\( \sqrt{98}+\sqrt{162}-\sqrt{50} \) का सरल रूप क्या है?
What is the simplified form of \( \sqrt{98}+\sqrt{162}-\sqrt{50} \)?
Explanation opens after your attempt
Correct Answer
A. \(11\sqrt{2}\)
Concept
\( \sqrt{98}=7\sqrt{2} \), \( \sqrt{162}=9\sqrt{2} \), and \( \sqrt{50}=5\sqrt{2} \). So the result is \(11\sqrt{2}\).
Why this answer is correct
The correct answer is A. \(11\sqrt{2}\). \( \sqrt{98}=7\sqrt{2} \), \( \sqrt{162}=9\sqrt{2} \), and \( \sqrt{50}=5\sqrt{2} \). So the result is \(11\sqrt{2}\).
Exam Tip
\( \sqrt{98}=7\sqrt{2} \), \( \sqrt{162}=9\sqrt{2} \), और \( \sqrt{50}=5\sqrt{2} \)। इसलिए परिणाम \(11\sqrt{2}\) है।
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