\( \frac{3+\sqrt{2}}{3-\sqrt{2}} \) का परिमेय हर करने पर मान क्या होगा?

What is the value of \( \frac{3+\sqrt{2}}{3-\sqrt{2}} \) after rationalising?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \frac{11+6\sqrt{2}}{7} \)

Step 1

Concept

Multiply by the conjugate \(3+\sqrt{2}\). The numerator is (\(3+\sqrt{2}\)2=11+6\sqrt{2}) and the denominator is (7).

Step 2

Why this answer is correct

The correct answer is A. \( \frac{11+6\sqrt{2}}{7} \). Multiply by the conjugate \(3+\sqrt{2}\). The numerator is (\(3+\sqrt{2}\)2=11+6\sqrt{2}) and the denominator is (7).

Step 3

Exam Tip

हर के संयुग्मी \(3+\sqrt{2}\) से गुणा करें। अंश (\(3+\sqrt{2}\)2=11+6\sqrt{2}) और हर (7) होगा।

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Mathematics Answer, Explanation and Revision Hints

\( \frac{3+\sqrt{2}}{3-\sqrt{2}} \) का परिमेय हर करने पर मान क्या होगा? / What is the value of \( \frac{3+\sqrt{2}}{3-\sqrt{2}} \) after rationalising?

Correct Answer: A. \( \frac{11+6\sqrt{2}}{7} \). Explanation: हर के संयुग्मी \(3+\sqrt{2}\) से गुणा करें। अंश (\(3+\sqrt{2}\)2=11+6\sqrt{2}) और हर (7) होगा। / Multiply by the conjugate \(3+\sqrt{2}\). The numerator is (\(3+\sqrt{2}\)2=11+6\sqrt{2}) and the denominator is (7).

Which concept should I revise for this Mathematics MCQ?

Multiply by the conjugate \(3+\sqrt{2}\). The numerator is (\(3+\sqrt{2}\)2=11+6\sqrt{2}) and the denominator is (7).

What exam hint can help solve this Mathematics question?

हर के संयुग्मी \(3+\sqrt{2}\) से गुणा करें। अंश (\(3+\sqrt{2}\)2=11+6\sqrt{2}) और हर (7) होगा।