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one-root MCQ Questions for Class 10

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10 questions tagged with one-root.

Question 1/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि (x-2-(m+7)x+7m=0) का एक मूल (7) है, तो दूसरा मूल क्या है?

If one root of (x-2-(m+7)x+7m=0) is (7), what is the other root?

Explanation opens after your attempt
Correct Answer

A. (m)

Step 1

Concept

The product of roots is (7m) and one root is (7). Hence the other root is \(\frac{7m}{7}=m\).

Step 2

Why this answer is correct

The correct answer is A. (m). The product of roots is (7m) and one root is (7). Hence the other root is \(\frac{7m}{7}=m\).

Step 3

Exam Tip

मूलों का गुणनफल (7m) है और एक मूल (7) है। इसलिए दूसरा मूल \(\frac{7m}{7}=m\) है।

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Question 2/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2+ax+54=0\) का एक मूल (6) है, तो दूसरा मूल और (a) कौन-से हैं?

If one root of \(x^2+ax+54=0\) is (6), what are the other root and (a)?

Explanation opens after your attempt
Correct Answer

A. दूसरा मूल (9), (a=-15)other root (9), (a=-15)

Step 1

Concept

The product of roots is (54), so the other root is (9). The sum is (15), and (-a=15), so (a=-15).

Step 2

Why this answer is correct

The correct answer is A. दूसरा मूल (9), (a=-15) / other root (9), (a=-15). The product of roots is (54), so the other root is (9). The sum is (15), and (-a=15), so (a=-15).

Step 3

Exam Tip

मूलों का गुणनफल (54) है, इसलिए दूसरा मूल (9) होगा। योग (15) है और (-a=15), इसलिए (a=-15)।

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Question 3/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि (x-2-(m+6)x+6m=0) का एक मूल (6) है, तो दूसरा मूल क्या है?

If one root of (x-2-(m+6)x+6m=0) is (6), what is the other root?

Explanation opens after your attempt
Correct Answer

A. (m)

Step 1

Concept

The product of roots is (6m) and one root is (6). Hence the other root is \(\frac{6m}{6}=m\).

Step 2

Why this answer is correct

The correct answer is A. (m). The product of roots is (6m) and one root is (6). Hence the other root is \(\frac{6m}{6}=m\).

Step 3

Exam Tip

मूलों का गुणनफल (6m) है और एक मूल (6) है। इसलिए दूसरा मूल \(\frac{6m}{6}=m\) है।

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Question 4/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2+ax+40=0\) का एक मूल (5) है, तो दूसरा मूल और (a) कौन-से हैं?

If one root of \(x^2+ax+40=0\) is (5), what are the other root and (a)?

Explanation opens after your attempt
Correct Answer

A. दूसरा मूल (8), (a=-13)other root (8), (a=-13)

Step 1

Concept

The product of roots is (40), so the other root is (8). The sum is (13), and (-a=13), so (a=-13).

Step 2

Why this answer is correct

The correct answer is A. दूसरा मूल (8), (a=-13) / other root (8), (a=-13). The product of roots is (40), so the other root is (8). The sum is (13), and (-a=13), so (a=-13).

Step 3

Exam Tip

मूलों का गुणनफल (40) है, इसलिए दूसरा मूल (8) होगा। योग (13) है और (-a=13), इसलिए (a=-13)।

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Question 5/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि (x-2-(m+5)x+5m=0) का एक मूल (5) है, तो दूसरा मूल क्या है?

If one root of (x-2-(m+5)x+5m=0) is (5), what is the other root?

Explanation opens after your attempt
Correct Answer

A. (m)

Step 1

Concept

The product of roots is (5m) and one root is (5). Hence the other root is \(\frac{5m}{5}=m\).

Step 2

Why this answer is correct

The correct answer is A. (m). The product of roots is (5m) and one root is (5). Hence the other root is \(\frac{5m}{5}=m\).

Step 3

Exam Tip

मूलों का गुणनफल (5m) है और एक मूल (5) है। इसलिए दूसरा मूल \(\frac{5m}{5}=m\) है।

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Question 6/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि \(x^2+ax+24=0\) का एक मूल (4) है, तो दूसरा मूल और (a) कौन-से हैं?

If one root of \(x^2+ax+24=0\) is (4), what are the other root and (a)?

Explanation opens after your attempt
Correct Answer

A. दूसरा मूल (6), (a=-10)other root (6), (a=-10)

Step 1

Concept

The product of roots is (24), so the other root is (6). The sum is (10), and (-a=10), so (a=-10).

Step 2

Why this answer is correct

The correct answer is A. दूसरा मूल (6), (a=-10) / other root (6), (a=-10). The product of roots is (24), so the other root is (6). The sum is (10), and (-a=10), so (a=-10).

Step 3

Exam Tip

मूलों का गुणनफल (24) है, इसलिए दूसरा मूल (6) होगा। योग (10) है और (-a=10), इसलिए (a=-10)।

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Question 7/10 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि (x-2-(m+4)x+4m=0) का एक मूल (4) है, तो दूसरा मूल क्या है?

If one root of (x-2-(m+4)x+4m=0) is (4), what is the other root?

Explanation opens after your attempt
Correct Answer

A. (m)

Step 1

Concept

The product of roots is (4m) and one root is (4). Hence the other root is \(\frac{4m}{4}=m\).

Step 2

Why this answer is correct

The correct answer is A. (m). The product of roots is (4m) and one root is (4). Hence the other root is \(\frac{4m}{4}=m\).

Step 3

Exam Tip

गुणनफल (4m) है और एक मूल (4) है। इसलिए दूसरा मूल \(\frac{4m}{4}=m\) है।

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Question 8/10 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2+ax+18=0\) का एक मूल (2) है, तो दूसरा मूल और (a) कौन-से हैं?

If one root of \(x^2+ax+18=0\) is (2), what are the other root and (a)?

Explanation opens after your attempt
Correct Answer

A. दूसरा मूल (9), (a=-11)other root (9), (a=-11)

Step 1

Concept

The product of roots is (18), so the other root is (9). The sum is (11), and (-a=11), so (a=-11).

Step 2

Why this answer is correct

The correct answer is A. दूसरा मूल (9), (a=-11) / other root (9), (a=-11). The product of roots is (18), so the other root is (9). The sum is (11), and (-a=11), so (a=-11).

Step 3

Exam Tip

मूलों का गुणनफल (18) है, इसलिए दूसरा मूल (9) होगा। योग (11) है और (-a=11), इसलिए (a=-11)।

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Question 9/10 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि (x-2-(m+2)x+2m=0) का एक मूल (2) है, तो दूसरा मूल क्या है?

If one root of (x-2-(m+2)x+2m=0) is (2), what is the other root?

Explanation opens after your attempt
Correct Answer

A. (m)

Step 1

Concept

The product of roots is (2m) and one root is (2). Hence the other root is \(\frac{2m}{2}=m\).

Step 2

Why this answer is correct

The correct answer is A. (m). The product of roots is (2m) and one root is (2). Hence the other root is \(\frac{2m}{2}=m\).

Step 3

Exam Tip

गुणनफल (2m) है और एक मूल (2) है। इसलिए दूसरा मूल \(\frac{2m}{2}=m\) है।

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Question 10/10 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2+ax+12=0\) का एक मूल (3) है, तो दूसरा मूल और (a) कौन-से हैं?

If one root of \(x^2+ax+12=0\) is (3), what are the other root and (a)?

Explanation opens after your attempt
Correct Answer

A. दूसरा मूल (4), (a=-7)other root (4), (a=-7)

Step 1

Concept

The product of roots is (12), so the other root is (4). The sum is (7), and (-a=7), so (a=-7).

Step 2

Why this answer is correct

The correct answer is A. दूसरा मूल (4), (a=-7) / other root (4), (a=-7). The product of roots is (12), so the other root is (4). The sum is (7), and (-a=7), so (a=-7).

Step 3

Exam Tip

मूलों का गुणनफल (12) है, इसलिए दूसरा मूल (4) होगा। योग (7) है और (-a=7), इसलिए (a=-7)।

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