x)=0) है। टिप: तालिका में शून्य (y)-मान खोजें।

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