\( \sqrt{180} \) का सरल करणी रूप क्या है?
What is the simplified surd form of \( \sqrt{180} \)?
#real numbers
#surds
#simplification
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A \(6\sqrt{5}\)
B \(18\sqrt{5}\)
C \(3\sqrt{20}\)
D \(12\sqrt{5}\)
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{5}\)
Step 1
Concept
Since \(180=36\times5\), \( \sqrt{180}=6\sqrt{5} \). Choose the largest perfect-square factor.
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{5}\). Since \(180=36\times5\), \( \sqrt{180}=6\sqrt{5} \). Choose the largest perfect-square factor.
Step 3
Exam Tip
\(180=36\times5\) इसलिए \( \sqrt{180}=6\sqrt{5} \)। सबसे बड़ा पूर्ण वर्ग गुणनखंड चुनें।
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\( \sqrt{245} \) को सरल करने पर क्या मिलेगा?
What is obtained by simplifying \( \sqrt{245} \)?
#real numbers
#radicals
#simplification
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A \(35\sqrt{7}\)
B \(7\sqrt{5}\)
C \(5\sqrt{7}\)
D \(49\sqrt{5}\)
Explanation opens after your attempt
Correct Answer
B. \(7\sqrt{5}\)
Step 1
Concept
Since \(245=49\times5\), \( \sqrt{245}=7\sqrt{5} \). Take the perfect square outside the radical.
Step 2
Why this answer is correct
The correct answer is B. \(7\sqrt{5}\). Since \(245=49\times5\), \( \sqrt{245}=7\sqrt{5} \). Take the perfect square outside the radical.
Step 3
Exam Tip
\(245=49\times5\) इसलिए \( \sqrt{245}=7\sqrt{5} \)। करणी में पूर्ण वर्ग को बाहर निकालें।
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\( \sqrt{288} \) का सरल रूप कौन सा है?
Which is the simplified form of \( \sqrt{288} \)?
#real numbers
#surd form
#radicals
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A \(24\sqrt{2}\)
B \(6\sqrt{8}\)
C \(12\sqrt{2}\)
D \(8\sqrt{6}\)
Explanation opens after your attempt
Correct Answer
C. \(12\sqrt{2}\)
Step 1
Concept
Since \(288=144\times2\), \( \sqrt{288}=12\sqrt{2} \). First find the largest perfect square.
Step 2
Why this answer is correct
The correct answer is C. \(12\sqrt{2}\). Since \(288=144\times2\), \( \sqrt{288}=12\sqrt{2} \). First find the largest perfect square.
Step 3
Exam Tip
\(288=144\times2\) इसलिए \( \sqrt{288}=12\sqrt{2} \)। पहले सबसे बड़ा पूर्ण वर्ग खोजें।
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\(2\sqrt{45}+3\sqrt{20}\) का सरल रूप क्या है?
What is the simplified form of \(2\sqrt{45}+3\sqrt{20}\)?
#real numbers
#like surds
#addition
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A \(12\sqrt{5}\)
B \(18\sqrt{5}\)
C \(15\sqrt{5}\)
D \(24\sqrt{5}\)
Explanation opens after your attempt
Correct Answer
A. \(12\sqrt{5}\)
Step 1
Concept
\(2\sqrt{45}=6\sqrt{5}\) and \(3\sqrt{20}=6\sqrt{5}\). So the sum is \(12\sqrt{5}\).
Step 2
Why this answer is correct
The correct answer is A. \(12\sqrt{5}\). \(2\sqrt{45}=6\sqrt{5}\) and \(3\sqrt{20}=6\sqrt{5}\). So the sum is \(12\sqrt{5}\).
Step 3
Exam Tip
\(2\sqrt{45}=6\sqrt{5}\) और \(3\sqrt{20}=6\sqrt{5}\) है। इसलिए योग \(12\sqrt{5}\) है।
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\(4\sqrt{27}-2\sqrt{75}\) का सरल रूप क्या है?
What is the simplified form of \(4\sqrt{27}-2\sqrt{75}\)?
#real numbers
#surd subtraction
#medium
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A \(2\sqrt{3}\)
B \(4\sqrt{3}\)
C \(6\sqrt{3}\)
D \(8\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{3}\)
Step 1
Concept
\(4\sqrt{27}=12\sqrt{3}\) and \(2\sqrt{75}=10\sqrt{3}\). The difference is \(2\sqrt{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(2\sqrt{3}\). \(4\sqrt{27}=12\sqrt{3}\) and \(2\sqrt{75}=10\sqrt{3}\). The difference is \(2\sqrt{3}\).
Step 3
Exam Tip
\(4\sqrt{27}=12\sqrt{3}\) और \(2\sqrt{75}=10\sqrt{3}\) है। अंतर \(2\sqrt{3}\) मिलता है।
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( \sqrt{5}\(3+\sqrt{5}\) ) का मान क्या है?
What is the value of ( \sqrt{5}\(3+\sqrt{5}\) )?
#real numbers
#distribution
#surds
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A \(3\sqrt{5}+5\)
B \(8\sqrt{5}\)
C \(3+\sqrt{25}\)
D \(5\sqrt{5}+3\)
Explanation opens after your attempt
Correct Answer
A. \(3\sqrt{5}+5\)
Step 1
Concept
By distributive law, \( \sqrt{5}\times3+\sqrt{5}\times\sqrt{5}=3\sqrt{5}+5 \). Be careful in surd multiplication.
Step 2
Why this answer is correct
The correct answer is A. \(3\sqrt{5}+5\). By distributive law, \( \sqrt{5}\times3+\sqrt{5}\times\sqrt{5}=3\sqrt{5}+5 \). Be careful in surd multiplication.
Step 3
Exam Tip
वितरण नियम से \( \sqrt{5}\times3+\sqrt{5}\times\sqrt{5}=3\sqrt{5}+5 \)। समान करणी गुणन में सावधानी रखें।
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( \(4+\sqrt{3}\)2 ) का विस्तार क्या है?
What is the expansion of ( \(4+\sqrt{3}\)2 )?
#real numbers
#identity
#surd square
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A \(19+8\sqrt{3}\)
B \(13+4\sqrt{3}\)
C \(16+3\sqrt{4}\)
D \(7+8\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(19+8\sqrt{3}\)
Step 1
Concept
Use ( (a+b)2 ). Here \(16+8\sqrt{3}+3=19+8\sqrt{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(19+8\sqrt{3}\). Use ( (a+b)2 ). Here \(16+8\sqrt{3}+3=19+8\sqrt{3}\).
Step 3
Exam Tip
( (a+b)2 ) का प्रयोग करें। यहाँ \(16+8\sqrt{3}+3=19+8\sqrt{3}\) मिलता है।
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( \(6-\sqrt{8}\)2 ) का सरल रूप क्या है?
What is the simplified form of ( \(6-\sqrt{8}\)2 )?
#real numbers
#algebraic identity
#surds
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A \(44-12\sqrt{8}\)
B \(44-24\sqrt{2}\)
C \(28-12\sqrt{2}\)
D \(36-8\sqrt{6}\)
Explanation opens after your attempt
Correct Answer
B. \(44-24\sqrt{2}\)
Step 1
Concept
( \(6-\sqrt{8}\)2 =36-12\sqrt{8}+8 ). Using \( \sqrt{8}=2\sqrt{2} \), it becomes \(44-24\sqrt{2}\).
Step 2
Why this answer is correct
The correct answer is B. \(44-24\sqrt{2}\). ( \(6-\sqrt{8}\)2 =36-12\sqrt{8}+8 ). Using \( \sqrt{8}=2\sqrt{2} \), it becomes \(44-24\sqrt{2}\).
Step 3
Exam Tip
( \(6-\sqrt{8}\)2 =36-12\sqrt{8}+8 ) है। \( \sqrt{8}=2\sqrt{2} \) रखने पर \(44-24\sqrt{2}\) मिलता है।
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( \(5+\sqrt{17}\)\(5-\sqrt{17}\) ) का मान क्या है?
What is the value of ( \(5+\sqrt{17}\)\(5-\sqrt{17}\) )?
#real numbers
#conjugate
#difference of squares
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A (42)
B (8)
C \(25+\sqrt{17}\)
D \(25-\sqrt{17}\)
Explanation opens after your attempt
Step 1
Concept
This is conjugate multiplication. (52 -\(\sqrt{17}\)2 =25-17=8).
Step 2
Why this answer is correct
The correct answer is B. (8). This is conjugate multiplication. (52 -\(\sqrt{17}\)2 =25-17=8).
Step 3
Exam Tip
यह संयुग्मी गुणन है। (52 -\(\sqrt{17}\)2 =25-17=8) होगा।
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( \(2+\sqrt{19}\)\(2-\sqrt{19}\) ) का मान क्या है?
What is the value of ( \(2+\sqrt{19}\)\(2-\sqrt{19}\) )?
#real numbers
#conjugate
#surds
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A (15)
B ( -15 )
C (23)
D \(4-\sqrt{19}\)
Explanation opens after your attempt
Correct Answer
B. ( -15 )
Step 1
Concept
Conjugate multiplication gives (22 -\(\sqrt{19}\)2 =4-19=-15). The middle terms cancel.
Step 2
Why this answer is correct
The correct answer is B. ( -15 ). Conjugate multiplication gives (22 -\(\sqrt{19}\)2 =4-19=-15). The middle terms cancel.
Step 3
Exam Tip
संयुग्मी गुणन से (22 -\(\sqrt{19}\)2 =4-19=-15) मिलता है। मध्य पद कट जाते हैं।
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\( \frac{6}{\sqrt{7}} \) का परिमेय हर वाला रूप क्या है?
What is the rationalised form of \( \frac{6}{\sqrt{7}} \)?
#real numbers
#rationalisation
#denominator
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A \( \frac{6\sqrt{7}}{7} \)
B \( \frac{\sqrt{7}}{6} \)
C \( \frac{6}{7} \)
D \(6\sqrt{7}\)
Explanation opens after your attempt
Correct Answer
A. \( \frac{6\sqrt{7}}{7} \)
Step 1
Concept
Multiply numerator and denominator by \( \sqrt{7} \). This makes the denominator (7).
Step 2
Why this answer is correct
The correct answer is A. \( \frac{6\sqrt{7}}{7} \). Multiply numerator and denominator by \( \sqrt{7} \). This makes the denominator (7).
Step 3
Exam Tip
अंश और हर को \( \sqrt{7} \) से गुणा करें। इससे हर (7) हो जाता है।
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\( \frac{5}{3\sqrt{2}} \) का परिमेय हर वाला रूप क्या है?
What is the rationalised form of \( \frac{5}{3\sqrt{2}} \)?
#real numbers
#rationalisation
#surds
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A \( \frac{5\sqrt{2}}{6} \)
B \( \frac{5\sqrt{2}}{3} \)
C \( \frac{10\sqrt{2}}{3} \)
D \( \frac{5}{6} \)
Explanation opens after your attempt
Correct Answer
A. \( \frac{5\sqrt{2}}{6} \)
Step 1
Concept
Multiplying numerator and denominator by \( \sqrt{2} \) gives \( \frac{5\sqrt{2}}{6} \). The radical should be removed from the denominator.
Step 2
Why this answer is correct
The correct answer is A. \( \frac{5\sqrt{2}}{6} \). Multiplying numerator and denominator by \( \sqrt{2} \) gives \( \frac{5\sqrt{2}}{6} \). The radical should be removed from the denominator.
Step 3
Exam Tip
अंश और हर को \( \sqrt{2} \) से गुणा करने पर \( \frac{5\sqrt{2}}{6} \) मिलता है। हर से करणी हटनी चाहिए।
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\( \frac{1}{\sqrt{10}+\sqrt{9}} \) का परिमेय हर वाला रूप क्या है?
What is the rationalised form of \( \frac{1}{\sqrt{10}+\sqrt{9}} \)?
#real numbers
#rationalisation
#conjugate
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A \( \sqrt{10}-3 \)
B \( \sqrt{10}+3 \)
C \( \frac{\sqrt{10}-3}{19} \)
D \( \frac{1}{\sqrt{10}-3} \)
Explanation opens after your attempt
Correct Answer
A. \( \sqrt{10}-3 \)
Step 1
Concept
The denominator is \( \sqrt{10}+3 \) and its conjugate is \( \sqrt{10}-3 \). The denominator becomes (10-9=1).
Step 2
Why this answer is correct
The correct answer is A. \( \sqrt{10}-3 \). The denominator is \( \sqrt{10}+3 \) and its conjugate is \( \sqrt{10}-3 \). The denominator becomes (10-9=1).
Step 3
Exam Tip
हर \( \sqrt{10}+3 \) है और संयुग्मी \( \sqrt{10}-3 \) होगा। हर (10-9=1) बनता है।
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\( \frac{1}{\sqrt{11}-\sqrt{2}} \) का परिमेय हर वाला रूप क्या है?
What is the rationalised form of \( \frac{1}{\sqrt{11}-\sqrt{2}} \)?
#real numbers
#rationalisation
#binomial surd
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A \( \frac{\sqrt{11}+\sqrt{2}}{9} \)
B \( \sqrt{11}+\sqrt{2} \)
C \( \frac{\sqrt{11}-\sqrt{2}}{13} \)
D \( \frac{1}{9} \)
Explanation opens after your attempt
Correct Answer
A. \( \frac{\sqrt{11}+\sqrt{2}}{9} \)
Step 1
Concept
Multiply by the conjugate \( \sqrt{11}+\sqrt{2} \). The denominator becomes (11-2=9).
Step 2
Why this answer is correct
The correct answer is A. \( \frac{\sqrt{11}+\sqrt{2}}{9} \). Multiply by the conjugate \( \sqrt{11}+\sqrt{2} \). The denominator becomes (11-2=9).
Step 3
Exam Tip
संयुग्मी \( \sqrt{11}+\sqrt{2} \) से गुणा करें। हर (11-2=9) मिलेगा।
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\( \sqrt{98}+\sqrt{162}-\sqrt{50} \) का सरल रूप क्या है?
What is the simplified form of \( \sqrt{98}+\sqrt{162}-\sqrt{50} \)?
#real numbers
#surd simplification
#combined
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A \(11\sqrt{2}\)
B \(9\sqrt{2}\)
C \(13\sqrt{2}\)
D \(7\sqrt{2}\)
Explanation opens after your attempt
Correct Answer
A. \(11\sqrt{2}\)
Step 1
Concept
\( \sqrt{98}=7\sqrt{2} \), \( \sqrt{162}=9\sqrt{2} \), and \( \sqrt{50}=5\sqrt{2} \). So the result is \(11\sqrt{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(11\sqrt{2}\). \( \sqrt{98}=7\sqrt{2} \), \( \sqrt{162}=9\sqrt{2} \), and \( \sqrt{50}=5\sqrt{2} \). So the result is \(11\sqrt{2}\).
Step 3
Exam Tip
\( \sqrt{98}=7\sqrt{2} \), \( \sqrt{162}=9\sqrt{2} \), और \( \sqrt{50}=5\sqrt{2} \)। इसलिए परिणाम \(11\sqrt{2}\) है।
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\(2\sqrt{44}+3\sqrt{99}\) का सरल रूप क्या है?
What is the simplified form of \(2\sqrt{44}+3\sqrt{99}\)?
#real numbers
#like radicals
#addition
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A \(35\sqrt{11}\)
B \(13\sqrt{11}\)
C \(15\sqrt{11}\)
D \(11\sqrt{13}\)
Explanation opens after your attempt
Correct Answer
B. \(13\sqrt{11}\)
Step 1
Concept
\(2\sqrt{44}=4\sqrt{11}\) and \(3\sqrt{99}=9\sqrt{11}\). The sum is \(13\sqrt{11}\).
Step 2
Why this answer is correct
The correct answer is B. \(13\sqrt{11}\). \(2\sqrt{44}=4\sqrt{11}\) and \(3\sqrt{99}=9\sqrt{11}\). The sum is \(13\sqrt{11}\).
Step 3
Exam Tip
\(2\sqrt{44}=4\sqrt{11}\) और \(3\sqrt{99}=9\sqrt{11}\) है। योग \(13\sqrt{11}\) होगा।
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\( \sqrt{112}+2\sqrt{175} \) का सरल रूप क्या है?
What is the simplified form of \( \sqrt{112}+2\sqrt{175} \)?
#real numbers
#surd addition
#medium
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A \(26\sqrt{7}\)
B \(14\sqrt{7}\)
C \(24\sqrt{7}\)
D \(18\sqrt{7}\)
Explanation opens after your attempt
Correct Answer
B. \(14\sqrt{7}\)
Step 1
Concept
\( \sqrt{112}=4\sqrt{7} \) and \(2\sqrt{175}=10\sqrt{7}\). The sum is \(14\sqrt{7}\).
Step 2
Why this answer is correct
The correct answer is B. \(14\sqrt{7}\). \( \sqrt{112}=4\sqrt{7} \) and \(2\sqrt{175}=10\sqrt{7}\). The sum is \(14\sqrt{7}\).
Step 3
Exam Tip
\( \sqrt{112}=4\sqrt{7} \) और \(2\sqrt{175}=10\sqrt{7}\) है। योग \(14\sqrt{7}\) है।
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\(5\sqrt{48}-3\sqrt{75}\) का सरल रूप क्या है?
What is the simplified form of \(5\sqrt{48}-3\sqrt{75}\)?
#real numbers
#surds
#subtraction
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A \(5\sqrt{3}\)
B \(10\sqrt{3}\)
C \(25\sqrt{3}\)
D \(15\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(5\sqrt{3}\)
Step 1
Concept
\(5\sqrt{48}=20\sqrt{3}\) and \(3\sqrt{75}=15\sqrt{3}\). The difference is \(5\sqrt{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{3}\). \(5\sqrt{48}=20\sqrt{3}\) and \(3\sqrt{75}=15\sqrt{3}\). The difference is \(5\sqrt{3}\).
Step 3
Exam Tip
\(5\sqrt{48}=20\sqrt{3}\) और \(3\sqrt{75}=15\sqrt{3}\) है। अंतर \(5\sqrt{3}\) मिलता है।
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\( \sqrt{32}\times\sqrt{50} \) का मान क्या है?
What is the value of \( \sqrt{32}\times\sqrt{50} \)?
#real numbers
#surd multiplication
#perfect square
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A (40)
B (80)
C \(20\sqrt{2}\)
D \( \sqrt{82} \)
Explanation opens after your attempt
Step 1
Concept
\( \sqrt{32}\times\sqrt{50}=\sqrt{1600}=40 \). In radical multiplication, multiply the radicands.
Step 2
Why this answer is correct
The correct answer is A. (40). \( \sqrt{32}\times\sqrt{50}=\sqrt{1600}=40 \). In radical multiplication, multiply the radicands.
Step 3
Exam Tip
\( \sqrt{32}\times\sqrt{50}=\sqrt{1600}=40 \)। करणी गुणन में अंदर की संख्याएँ गुणा करें।
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\( \sqrt{180}\div\sqrt{20} \) का मान क्या है?
What is the value of \( \sqrt{180}\div\sqrt{20} \)?
#real numbers
#surd division
#square root
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A (9)
B (3)
C \( \sqrt{160} \)
D (6)
Explanation opens after your attempt
Step 1
Concept
\( \frac{\sqrt{180}}{\sqrt{20}}=\sqrt{9}=3 \). In division of square roots, divide the radicands.
Step 2
Why this answer is correct
The correct answer is B. (3). \( \frac{\sqrt{180}}{\sqrt{20}}=\sqrt{9}=3 \). In division of square roots, divide the radicands.
Step 3
Exam Tip
\( \frac{\sqrt{180}}{\sqrt{20}}=\sqrt{9}=3 \)। वर्गमूल के भाग में अंदर की संख्याओं का भाग लें।
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\( \frac{\sqrt{200}}{\sqrt{2}}+\sqrt{16} \) का मान क्या है?
What is the value of \( \frac{\sqrt{200}}{\sqrt{2}}+\sqrt{16} \)?
#real numbers
#mixed surds
#calculation
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A (14)
B (12)
C (18)
D (20)
Explanation opens after your attempt
Step 1
Concept
\( \frac{\sqrt{200}}{\sqrt{2}}=\sqrt{100}=10 \) and \( \sqrt{16}=4 \). The total value is (14).
Step 2
Why this answer is correct
The correct answer is A. (14). \( \frac{\sqrt{200}}{\sqrt{2}}=\sqrt{100}=10 \) and \( \sqrt{16}=4 \). The total value is (14).
Step 3
Exam Tip
\( \frac{\sqrt{200}}{\sqrt{2}}=\sqrt{100}=10 \) और \( \sqrt{16}=4 \)। कुल मान (14) है।
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\( \sqrt{1.69}+\sqrt{0.09} \) का मान क्या है?
What is the value of \( \sqrt{1.69}+\sqrt{0.09} \)?
#real numbers
#decimal square root
#addition
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A (1.6)
B (1.9)
C (2.2)
D (1.3)
Explanation opens after your attempt
Step 1
Concept
\( \sqrt{1.69}=1.3 \) and \( \sqrt{0.09}=0.3 \). The sum is (1.6).
Step 2
Why this answer is correct
The correct answer is A. (1.6). \( \sqrt{1.69}=1.3 \) and \( \sqrt{0.09}=0.3 \). The sum is (1.6).
Step 3
Exam Tip
\( \sqrt{1.69}=1.3 \) और \( \sqrt{0.09}=0.3 \) है। योग (1.6) होगा।
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\( \sqrt{4.84}-\sqrt{1.44} \) का मान क्या है?
What is the value of \( \sqrt{4.84}-\sqrt{1.44} \)?
#real numbers
#decimal radicals
#subtraction
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A (1)
B (1.2)
C (1.4)
D (2.2)
Explanation opens after your attempt
Step 1
Concept
\( \sqrt{4.84}=2.2 \) and \( \sqrt{1.44}=1.2 \). The difference is (1).
Step 2
Why this answer is correct
The correct answer is A. (1). \( \sqrt{4.84}=2.2 \) and \( \sqrt{1.44}=1.2 \). The difference is (1).
Step 3
Exam Tip
\( \sqrt{4.84}=2.2 \) और \( \sqrt{1.44}=1.2 \) है। अंतर (1) है।
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\( \sqrt{\frac{16}{25}}+\sqrt{\frac{9}{64}} \) का मान क्या है?
What is the value of \( \sqrt{\frac{16}{25}}+\sqrt{\frac{9}{64}} \)?
#real numbers
#fraction square roots
#addition
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A \( \frac{47}{40} \)
B \( \frac{17}{40} \)
C \( \frac{7}{13} \)
D \( \frac{31}{40} \)
Explanation opens after your attempt
Correct Answer
A. \( \frac{47}{40} \)
Step 1
Concept
The first term is \( \frac{4}{5} \) and the second is \( \frac{3}{8} \). The sum is \( \frac{32}{40}+\frac{15}{40}=\frac{47}{40} \).
Step 2
Why this answer is correct
The correct answer is A. \( \frac{47}{40} \). The first term is \( \frac{4}{5} \) and the second is \( \frac{3}{8} \). The sum is \( \frac{32}{40}+\frac{15}{40}=\frac{47}{40} \).
Step 3
Exam Tip
पहला पद \( \frac{4}{5} \) और दूसरा \( \frac{3}{8} \) है। योग \( \frac{32}{40}+\frac{15}{40}=\frac{47}{40} \) है।
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\( \sqrt{\frac{81}{121}}-\sqrt{\frac{4}{49}} \) का मान क्या है?
What is the value of \( \sqrt{\frac{81}{121}}-\sqrt{\frac{4}{49}} \)?
#real numbers
#fraction roots
#subtraction
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A \( \frac{35}{77} \)
B \( \frac{41}{77} \)
C \( \frac{29}{77} \)
D \( \frac{23}{77} \)
Explanation opens after your attempt
Correct Answer
B. \( \frac{41}{77} \)
Step 1
Concept
\( \sqrt{\frac{81}{121}}=\frac{9}{11} \) and \( \sqrt{\frac{4}{49}}=\frac{2}{7} \). The difference is \( \frac{63}{77}-\frac{22}{77}=\frac{41}{77} \).
Step 2
Why this answer is correct
The correct answer is B. \( \frac{41}{77} \). \( \sqrt{\frac{81}{121}}=\frac{9}{11} \) and \( \sqrt{\frac{4}{49}}=\frac{2}{7} \). The difference is \( \frac{63}{77}-\frac{22}{77}=\frac{41}{77} \).
Step 3
Exam Tip
\( \sqrt{\frac{81}{121}}=\frac{9}{11} \) और \( \sqrt{\frac{4}{49}}=\frac{2}{7} \) है। अंतर \( \frac{63}{77}-\frac{22}{77}=\frac{41}{77} \) है।
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कौन सा विकल्प (5) और (6) के बीच अपरिमेय संख्या है?
Which option is an irrational number between (5) and (6)?
#real numbers
#irrational between
#interval
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A \( \frac{11}{2} \)
B \( \sqrt{31} \)
C (5.5)
D \( \sqrt{36} \)
Explanation opens after your attempt
Correct Answer
B. \( \sqrt{31} \)
Step 1
Concept
Since \(5^2<31<6^2\), \( \sqrt{31} \) lies between (5) and (6). Since (31) is not a perfect square, it is irrational.
Step 2
Why this answer is correct
The correct answer is B. \( \sqrt{31} \). Since \(5^2<31<6^2\), \( \sqrt{31} \) lies between (5) and (6). Since (31) is not a perfect square, it is irrational.
Step 3
Exam Tip
\(5^2<31<6^2\) इसलिए \( \sqrt{31} \) (5) और (6) के बीच है। (31) पूर्ण वर्ग नहीं है इसलिए यह अपरिमेय है।
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\( \sqrt{45} \) और \( \frac{13}{2} \) में कौन बड़ा है?
Which is greater between \( \sqrt{45} \) and \( \frac{13}{2} \)?
#real numbers
#comparison
#ordering
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A \( \sqrt{45} \)
B \( \frac{13}{2} \)
C दोनों बराबर / Both are equal
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Correct Answer
A. \( \sqrt{45} \)
Step 1
Concept
\( \sqrt{45}\approx6.70 \) and \( \frac{13}{2}=6.5 \). Therefore \( \sqrt{45} \) is greater.
Step 2
Why this answer is correct
The correct answer is A. \( \sqrt{45} \). \( \sqrt{45}\approx6.70 \) and \( \frac{13}{2}=6.5 \). Therefore \( \sqrt{45} \) is greater.
Step 3
Exam Tip
\( \sqrt{45}\approx6.70 \) और \( \frac{13}{2}=6.5 \) है। इसलिए \( \sqrt{45} \) बड़ा है।
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\( \sqrt{68} \) किस दो पूर्णांकों के बीच है?
Between which two integers does \( \sqrt{68} \) lie?
#real numbers
#square root estimation
#number line
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A (6) और (7) / (6) and (7)
B (7) और (8) / (7) and (8)
C (8) और (9) / (8) and (9)
D (9) और (10) / (9) and (10)
Explanation opens after your attempt
Correct Answer
C. (8) और (9) / (8) and (9)
Step 1
Concept
\(8^2=64\) and \(9^2=81\), so \( \sqrt{68} \) lies between (8) and (9). Compare nearby perfect squares.
Step 2
Why this answer is correct
The correct answer is C. (8) और (9) / (8) and (9). \(8^2=64\) and \(9^2=81\), so \( \sqrt{68} \) lies between (8) and (9). Compare nearby perfect squares.
Step 3
Exam Tip
\(8^2=64\) और \(9^2=81\) है इसलिए \( \sqrt{68} \) (8) और (9) के बीच है। निकट पूर्ण वर्गों की तुलना करें।
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\( \sqrt{86} \) का स्थान किन दो पूर्णांकों के बीच होगा?
Between which two integers will \( \sqrt{86} \) lie?
#real numbers
#estimation
#roots
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A (7) और (8) / (7) and (8)
B (8) और (9) / (8) and (9)
C (9) और (10) / (9) and (10)
D (10) और (11) / (10) and (11)
Explanation opens after your attempt
Correct Answer
C. (9) और (10) / (9) and (10)
Step 1
Concept
\(9^2=81\) and \(10^2=100\), so \( \sqrt{86} \) lies between (9) and (10). Check the range by squaring.
Step 2
Why this answer is correct
The correct answer is C. (9) और (10) / (9) and (10). \(9^2=81\) and \(10^2=100\), so \( \sqrt{86} \) lies between (9) and (10). Check the range by squaring.
Step 3
Exam Tip
\(9^2=81\) और \(10^2=100\) है इसलिए \( \sqrt{86} \) (9) और (10) के बीच है। वर्ग करके सीमा जाँचें।
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\( -\sqrt{50} \) और ( -7.2 ) में कौन बड़ी संख्या है?
Which is greater between \( -\sqrt{50} \) and ( -7.2 )?
#real numbers
#negative comparison
#number line
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A \( -\sqrt{50} \)
B ( -7.2 )
C दोनों बराबर / Both are equal
D दोनों धनात्मक / Both are positive
Explanation opens after your attempt
Correct Answer
A. \( -\sqrt{50} \)
Step 1
Concept
\( \sqrt{50}\approx7.07 \), so \( -\sqrt{50}\approx-7.07 \). It is greater than ( -7.2 ) because it is closer to zero.
Step 2
Why this answer is correct
The correct answer is A. \( -\sqrt{50} \). \( \sqrt{50}\approx7.07 \), so \( -\sqrt{50}\approx-7.07 \). It is greater than ( -7.2 ) because it is closer to zero.
Step 3
Exam Tip
\( \sqrt{50}\approx7.07 \) इसलिए \( -\sqrt{50}\approx-7.07 \)। यह ( -7.2 ) से बड़ी है क्योंकि यह शून्य के अधिक निकट है।
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(0.2020020002...) यदि कोई स्थिर आवृत्ति नहीं रखता है तो यह किस प्रकार की संख्या है?
If (0.2020020002...) has no fixed repetition, what type of number is it?
#real numbers
#irrational decimal
#classification
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A परिमेय संख्या / Rational number
B अपरिमेय वास्तविक संख्या / Irrational real number
C पूर्णांक / Integer
D समाप्त दशमलव / Terminating decimal
Explanation opens after your attempt
Correct Answer
B. अपरिमेय वास्तविक संख्या / Irrational real number
Step 1
Concept
A non-terminating and non-repeating decimal is irrational. Identify the difference between repeating and non-repeating.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय वास्तविक संख्या / Irrational real number. A non-terminating and non-repeating decimal is irrational. Identify the difference between repeating and non-repeating.
Step 3
Exam Tip
असमाप्त और अनावर्ती दशमलव अपरिमेय होता है। आवर्ती और अनावर्ती में अंतर पहचानें।
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(3.454545...) किस प्रकार की वास्तविक संख्या है?
What type of real number is (3.454545...)?
#real numbers
#repeating decimal
#rational
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A अपरिमेय संख्या / Irrational number
B परिमेय वास्तविक संख्या / Rational real number
C केवल पूर्णांक / Only integer
D अपरिभाषित संख्या / Undefined number
Explanation opens after your attempt
Correct Answer
B. परिमेय वास्तविक संख्या / Rational real number
Step 1
Concept
The block (45) repeats, so the decimal is repeating. Repeating decimals are rational.
Step 2
Why this answer is correct
The correct answer is B. परिमेय वास्तविक संख्या / Rational real number. The block (45) repeats, so the decimal is repeating. Repeating decimals are rational.
Step 3
Exam Tip
(45) बार-बार आ रहा है इसलिए दशमलव आवर्ती है। आवर्ती दशमलव परिमेय होते हैं।
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(0.070070007...) यदि कोई नियमित आवृत्ति नहीं है तो यह क्या है?
If (0.070070007...) has no regular repetition, what is it?
#real numbers
#non repeating decimal
#irrational
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A परिमेय संख्या / Rational number
B पूर्ण संख्या / Whole number
C अपरिमेय वास्तविक संख्या / Irrational real number
D प्राकृतिक संख्या / Natural number
Explanation opens after your attempt
Correct Answer
C. अपरिमेय वास्तविक संख्या / Irrational real number
Step 1
Concept
A non-terminating decimal without regular repetition is irrational. Only fixed repeating decimals are rational.
Step 2
Why this answer is correct
The correct answer is C. अपरिमेय वास्तविक संख्या / Irrational real number. A non-terminating decimal without regular repetition is irrational. Only fixed repeating decimals are rational.
Step 3
Exam Tip
नियमित आवृत्ति न होने पर असमाप्त दशमलव अपरिमेय होता है। केवल स्थिर आवर्ती दशमलव परिमेय होते हैं।
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\( \frac{8}{13} \) के दशमलव रूप के बारे में सही कथन क्या है?
What is the correct statement about the decimal form of \( \frac{8}{13} \)?
#real numbers
#decimal expansion
#rational
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A यह समाप्त दशमलव है / It is terminating
B यह असमाप्त आवर्ती दशमलव है / It is non-terminating repeating
C यह अपरिभाषित है / It is undefined
D यह पूर्णांक है / It is an integer
Explanation opens after your attempt
Correct Answer
B. यह असमाप्त आवर्ती दशमलव है / It is non-terminating repeating
Step 1
Concept
The denominator (13) has factors other than (2) or (5). Therefore the decimal will be non-terminating repeating.
Step 2
Why this answer is correct
The correct answer is B. यह असमाप्त आवर्ती दशमलव है / It is non-terminating repeating. The denominator (13) has factors other than (2) or (5). Therefore the decimal will be non-terminating repeating.
Step 3
Exam Tip
हर (13) में (2) या (5) के अलावा गुणनखंड है। इसलिए दशमलव असमाप्त आवर्ती होगा।
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\( \frac{21}{80} \) के दशमलव रूप के बारे में सही कथन क्या है?
What is the correct statement about the decimal form of \( \frac{21}{80} \)?
#real numbers
#terminating decimal
#denominator
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A यह समाप्त दशमलव है / It is terminating
B यह अपरिमेय है / It is irrational
C यह अपरिभाषित है / It is undefined
D यह असमाप्त अनावर्ती है / It is non-terminating non-repeating
Explanation opens after your attempt
Correct Answer
A. यह समाप्त दशमलव है / It is terminating
Step 1
Concept
\(80=2^4\times5\), so the denominator has only (2) and (5). Such a fraction gives a terminating decimal.
Step 2
Why this answer is correct
The correct answer is A. यह समाप्त दशमलव है / It is terminating. \(80=2^4\times5\), so the denominator has only (2) and (5). Such a fraction gives a terminating decimal.
Step 3
Exam Tip
\(80=2^4\times5\) है इसलिए हर में केवल (2) और (5) हैं। ऐसा भिन्न समाप्त दशमलव देता है।
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\( \frac{5}{42} \) के दशमलव रूप के बारे में सही कथन क्या है?
What is the correct statement about the decimal form of \( \frac{5}{42} \)?
#real numbers
#decimal expansion
#recurring
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A यह समाप्त दशमलव है / It is terminating
B यह असमाप्त आवर्ती दशमलव है / It is non-terminating repeating decimal
C यह अपरिमेय है / It is irrational
D यह पूर्णांक है / It is an integer
Explanation opens after your attempt
Correct Answer
B. यह असमाप्त आवर्ती दशमलव है / It is non-terminating repeating decimal
Step 1
Concept
\(42=2\times3\times7\) has (3) and (7). So the decimal will not terminate but will repeat.
Step 2
Why this answer is correct
The correct answer is B. यह असमाप्त आवर्ती दशमलव है / It is non-terminating repeating decimal. \(42=2\times3\times7\) has (3) and (7). So the decimal will not terminate but will repeat.
Step 3
Exam Tip
\(42=2\times3\times7\) में (3) और (7) हैं। इसलिए दशमलव समाप्त नहीं होगा लेकिन आवर्ती होगा।
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\( \frac{29}{200} \) दशमलव रूप में किस प्रकार का होगा?
What type will \( \frac{29}{200} \) be in decimal form?
#real numbers
#terminating decimal
#factorisation
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A समाप्त दशमलव / Terminating decimal
B असमाप्त अनावर्ती दशमलव / Non-terminating non-repeating decimal
C अपरिमेय संख्या / Irrational number
D अपरिभाषित संख्या / Undefined number
Explanation opens after your attempt
Correct Answer
A. समाप्त दशमलव / Terminating decimal
Step 1
Concept
\(200=2^3\times5^2\), so the denominator has only (2) and (5). Such a fraction gives a terminating decimal.
Step 2
Why this answer is correct
The correct answer is A. समाप्त दशमलव / Terminating decimal. \(200=2^3\times5^2\), so the denominator has only (2) and (5). Such a fraction gives a terminating decimal.
Step 3
Exam Tip
\(200=2^3\times5^2\) है इसलिए हर में केवल (2) और (5) हैं। ऐसा भिन्न समाप्त दशमलव देता है।
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\( \frac{31}{45} \) का दशमलव विस्तार कैसा होगा?
What will be the decimal expansion of \( \frac{31}{45} \)?
#real numbers
#decimal expansion
#medium
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A समाप्त / Terminating
B असमाप्त आवर्ती / Non-terminating repeating
C असमाप्त अनावर्ती / Non-terminating non-repeating
D अपरिभाषित / Undefined
Explanation opens after your attempt
Correct Answer
B. असमाप्त आवर्ती / Non-terminating repeating
Step 1
Concept
\(45=3^2\times5\) also has (3). Therefore it will be a non-terminating repeating decimal.
Step 2
Why this answer is correct
The correct answer is B. असमाप्त आवर्ती / Non-terminating repeating. \(45=3^2\times5\) also has (3). Therefore it will be a non-terminating repeating decimal.
Step 3
Exam Tip
\(45=3^2\times5\) में (3) भी है। इसलिए यह असमाप्त आवर्ती दशमलव होगा।
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\( \sqrt{6}+\sqrt{24} \) किसके बराबर है?
What is \( \sqrt{6}+\sqrt{24} \) equal to?
#real numbers
#irrational sum
#surds
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A \(3\sqrt{6}\)
B \( \sqrt{30} \)
C \(2\sqrt{6}\)
D \(6\sqrt{2}\)
Explanation opens after your attempt
Correct Answer
A. \(3\sqrt{6}\)
Step 1
Concept
\( \sqrt{24}=2\sqrt{6} \). Therefore \( \sqrt{6}+2\sqrt{6}=3\sqrt{6} \).
Step 2
Why this answer is correct
The correct answer is A. \(3\sqrt{6}\). \( \sqrt{24}=2\sqrt{6} \). Therefore \( \sqrt{6}+2\sqrt{6}=3\sqrt{6} \).
Step 3
Exam Tip
\( \sqrt{24}=2\sqrt{6} \) है। इसलिए \( \sqrt{6}+2\sqrt{6}=3\sqrt{6} \)।
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\( \sqrt{12}\times\sqrt{75} \) किस प्रकार की संख्या है?
What type of number is \( \sqrt{12}\times\sqrt{75} \)?
#real numbers
#surd product
#rational result
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A परिमेय वास्तविक संख्या / Rational real number
B अपरिमेय वास्तविक संख्या / Irrational real number
C अपरिभाषित संख्या / Undefined number
D असमाप्त अनावर्ती दशमलव / Non-terminating non-repeating decimal
Explanation opens after your attempt
Correct Answer
A. परिमेय वास्तविक संख्या / Rational real number
Step 1
Concept
\( \sqrt{12}\times\sqrt{75}=\sqrt{900}=30 \). Therefore the result is a rational real number.
Step 2
Why this answer is correct
The correct answer is A. परिमेय वास्तविक संख्या / Rational real number. \( \sqrt{12}\times\sqrt{75}=\sqrt{900}=30 \). Therefore the result is a rational real number.
Step 3
Exam Tip
\( \sqrt{12}\times\sqrt{75}=\sqrt{900}=30 \) है। इसलिए परिणाम परिमेय वास्तविक संख्या है।
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\( \sqrt{3}\times\sqrt{21} \) किस प्रकार की संख्या है?
What type of number is \( \sqrt{3}\times\sqrt{21} \)?
#real numbers
#surd multiplication
#classification
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A परिमेय संख्या / Rational number
B अपरिमेय वास्तविक संख्या / Irrational real number
C पूर्णांक / Integer
D समाप्त दशमलव / Terminating decimal
Explanation opens after your attempt
Correct Answer
B. अपरिमेय वास्तविक संख्या / Irrational real number
Step 1
Concept
\( \sqrt{3}\times\sqrt{21}=\sqrt{63}=3\sqrt{7} \). This is an irrational real number.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय वास्तविक संख्या / Irrational real number. \( \sqrt{3}\times\sqrt{21}=\sqrt{63}=3\sqrt{7} \). This is an irrational real number.
Step 3
Exam Tip
\( \sqrt{3}\times\sqrt{21}=\sqrt{63}=3\sqrt{7} \) है। यह अपरिमेय वास्तविक संख्या है।
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\(3+\sqrt{14}\) और \(3-\sqrt{14}\) का गुणनफल क्या है?
What is the product of \(3+\sqrt{14}\) and \(3-\sqrt{14}\)?
#real numbers
#conjugate
#product
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A (5)
B ( -5 )
C (23)
D \(9+\sqrt{14}\)
Explanation opens after your attempt
Step 1
Concept
Conjugate multiplication gives (32 -\(\sqrt{14}\)2 =9-14=-5). Use the difference of squares rule.
Step 2
Why this answer is correct
The correct answer is B. ( -5 ). Conjugate multiplication gives (32 -\(\sqrt{14}\)2 =9-14=-5). Use the difference of squares rule.
Step 3
Exam Tip
संयुग्मी गुणन से (32 -\(\sqrt{14}\)2 =9-14=-5) मिलता है। अंतर के वर्ग का नियम लगाएँ।
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\( \frac{3+\sqrt{2}}{3-\sqrt{2}} \) का परिमेय हर करने पर मान क्या होगा?
What is the value of \( \frac{3+\sqrt{2}}{3-\sqrt{2}} \) after rationalising?
#real numbers
#rationalisation
#advanced
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A \( \frac{11+6\sqrt{2}}{7} \)
B \( \frac{7+6\sqrt{2}}{11} \)
C (1)
D \( \frac{9+\sqrt{2}}{7} \)
Explanation opens after your attempt
Correct Answer
A. \( \frac{11+6\sqrt{2}}{7} \)
Step 1
Concept
Multiply by the conjugate \(3+\sqrt{2}\). The numerator is (\(3+\sqrt{2}\)2 =11+6\sqrt{2}) and the denominator is (7).
Step 2
Why this answer is correct
The correct answer is A. \( \frac{11+6\sqrt{2}}{7} \). Multiply by the conjugate \(3+\sqrt{2}\). The numerator is (\(3+\sqrt{2}\)2 =11+6\sqrt{2}) and the denominator is (7).
Step 3
Exam Tip
हर के संयुग्मी \(3+\sqrt{2}\) से गुणा करें। अंश (\(3+\sqrt{2}\)2 =11+6\sqrt{2}) और हर (7) होगा।
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\( \frac{\sqrt{7}+2}{\sqrt{7}-2} \) का हर परिमेय करने के बाद हर क्या होगा?
What will be the denominator after rationalising \( \frac{\sqrt{7}+2}{\sqrt{7}-2} \)?
#real numbers
#rationalisation
#denominator
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A (3)
B (7)
C (5)
D (11)
Explanation opens after your attempt
Step 1
Concept
Multiplying by the conjugate \( \sqrt{7}+2 \) makes the denominator (7-4=3). Use difference of squares in the conjugate method.
Step 2
Why this answer is correct
The correct answer is A. (3). Multiplying by the conjugate \( \sqrt{7}+2 \) makes the denominator (7-4=3). Use difference of squares in the conjugate method.
Step 3
Exam Tip
हर के संयुग्मी \( \sqrt{7}+2 \) से गुणा करने पर हर (7-4=3) होगा। संयुग्मी विधि में अंतर के वर्ग का प्रयोग करें।
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\( |-\sqrt{64}+5| \) का मान क्या है?
What is the value of \( |-\sqrt{64}+5| \)?
#real numbers
#absolute value
#square root
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A (3)
B ( -3 )
C (13)
D (8)
Explanation opens after your attempt
Step 1
Concept
\( -\sqrt{64}+5=-8+5=-3 \) and ( |-3|=3 ). Absolute value gives distance.
Step 2
Why this answer is correct
The correct answer is A. (3). \( -\sqrt{64}+5=-8+5=-3 \) and ( |-3|=3 ). Absolute value gives distance.
Step 3
Exam Tip
\( -\sqrt{64}+5=-8+5=-3 \) है और ( |-3|=3 )। निरपेक्ष मान दूरी देता है।
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\( |\sqrt{25}-\sqrt{100}| \) का मान क्या है?
What is the value of \( |\sqrt{25}-\sqrt{100}| \)?
#real numbers
#absolute value
#calculation
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A (5)
B (15)
C ( -5 )
D (10)
Explanation opens after your attempt
Step 1
Concept
\( \sqrt{25}=5 \) and \( \sqrt{100}=10 \). So ( |5-10|=5 ).
Step 2
Why this answer is correct
The correct answer is A. (5). \( \sqrt{25}=5 \) and \( \sqrt{100}=10 \). So ( |5-10|=5 ).
Step 3
Exam Tip
\( \sqrt{25}=5 \) और \( \sqrt{100}=10 \) है। ( |5-10|=5 ) होगा।
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( \sqrt{( -9)2 } ) का मान क्या है?
What is the value of ( \sqrt{( -9)2 } )?
#real numbers
#absolute value
#concept
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A ( -9 )
B (9)
C (81)
D \( \sqrt{-81} \)
Explanation opens after your attempt
Step 1
Concept
In real numbers, \( \sqrt{a^2}=|a| \). Therefore ( \sqrt{( -9)2 }=9 ).
Step 2
Why this answer is correct
The correct answer is B. (9). In real numbers, \( \sqrt{a^2}=|a| \). Therefore ( \sqrt{( -9)2 }=9 ).
Step 3
Exam Tip
वास्तविक संख्याओं में \( \sqrt{a^2}=|a| \) होता है। इसलिए ( \sqrt{( -9)2 }=9 )।
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यदि (x=-8) है तो \( \sqrt{x^2}+x \) का मान क्या होगा?
If (x=-8), what is the value of \( \sqrt{x^2}+x \)?
#real numbers
#absolute value
#substitution
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A (0)
B ( -16 )
C (16)
D (8)
Explanation opens after your attempt
Step 1
Concept
\( \sqrt{x^2}=|x| \). When (x=-8), we get (8+(-8)=0).
Step 2
Why this answer is correct
The correct answer is A. (0). \( \sqrt{x^2}=|x| \). When (x=-8), we get (8+(-8)=0).
Step 3
Exam Tip
\( \sqrt{x^2}=|x| \) होता है। (x=-8) होने पर (8+(-8)=0) मिलेगा।
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\( \frac{1}{5+2\sqrt{6}} \) का परिमेय हर वाला रूप क्या है?
What is the rationalised form of \( \frac{1}{5+2\sqrt{6}} \)?
#real numbers
#rationalisation
#conjugate
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A \(5+2\sqrt{6}\)
B \( \frac{5-2\sqrt{6}}{49} \)
C \(2\sqrt{6}-5\)
D \(5-2\sqrt{6}\)
Explanation opens after your attempt
Correct Answer
D. \(5-2\sqrt{6}\)
Step 1
Concept
Multiplying by the conjugate \(5-2\sqrt{6}\) makes the denominator (25-24=1). So the rationalised form is \(5-2\sqrt{6}\).
Step 2
Why this answer is correct
The correct answer is D. \(5-2\sqrt{6}\). Multiplying by the conjugate \(5-2\sqrt{6}\) makes the denominator (25-24=1). So the rationalised form is \(5-2\sqrt{6}\).
Step 3
Exam Tip
संयुग्मी \(5-2\sqrt{6}\) से गुणा करने पर हर (25-24=1) बनता है। इसलिए परिमेय हर वाला रूप \(5-2\sqrt{6}\) है।
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\( \sqrt{242}-\sqrt{128} \) का सरल रूप क्या है?
What is the simplified form of \( \sqrt{242}-\sqrt{128} \)?
#real numbers
#surd subtraction
#simplification
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A \(19\sqrt{2}\)
B \(5\sqrt{2}\)
C \(3\sqrt{2}\)
D \( \sqrt{114} \)
Explanation opens after your attempt
Correct Answer
C. \(3\sqrt{2}\)
Step 1
Concept
\( \sqrt{242}=11\sqrt{2} \) and \( \sqrt{128}=8\sqrt{2} \). Therefore the difference is \(3\sqrt{2}\).
Step 2
Why this answer is correct
The correct answer is C. \(3\sqrt{2}\). \( \sqrt{242}=11\sqrt{2} \) and \( \sqrt{128}=8\sqrt{2} \). Therefore the difference is \(3\sqrt{2}\).
Step 3
Exam Tip
\( \sqrt{242}=11\sqrt{2} \) और \( \sqrt{128}=8\sqrt{2} \) है। इसलिए अंतर \(3\sqrt{2}\) मिलता है।
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