Question 1/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
यदि किसी छात्र ने \(x^2=81\) से केवल (x=9) लिखा, तो सही सुधार क्या है?
If a student wrote only (x=9) from \(x^2=81\), what is the correct correction?
#quadratic
#square-root-method
#common-mistake
A \(x=\pm9\) लिखना चाहिए / One should write \(x=\pm9\)
B (x=81) लिखना चाहिए / One should write (x=81)
C (x=-81) लिखना चाहिए / One should write (x=-81)
D \(x=\pm81\) लिखना चाहिए / One should write \(x=\pm81\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm9\) लिखना चाहिए / One should write \(x=\pm9\)
Step 1
Concept
From \(x^2=81\), \(x=\pm\sqrt{81}=\pm9\). In exams, both signs are necessary in the square root method.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm9\) लिखना चाहिए / One should write \(x=\pm9\). From \(x^2=81\), \(x=\pm\sqrt{81}=\pm9\). In exams, both signs are necessary in the square root method.
Step 3
Exam Tip
\(x^2=81\) से \(x=\pm\sqrt{81}=\pm9\) मिलता है। परीक्षा में वर्गमूल विधि में दोनों चिन्ह अनिवार्य हैं।
Login to save your score, XP, coins and progress.
Question 2/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
((x-7)2 =11) को हल करने पर (x) का मान क्या होगा?
Solving ((x-7)2 =11), what will be the value of (x)?
#quadratic
#square-root-method
#irrational-roots
A \(x=7\pm\sqrt{11}\)
B \(x=-7\pm\sqrt{11}\)
C \(x=7\pm11\)
D \(x=\sqrt{7}\pm11\)
Explanation opens after your attempt
Correct Answer
A. \(x=7\pm\sqrt{11}\)
Step 1
Concept
\(x-7=\pm\sqrt{11}\), so \(x=7\pm\sqrt{11}\). In exams, write \(\pm\) with the whole square root.
Step 2
Why this answer is correct
The correct answer is A. \(x=7\pm\sqrt{11}\). \(x-7=\pm\sqrt{11}\), so \(x=7\pm\sqrt{11}\). In exams, write \(\pm\) with the whole square root.
Step 3
Exam Tip
\(x-7=\pm\sqrt{11}\), इसलिए \(x=7\pm\sqrt{11}\) है। परीक्षा में \(\pm\) को पूरे वर्गमूल के साथ लिखें।
Login to save your score, XP, coins and progress.
Question 3/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
\(7x^2=175\) को वर्गमूल विधि से हल करने पर मूल क्या होंगे?
What roots are obtained by solving \(7x^2=175\) by square root method?
#quadratic
#square-root-method
#solutions
A \(x=\pm5\)
B (x=5)
C (x=-5)
D \(x=\pm25\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm5\)
Step 1
Concept
First \(x^2=25\), so \(x=\pm5\). In exams, write both signs while taking square root.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm5\). First \(x^2=25\), so \(x=\pm5\). In exams, write both signs while taking square root.
Step 3
Exam Tip
पहले \(x^2=25\) मिलता है, इसलिए \(x=\pm5\) है। परीक्षा में वर्गमूल लेते समय दोनों चिन्ह लिखें।
Login to save your score, XP, coins and progress.
Question 4/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
यदि किसी छात्र ने \(x^2=49\) से केवल (x=7) लिखा, तो सही सुधार क्या है?
If a student wrote only (x=7) from \(x^2=49\), what is the correct correction?
#quadratic
#square-root-method
#common-mistake
A \(x=\pm7\) लिखना चाहिए / One should write \(x=\pm7\)
B (x=49) लिखना चाहिए / One should write (x=49)
C (x=-49) लिखना चाहिए / One should write (x=-49)
D \(x=\pm49\) लिखना चाहिए / One should write \(x=\pm49\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm7\) लिखना चाहिए / One should write \(x=\pm7\)
Step 1
Concept
From \(x^2=49\), \(x=\pm\sqrt{49}=\pm7\). In exams, both signs are necessary in the square root method.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm7\) लिखना चाहिए / One should write \(x=\pm7\). From \(x^2=49\), \(x=\pm\sqrt{49}=\pm7\). In exams, both signs are necessary in the square root method.
Step 3
Exam Tip
\(x^2=49\) से \(x=\pm\sqrt{49}=\pm7\) मिलता है। परीक्षा में वर्गमूल विधि में दोनों चिन्ह अनिवार्य हैं।
Login to save your score, XP, coins and progress.
Question 5/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
((x+6)2 =5) को हल करने पर (x) का मान क्या होगा?
Solving ((x+6)2 =5), what will be the value of (x)?
#quadratic
#square-root-method
#irrational-roots
A \(x=-6\pm\sqrt{5}\)
B \(x=6\pm\sqrt{5}\)
C \(x=-6\pm5\)
D \(x=\sqrt{6}\pm5\)
Explanation opens after your attempt
Correct Answer
A. \(x=-6\pm\sqrt{5}\)
Step 1
Concept
\(x+6=\pm\sqrt{5}\), so \(x=-6\pm\sqrt{5}\). In exams, write \(\pm\) with the whole square root.
Step 2
Why this answer is correct
The correct answer is A. \(x=-6\pm\sqrt{5}\). \(x+6=\pm\sqrt{5}\), so \(x=-6\pm\sqrt{5}\). In exams, write \(\pm\) with the whole square root.
Step 3
Exam Tip
\(x+6=\pm\sqrt{5}\), इसलिए \(x=-6\pm\sqrt{5}\) है। परीक्षा में \(\pm\) को पूरे वर्गमूल के साथ लिखें।
Login to save your score, XP, coins and progress.
Question 6/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
\(5x^2=80\) को वर्गमूल विधि से हल करने पर मूल क्या होंगे?
What roots are obtained by solving \(5x^2=80\) by square root method?
#quadratic
#square-root-method
#solutions
A \(x=\pm4\)
B (x=4)
C (x=-4)
D \(x=\pm16\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm4\)
Step 1
Concept
First \(x^2=16\), so \(x=\pm4\). In exams, write both signs while taking square root.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm4\). First \(x^2=16\), so \(x=\pm4\). In exams, write both signs while taking square root.
Step 3
Exam Tip
पहले \(x^2=16\) मिलता है, इसलिए \(x=\pm4\) है। परीक्षा में वर्गमूल लेते समय दोनों चिन्ह लिखें।
Login to save your score, XP, coins and progress.
Question 7/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
यदि किसी छात्र ने \(x^2=25\) से केवल (x=5) लिखा, तो सुधार क्या है?
If a student wrote only (x=5) from \(x^2=25\), what is the correction?
#quadratic
#square-root-method
#common-mistake
A \(x=\pm5\) लिखना चाहिए / One should write \(x=\pm5\)
B (x=25) लिखना चाहिए / One should write (x=25)
C (x=-25) लिखना चाहिए / One should write (x=-25)
D \(x=\pm25\) लिखना चाहिए / One should write \(x=\pm25\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm5\) लिखना चाहिए / One should write \(x=\pm5\)
Step 1
Concept
From \(x^2=25\), \(x=\pm\sqrt{25}=\pm5\). In exams, both signs are necessary in the square root method.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm5\) लिखना चाहिए / One should write \(x=\pm5\). From \(x^2=25\), \(x=\pm\sqrt{25}=\pm5\). In exams, both signs are necessary in the square root method.
Step 3
Exam Tip
\(x^2=25\) से \(x=\pm\sqrt{25}=\pm5\) मिलता है। परीक्षा में वर्गमूल विधि में दोनों चिन्ह अनिवार्य हैं।
Login to save your score, XP, coins and progress.
Question 8/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
((x-5)2 =3) को हल करने पर (x) का मान क्या होगा?
Solving ((x-5)2 =3), what will be the value of (x)?
#quadratic
#square-root-method
#irrational-roots
A \(x=5\pm\sqrt{3}\)
B \(x=-5\pm\sqrt{3}\)
C \(x=5\pm3\)
D \(x=\sqrt{5}\pm3\)
Explanation opens after your attempt
Correct Answer
A. \(x=5\pm\sqrt{3}\)
Step 1
Concept
\(x-5=\pm\sqrt{3}\), so \(x=5\pm\sqrt{3}\). In exams, write \(\pm\) with the whole square root.
Step 2
Why this answer is correct
The correct answer is A. \(x=5\pm\sqrt{3}\). \(x-5=\pm\sqrt{3}\), so \(x=5\pm\sqrt{3}\). In exams, write \(\pm\) with the whole square root.
Step 3
Exam Tip
\(x-5=\pm\sqrt{3}\), इसलिए \(x=5\pm\sqrt{3}\) है। परीक्षा में \(\pm\) को पूरे वर्गमूल के साथ लिखें।
Login to save your score, XP, coins and progress.
Question 9/31
Medium Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
\(3x^2=12\) को वर्गमूल विधि से हल करने पर मूल क्या होंगे?
What roots are obtained by solving \(3x^2=12\) by square root method?
#quadratic
#square-root-method
#solutions
A \(x=\pm2\)
B (x=2)
C (x=-2)
D \(x=\pm4\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm2\)
Step 1
Concept
First \(x^2=4\), so \(x=\pm2\). In exams, write both signs while taking square root.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm2\). First \(x^2=4\), so \(x=\pm2\). In exams, write both signs while taking square root.
Step 3
Exam Tip
पहले \(x^2=4\) मिलता है, इसलिए \(x=\pm2\) है। परीक्षा में वर्गमूल लेते समय दोनों चिन्ह लिखें।
Login to save your score, XP, coins and progress.
Question 10/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
\(12x^2=108\) के हल क्या हैं?
What are the solutions of \(12x^2=108\)?
#quadratic
#square-root-method
#solutions
A \(x=\pm3\)
B (x=3)
C (x=-3)
D \(x=\pm9\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm3\)
Step 1
Concept
From \(12x^2=108\), \(x^2=9\), so \(x=\pm3\). In exams, write both values in the final answer.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm3\). From \(12x^2=108\), \(x^2=9\), so \(x=\pm3\). In exams, write both values in the final answer.
Step 3
Exam Tip
\(12x^2=108\) से \(x^2=9\), इसलिए \(x=\pm3\) है। परीक्षा में अंतिम उत्तर में दोनों मान लिखें।
Login to save your score, XP, coins and progress.
Question 11/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
\(12x^2=108\) को हल करने का सही सरल रूप कौनसा है?
What is the correct simplified form to solve \(12x^2=108\)?
#quadratic
#simplification
#square-root-method
A \(x^2=9\)
B \(x^2=108\)
C \(x^2=12\)
D \(x^2=96\)
Explanation opens after your attempt
Correct Answer
A. \(x^2=9\)
Step 1
Concept
Dividing both sides by (12) gives \(x^2=9\). In exams, remove the coefficient first.
Step 2
Why this answer is correct
The correct answer is A. \(x^2=9\). Dividing both sides by (12) gives \(x^2=9\). In exams, remove the coefficient first.
Step 3
Exam Tip
दोनों पक्षों को (12) से भाग देने पर \(x^2=9\) मिलता है। परीक्षा में पहले गुणांक हटाएं।
Login to save your score, XP, coins and progress.
Question 12/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
\(x^2+36=0\) के वास्तविक मूलों के बारे में सही कथन क्या है?
What is the correct statement about the real roots of \(x^2+36=0\)?
#quadratic
#no-real-roots
#square-root-method
A कोई वास्तविक मूल नहीं / No real roots
B दो वास्तविक मूल (6) और (-6) / Two real roots (6) and (-6)
C एक वास्तविक मूल (36) / One real root (36)
D दो समान वास्तविक मूल (0) / Two equal real roots (0)
Explanation opens after your attempt
Correct Answer
A. कोई वास्तविक मूल नहीं / No real roots
Step 1
Concept
\(x^2=-36\) is not possible in real numbers. In exams, \(x^2\) is not negative for real (x).
Step 2
Why this answer is correct
The correct answer is A. कोई वास्तविक मूल नहीं / No real roots. \(x^2=-36\) is not possible in real numbers. In exams, \(x^2\) is not negative for real (x).
Step 3
Exam Tip
\(x^2=-36\) वास्तविक संख्याओं में संभव नहीं है। परीक्षा में \(x^2\) का मान वास्तविक (x) के लिए ऋणात्मक नहीं होता।
Login to save your score, XP, coins and progress.
Question 13/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
((x-4)2 =25) को हल करने पर कौनसे मान मिलते हैं?
Solving ((x-4)2 =25) gives which values?
#quadratic
#square-root-method
#roots
A (x=9,-1)
B (x=5,-5)
C (x=4,25)
D (x=1,9)
Explanation opens after your attempt
Correct Answer
A. (x=9,-1)
Step 1
Concept
\(x-4=\pm5\), so (x=9) or (x=-1). In exams, write both \(\pm\) cases.
Step 2
Why this answer is correct
The correct answer is A. (x=9,-1). \(x-4=\pm5\), so (x=9) or (x=-1). In exams, write both \(\pm\) cases.
Step 3
Exam Tip
\(x-4=\pm5\), इसलिए (x=9) या (x=-1) है। परीक्षा में दोनों \(\pm\) स्थितियां लिखें।
Login to save your score, XP, coins and progress.
Question 14/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
\(x^2=169\) को वर्गमूल विधि से हल करने पर क्या मिलेगा?
Solving \(x^2=169\) by square root method gives what?
#quadratic
#square-root-method
#common-mistake
A \(x=\pm13\)
B (x=13)
C (x=-13)
D \(x=\pm169\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm13\)
Step 1
Concept
\(x=\pm\sqrt{169}=\pm13\). In exams, writing only (13) is an incomplete answer.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm13\). \(x=\pm\sqrt{169}=\pm13\). In exams, writing only (13) is an incomplete answer.
Step 3
Exam Tip
\(x=\pm\sqrt{169}=\pm13\) होता है। परीक्षा में केवल (13) लिखना अधूरा उत्तर है।
Login to save your score, XP, coins and progress.
Question 15/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
\(10x^2-90=0\) को पहले सरल करने पर क्या मिलेगा?
What will be obtained first after simplifying \(10x^2-90=0\)?
#quadratic
#simplification
#square-root-method
A \(x^2-9=0\)
B \(x^2+9=0\)
C \(10x^2=0\)
D \(x^2-90=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-9=0\)
Step 1
Concept
Dividing both sides by (10) gives \(x^2-9=0\). In exams, simplifying the equation first saves time.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-9=0\). Dividing both sides by (10) gives \(x^2-9=0\). In exams, simplifying the equation first saves time.
Step 3
Exam Tip
दोनों पक्षों को (10) से भाग देने पर \(x^2-9=0\) मिलता है। परीक्षा में पहले समीकरण को सरल करना समय बचाता है।
Login to save your score, XP, coins and progress.
Question 16/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36
वर्गमूल विधि से \(x^2=144\) के हल क्या हैं?
By square root method, what are the solutions of \(x^2=144\)?
#quadratic
#square-root-method
#solutions
A \(x=\pm12\)
B (x=12)
C (x=-12)
D \(x=\pm72\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm12\)
Step 1
Concept
\(x=\pm\sqrt{144}=\pm12\). In exams, do not forget \(\pm\) while taking square root.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm12\). \(x=\pm\sqrt{144}=\pm12\). In exams, do not forget \(\pm\) while taking square root.
Step 3
Exam Tip
\(x=\pm\sqrt{144}=\pm12\) होता है। परीक्षा में वर्गमूल लेते समय \(\pm\) लगाना न भूलें।
Login to save your score, XP, coins and progress.
Question 17/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
\(8x^2=72\) के हल क्या हैं?
What are the solutions of \(8x^2=72\)?
#quadratic
#square-root-method
#solutions
A \(x=\pm3\)
B (x=3)
C (x=-3)
D \(x=\pm9\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm3\)
Step 1
Concept
From \(8x^2=72\), \(x^2=9\), so \(x=\pm3\). In exams, write both values in the final answer.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm3\). From \(8x^2=72\), \(x^2=9\), so \(x=\pm3\). In exams, write both values in the final answer.
Step 3
Exam Tip
\(8x^2=72\) से \(x^2=9\), इसलिए \(x=\pm3\) है। परीक्षा में अंतिम उत्तर में दोनों मान लिखें।
Login to save your score, XP, coins and progress.
Question 18/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
\(8x^2=72\) को हल करने का सही सरल रूप कौनसा है?
What is the correct simplified form to solve \(8x^2=72\)?
#quadratic
#simplification
#square-root-method
A \(x^2=9\)
B \(x^2=72\)
C \(x^2=64\)
D \(x^2=8\)
Explanation opens after your attempt
Correct Answer
A. \(x^2=9\)
Step 1
Concept
Dividing both sides by (8) gives \(x^2=9\). In exams, remove the coefficient first.
Step 2
Why this answer is correct
The correct answer is A. \(x^2=9\). Dividing both sides by (8) gives \(x^2=9\). In exams, remove the coefficient first.
Step 3
Exam Tip
दोनों पक्षों को (8) से भाग देने पर \(x^2=9\) मिलता है। परीक्षा में पहले गुणांक हटाएं।
Login to save your score, XP, coins and progress.
Question 19/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
\(x^2+25=0\) के वास्तविक मूलों के बारे में सही कथन क्या है?
What is the correct statement about the real roots of \(x^2+25=0\)?
#quadratic
#no-real-roots
#square-root-method
A कोई वास्तविक मूल नहीं / No real roots
B दो वास्तविक मूल (5) और (-5) / Two real roots (5) and (-5)
C एक वास्तविक मूल (25) / One real root (25)
D दो समान वास्तविक मूल (0) / Two equal real roots (0)
Explanation opens after your attempt
Correct Answer
A. कोई वास्तविक मूल नहीं / No real roots
Step 1
Concept
\(x^2=-25\) is not possible in real numbers. In exams, \(x^2\) is not negative for real (x).
Step 2
Why this answer is correct
The correct answer is A. कोई वास्तविक मूल नहीं / No real roots. \(x^2=-25\) is not possible in real numbers. In exams, \(x^2\) is not negative for real (x).
Step 3
Exam Tip
\(x^2=-25\) वास्तविक संख्याओं में संभव नहीं है। परीक्षा में \(x^2\) का मान वास्तविक (x) के लिए ऋणात्मक नहीं होता।
Login to save your score, XP, coins and progress.
Question 20/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
((x+3)2 =16) को हल करने पर कौनसे मान मिलते हैं?
Solving ((x+3)2 =16) gives which values?
#quadratic
#square-root-method
#roots
A (x=1,-7)
B (x=4,-4)
C (x=7,-1)
D (x=3,16)
Explanation opens after your attempt
Correct Answer
A. (x=1,-7)
Step 1
Concept
\(x+3=\pm4\), so (x=1) or (x=-7). In exams, write both \(\pm\) cases.
Step 2
Why this answer is correct
The correct answer is A. (x=1,-7). \(x+3=\pm4\), so (x=1) or (x=-7). In exams, write both \(\pm\) cases.
Step 3
Exam Tip
\(x+3=\pm4\), इसलिए (x=1) या (x=-7) है। परीक्षा में दोनों \(\pm\) स्थितियां लिखें।
Login to save your score, XP, coins and progress.
Question 21/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
\(x^2=121\) को वर्गमूल विधि से हल करने पर क्या मिलेगा?
Solving \(x^2=121\) by square root method gives what?
#quadratic
#square-root-method
#common-mistake
A \(x=\pm11\)
B (x=11)
C (x=-11)
D \(x=\pm121\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm11\)
Step 1
Concept
\(x=\pm\sqrt{121}=\pm11\). In exams, writing only (11) is an incomplete answer.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm11\). \(x=\pm\sqrt{121}=\pm11\). In exams, writing only (11) is an incomplete answer.
Step 3
Exam Tip
\(x=\pm\sqrt{121}=\pm11\) होता है। परीक्षा में केवल (11) लिखना अधूरा उत्तर है।
Login to save your score, XP, coins and progress.
Question 22/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
\(6x^2-24=0\) को पहले सरल करने पर क्या मिलेगा?
What will be obtained first after simplifying \(6x^2-24=0\)?
#quadratic
#simplification
#square-root-method
A \(x^2-4=0\)
B \(x^2+4=0\)
C \(6x^2=0\)
D \(x^2-24=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4=0\)
Step 1
Concept
Dividing both sides by (6) gives \(x^2-4=0\). In exams, simplify the equation first.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4=0\). Dividing both sides by (6) gives \(x^2-4=0\). In exams, simplify the equation first.
Step 3
Exam Tip
दोनों पक्षों को (6) से भाग देने पर \(x^2-4=0\) मिलता है। परीक्षा में पहले समीकरण सरल करें।
Login to save your score, XP, coins and progress.
Question 23/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35
वर्गमूल विधि से \(x^2=64\) के हल क्या हैं?
By square root method, what are the solutions of \(x^2=64\)?
#quadratic
#square-root-method
#solutions
A \(x=\pm8\)
B (x=8)
C (x=-8)
D \(x=\pm32\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm8\)
Step 1
Concept
\(x=\pm\sqrt{64}=\pm8\). In exams, write both signs while taking square root.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm8\). \(x=\pm\sqrt{64}=\pm8\). In exams, write both signs while taking square root.
Step 3
Exam Tip
\(x=\pm\sqrt{64}=\pm8\) होता है। परीक्षा में वर्गमूल लेते समय दोनों चिन्ह लिखें।
Login to save your score, XP, coins and progress.
Question 24/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
\(5x^2=20\) के हल क्या हैं?
What are the solutions of \(5x^2=20\)?
#quadratic
#square-root-method
#solutions
A \(x=\pm2\)
B (x=2)
C (x=-2)
D \(x=\pm4\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm2\)
Step 1
Concept
From \(5x^2=20\), \(x^2=4\), so \(x=\pm2\). In exams, write both values in the final answer.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm2\). From \(5x^2=20\), \(x^2=4\), so \(x=\pm2\). In exams, write both values in the final answer.
Step 3
Exam Tip
\(5x^2=20\) से \(x^2=4\), इसलिए \(x=\pm2\) है। परीक्षा में अंतिम उत्तर में दोनों मान लिखें।
Login to save your score, XP, coins and progress.
Question 25/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
\(5x^2=20\) को हल करने का सही सरल रूप कौनसा है?
What is the correct simplified form to solve \(5x^2=20\)?
#quadratic
#simplification
#square-root-method
A \(x^2=4\)
B \(x^2=20\)
C \(x^2=25\)
D \(x^2=100\)
Explanation opens after your attempt
Correct Answer
A. \(x^2=4\)
Step 1
Concept
Dividing both sides by (5) gives \(x^2=4\). In exams, remove the coefficient first and then take square root.
Step 2
Why this answer is correct
The correct answer is A. \(x^2=4\). Dividing both sides by (5) gives \(x^2=4\). In exams, remove the coefficient first and then take square root.
Step 3
Exam Tip
दोनों पक्षों को (5) से भाग देने पर \(x^2=4\) मिलता है। परीक्षा में पहले गुणांक हटाकर वर्गमूल लें।
Login to save your score, XP, coins and progress.
Question 26/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
\(x^2+9=0\) के वास्तविक मूलों के बारे में सही कथन क्या है?
What is the correct statement about the real roots of \(x^2+9=0\)?
#quadratic
#no-real-roots
#square-root-method
A कोई वास्तविक मूल नहीं / No real roots
B दो वास्तविक मूल (3) और (-3) / Two real roots (3) and (-3)
C एक वास्तविक मूल (9) / One real root (9)
D दो समान वास्तविक मूल (0) / Two equal real roots (0)
Explanation opens after your attempt
Correct Answer
A. कोई वास्तविक मूल नहीं / No real roots
Step 1
Concept
\(x^2=-9\) gives no solution in real numbers. In exams, remember that \(x^2\) cannot be negative for real (x).
Step 2
Why this answer is correct
The correct answer is A. कोई वास्तविक मूल नहीं / No real roots. \(x^2=-9\) gives no solution in real numbers. In exams, remember that \(x^2\) cannot be negative for real (x).
Step 3
Exam Tip
\(x^2=-9\) से वास्तविक संख्या में हल नहीं मिलता। परीक्षा में \(x^2\) ऋणात्मक नहीं हो सकता यह याद रखें।
Login to save your score, XP, coins and progress.
Question 27/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
((x-2)2 =9) को हल करने पर कौनसे मान मिलते हैं?
Solving ((x-2)2 =9) gives which values?
#quadratic
#square-root-method
#roots
A (x=5,-1)
B (x=2,9)
C (x=3,-3)
D (x=5,1)
Explanation opens after your attempt
Correct Answer
A. (x=5,-1)
Step 1
Concept
\(x-2=\pm3\), so (x=5) or (x=-1). In exams, write both \(\pm\) cases.
Step 2
Why this answer is correct
The correct answer is A. (x=5,-1). \(x-2=\pm3\), so (x=5) or (x=-1). In exams, write both \(\pm\) cases.
Step 3
Exam Tip
\(x-2=\pm3\), इसलिए (x=5) या (x=-1) है। परीक्षा में \(\pm\) के दोनों केस लिखें।
Login to save your score, XP, coins and progress.
Question 28/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
किस समीकरण को वर्गमूल विधि से सीधे हल किया जा सकता है?
Which equation can be solved directly by square root method?
#quadratic
#square-root-method
#method-selection
A ((x-2)2 =9)
B \(x^2+5x+6=0\)
C \(x^2+2x+1=0\)
D \(2x^2+3x+1=0\)
Explanation opens after your attempt
Correct Answer
A. ((x-2)2 =9)
Step 1
Concept
\(In ((x-2)^2=9), square root can be taken directly. In exams, recognize the form ((\)expression\()^2=k).\)
Step 2
Why this answer is correct
\(The correct answer is A. ((x-2)^2=9). In ((x-2)^2=9), square root can be taken directly. In exams, recognize the form ((\)expression\()^2=k).\)
Step 3
Exam Tip
((x-2)2 =9) में सीधे वर्गमूल लिया जा सकता है। परीक्षा में ((expression\()^2=k) रूप को पहचानें\)।
Login to save your score, XP, coins and progress.
Question 29/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
\(x^2=49\) को वर्गमूल विधि से हल करने पर क्या मिलेगा?
Solving \(x^2=49\) by square root method gives what?
#quadratic
#square-root-method
#common-mistake
A \(x=\pm7\)
B (x=7)
C (x=-7)
D \(x=\pm49\)
Explanation opens after your attempt
Correct Answer
A. \(x=\pm7\)
Step 1
Concept
\(x=\pm\sqrt{49}=\pm7\). In exams, writing only the positive root is a common mistake.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm7\). \(x=\pm\sqrt{49}=\pm7\). In exams, writing only the positive root is a common mistake.
Step 3
Exam Tip
\(x=\pm\sqrt{49}=\pm7\) होता है। परीक्षा में केवल धनात्मक मूल लिखना सामान्य गलती है।
Login to save your score, XP, coins and progress.
Question 30/31
Easy Mathematics
Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34
\(2x^2-8=0\) को पहले सरल करने पर क्या मिलेगा?
What do we get first after simplifying \(2x^2-8=0\)?
#quadratic
#simplification
#square-root-method
A \(x^2-4=0\)
B \(x^2+4=0\)
C \(2x^2=0\)
D \(x^2-8=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4=0\)
Step 1
Concept
Dividing both sides by (2) gives \(x^2-4=0\). In exams, simplifying the equation first saves time.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4=0\). Dividing both sides by (2) gives \(x^2-4=0\). In exams, simplifying the equation first saves time.
Step 3
Exam Tip
दोनों पक्षों को (2) से भाग देने पर \(x^2-4=0\) मिलता है। परीक्षा में समीकरण को पहले सरल करना समय बचाता है।
Login to save your score, XP, coins and progress.
