What are the values of \(x\) obtained by solving the equation \(x^2=169\) using the square-root method?
Answer and explanation
Correct answer: \(x=\pm13\)
Taking square roots gives \(x=\pm\sqrt{169}=\pm13\), so both \(x=13\) and \(x=-13\) are solutions. Writing only \(x=13\) is incomplete because both the positive and negative numbers have square 169. In an exam, remember to write both values as \(x=\pm\sqrt{a}\) when \(x^2=a\).
Frequently asked questions
What is the correct answer to this question?
\(x=\pm13\)
Why is this the correct answer?
Taking square roots gives \(x=\pm\sqrt{169}=\pm13\), so both \(x=13\) and \(x=-13\) are solutions. Writing only \(x=13\) is incomplete because both the positive and negative numbers have square 169. In an exam, remember to write both values as \(x=\pm\sqrt{a}\) when \(x^2=a\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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