Rational numbers

Correct answer: B. C={21,28}

The governing idea is interpreting an open interval. The multiples of 7 from this range are 14,21,28,35. Because “between 14 and 35” excludes both endpoints, only 21 and 28 remain. Therefore option B is correct. Option A includes both endpoints, C includes 7 and 14, and D includes the excluded endpoint 35. The wording would need “inclusive” or “from 14 to 35” to include the endpoints.

Correct answer: C. S={-3,3}

Solving x²=9 over the integers requires considering both square roots of 9. Since 3²=9 and (-3)²=9, the integer solutions are x=3 and x=-3. A set lists both distinct solutions, so S={-3,3}. Option A and option B each omit one valid solution, while option D contains values that do not all satisfy the equation. Therefore C is correct.

Correct answer: B. (11)

Direct answer: Option B is correct. To find the value of an algebraic expression, substitute the given value of the variable first and then follow the operations. Here, the variable is x and its value is 3. Replace x by 3: 2x+5 becomes 2(3)+5. Multiply before adding: 2(3)=6. Then add 5: 6+5=11. Thus the answer is 11, which is option B. Option A, 8, would result from an incorrect operation such as adding 3 and 5 while forgetting the coefficient 2. Option B is correct because it follows direct substitution and multiplication. Option C, 13, may come from adding incorrectly or using an unsupported operation; it is not the value of the expression. Option D, 15, is also obtained by an incorrect calculation and does not follow the stated expression. Exam cue: replace the letter, use brackets, multiply first, and add last.

Correct answer: A. Can be written as ( \frac{p}{q} ) where (q \neq 0)

A rational number can be written as ( \frac{p}{q} ) where the denominator is not zero. Always check the denominator in exams.

Correct answer: B. Rational number

The governing concept is the definition of a rational number. A number is rational if it can be written in the form p/q, where p and q are integers and q is not zero. The fraction 3/5 already has this form: the numerator 3 is an integer, the denominator 5 is an integer, and 5 is not zero. Therefore, option B is correct. It is not irrational because irrational numbers cannot be expressed as a ratio of two integers. Although 3 is a natural and whole number, the fraction 3/5 is not itself a whole number or a natural number. Its decimal form, 0.6, also terminates, which provides another familiar indication that it is rational.

Correct answer: C. ( \frac{-7}{4} )

( \frac{-7}{4} ) is a ratio of two integers with non-zero denominator. The given square-root numbers are not in simple rational form.

Correct answer: A. \(\frac{0}{5}\)

A number is rational if it can be written as \(\frac{p}{q}\), where \(p\) and \(q\) are integers and \(q\neq 0\). Thus, \(\frac{0}{5}=0\) is a valid representation. Options B and D are undefined because their denominators are zero, and option C, \(\frac{0}{0}\), is also undefined. Exam tip: the denominator of a rational-number fraction can never be zero.

Correct answer: B. ( \frac{3}{4} )

Dividing both (6) and (8) by (2) gives ( \frac{3}{4} ). Remove common factors for simplest form.

Correct answer: A. -3/4

The governing concept is the standard form of a rational number. In standard form, the denominator must be positive and the numerator and denominator must have no common factor other than 1. Starting with -9/12, the greatest common divisor of 9 and 12 is 3. Dividing both numerator and denominator by 3 gives -9/12 = -3/4. The denominator 4 is positive, and 3 and 4 are coprime, so option A is correct. Option B has the same numerical value but leaves the denominator negative, so it is not the standard form. Option C is not obtained by reducing the fraction, and option D changes the sign and is not equivalent to the original negative fraction.

Correct answer: C. ( \frac{8}{12} )

Multiplying ( \frac{2}{3} ) by (4) gives ( \frac{8}{12} ). For equivalent fractions multiply numerator and denominator by the same number.

Correct answer: B. \(-\frac{5}{7}\)

The additive inverse is the number that sums with the original number to give zero. Since \(\frac{5}{7}+\left(-\frac{5}{7}\right)=0\), the additive inverse is \(-\frac{5}{7}\).

Correct answer: B. -9/4

The governing concept is the multiplicative inverse, or reciprocal, of a nonzero rational number. The multiplicative inverse of a/b is b/a, provided a is not zero, because their product must equal 1. For -4/9, interchange the numerator and denominator while retaining the negative sign: the inverse is -9/4. Verification gives (-4/9) × (-9/4) = 36/36 = 1, so option B is correct. Option A loses the negative sign and its product with -4/9 is -1. Option C is the original number, not its inverse. Option D is equivalent to 4/9 because both signs are negative, so it also loses the required negative sign. The sign and reciprocal operation must both be handled correctly.

Correct answer: C. ( \frac{5}{6} )

Taking common denominator (6), ( \frac{3}{6}+\frac{2}{6}=\frac{5}{6} ). Use LCM while adding fractions.

Correct answer: B. \(\frac{1}{2}\)

Both fractions have the same denominator \(10\). So subtract numerators: \(\frac{7}{10}-\frac{2}{10}=\frac{7-2}{10}=\frac{5}{10}=\frac{1}{2}\).

Correct answer: B. ( \frac{3}{10} )

Direct answer: Option B, \(\frac{3}{10}\). To multiply fractions, multiply the numerators together and multiply the denominators together. The numerators are 3 and 2, so the numerator becomes \(3\times2=6\). The denominators are 4 and 5, so the denominator becomes \(4\times5=20\). Thus the product is \(\frac{6}{20}\). Divide numerator and denominator by their common factor 2: \(\frac{6\div2}{20\div2}=\frac{3}{10}\). Option A, \(\frac{5}{9}\), comes from adding or combining numbers incorrectly and is not the product. Option B is correct because it is the simplified product. Option C, \(\frac{6}{9}\), uses neither the correct denominator nor correct simplification. Option D, \(\frac{1}{20}\), loses the factor 3 and is therefore too small. A safe check is that \(\frac34\) is less than 1 and \(\frac25\) is less than 1, so the answer should be positive and less than either factor; \(\frac3{10}\) fits. Remember: fraction multiplication is numerator times numerator and denominator times denominator.

Correct answer: A. ( \frac{1}{4} )

Change division into multiplication by the reciprocal of the second fraction. ( \frac{5}{6}\times\frac{3}{10}=\frac{1}{4} ).

Correct answer: C. \(\frac{5}{9}\)

Both fractions have the same denominator, 9. When denominators are equal, compare the numerators; the fraction with the greater numerator is larger. Since 5 > 4, \(\frac{5}{9} > \frac{4}{9}\), so option C is correct. Exam tip: For fractions with equal denominators, compare only their numerators.

Correct answer: A. ( \frac{3}{8} )

( \frac{1}{2}=\frac{4}{8} ), so ( \frac{3}{8} ) is smaller. Making common denominators helps in comparison.

Correct answer: C. ( \frac{-1}{5} )

( \frac{-1}{5} ) lies between ( \frac{-2}{5} ) and ( \frac{1}{5} ) on the number line. Be careful with the direction of negative numbers.

Correct answer: B. ( \frac{1}{2} )

( \frac{1}{2}=\frac{2}{4} ), which lies between ( \frac{1}{4} ) and ( \frac{3}{4} ). Use common denominators to find a middle number.

Correct answer: D. ( \frac{4}{0} )

The direct answer is D, \\(\frac{4}{0}\\). A fraction is defined only when its denominator is not zero, because division asks how many times the denominator fits into the numerator, and division by zero has no defined value. Check the options carefully. In A, \\(\frac{8}{2}\\) has denominator 2, so it is defined and equals 4. In B, \\(\frac{0}{6}\\) has denominator 6, so it is defined and equals 0. In C, \\(\frac{-3}{7}\\) has denominator 7, so it is defined, even though its value is negative. In D, the denominator is 0, so \\(\frac{4}{0}\\) is undefined; it cannot be treated as an ordinary rational number. Thus D is correct. Remember: a rational number has the form \\(\frac{p}{q}\\) with integers p and q and the condition \\(q\ne0\\).

Correct answer: A. -6/1

The governing concept is the definition of a rational number: it is any number that can be written as p/q, where p and q are integers and q is not zero. The integer -6 can therefore be represented by placing it over 1: -6/1 = -6. Option A is correct because its denominator is non-zero and its value is exactly -6. Option B equals -1/6, not -6. Option C is invalid because division by zero is undefined. Option D equals 0, so it also does not represent -6. Thus every integer, including a negative integer, is rational because it can be divided by 1.

Correct answer: A. Every integer is a rational number

Any integer can be written in the form \(\frac{p}{1}\), where \(p\) is an integer and the denominator is non-zero. Therefore, every integer is a rational number. Option B is false because rational numbers such as \(\frac{1}{2}\) and \(-3\) are not natural numbers. A fraction with a zero denominator is undefined, not rational. Exam tip: the denominator of a rational number must always be non-zero.

Correct answer: B. ( \frac{1}{3} )

The direct answer is B, \\(\frac{1}{3}\\). The bar over 3 means that 3 repeats forever: \\(0.\overline{3}=0.3333\ldots\\). Let \\(x=0.\overline{3}\\). Multiplying by 10 gives \\(10x=3.\overline{3}\\). Subtract the first equation: \\(10x-x=3.\overline{3}-0.\overline{3}\\), so \\(9x=3\\). Dividing by 9 gives \\(x=\frac{3}{9}=\frac{1}{3}\\). Option A, \\(\frac{3}{10}\\), represents 0.3 with only one 3, not an endlessly repeating 3. Option B is correct because its decimal expansion is 0.3333... . Option C, \\(\frac{3}{100}\\), represents 0.03, not 0.333... . Option D, \\(\frac{10}{3}\\), is greater than 3 and has decimal value 3.333..., so it is not the given number. Memory cue: one repeating digit can be converted by placing that digit over 9, so repeating 3 gives \\(\frac{3}{9}=\frac{1}{3}\\).

Correct answer: C. (-2) and (-1)

( \frac{-3}{2}=-1.5 ), which lies between (-2) and (-1). Place negative decimals carefully on the number line.