Question
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29
समीकरण \(x^2-8x+16=0\) में (x=4) रखने पर क्या मिलता है?
What do we get by putting (x=4) in \(x^2-8x+16=0\)?
Explanation opens after your attempt
Step 1
Concept
We get \(4^2-8\cdot4+16=0\). So (x=4) satisfies the equation.
Step 2
Why this answer is correct
The correct answer is A. (0=0). We get \(4^2-8\cdot4+16=0\). So (x=4) satisfies the equation.
Step 3
Exam Tip
\(4^2-8\cdot4+16=0\) मिलता है। इसलिए (x=4) समीकरण को संतुष्ट करता है।
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Question
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28
यदि (x=2) है तो \(x^2-5x+6=0\) में बायां पक्ष कितना होगा?
If (x=2), what is the left side of \(x^2-5x+6=0\)?
Explanation opens after your attempt
Step 1
Concept
Substitution gives \(2^2-5\cdot2+6=0\). So (x=2) is a solution.
Step 2
Why this answer is correct
The correct answer is A. (0). Substitution gives \(2^2-5\cdot2+6=0\). So (x=2) is a solution.
Step 3
Exam Tip
रखने पर \(2^2-5\cdot2+6=0\) मिलता है। इसलिए (x=2) समीकरण का हल है।
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