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Class 10MathematicsQuadratic EquationsNature of RootsHard
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If the roots of (x^2-2kx+9=0) are equal, what are the possible values of (k)?

Answer and explanation

Correct answer: (k=\pm3)

For equal roots, (D=0), so ((-2k)^2-4\cdot1\cdot9=0) gives (k=\pm3). In exams, when (k^2) appears, check both signs.

Related tags

Quadratic EquationsNature Of RootsParameterNature Of RootsQuadratic EquationsMathematicsClass 10 Mcq
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